NSW Y8 Maths Area and Perimeter Metric Units for Measurement of Area

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Metric Units for Measurement of Area Theory

\begin{multicols}{2} \(\begin{aligned} 1 \text{~cm}^2 & =1 \text{~cm} \times 1 \text{~cm} \\ & =10 \text{~mm} \times 10 \text{~mm} \\ & =100 \text{~mm}^2  \end{aligned}\)\\[3pt] \(\begin{aligned} 1 \text{~m}^2 & =1 \text{~m} \times 1 \text{~m} \\ & =100 \text{~cm} \times 100 \text{~cm} \\ & =10000 \text{~cm}^2  \end{aligned}\)  \columnbreak \(\begin{aligned} 1 \text { hectare }(\text{ha}) & =10000 \text{~m}^2  \end{aligned}\)\\[3pt] \(\begin{aligned} 1 \text{~km}^2 & =1 \text{~km} \times 1 \text{~km} \\ & =1000 \text{~m} \times 1000 \text{~m} \\ & =1000000 \text{~m}^2 \\ & =100 \times 10000 \text{~m}^2 \\ & =100 \text{ha} .\end{aligned}\) \end{multicols}  \hfill\linebreak \begin{multicols}{2}  \textbf{Example 1}\\ Convert \(420000 \text{~m}^2\) to hectares\\  \textbf{Example 1 solution}\\ \(\begin{aligned} 420000 \text{~m}^2 & =42 \times 10000 \\ & =42 \text{ha} \end{aligned}\)  \columnbreak \textbf{Example 2}\\ Convert \(540 \text{~cm}^2\) to \(\text{m}^2\)\\  \textbf{Example 2 solution}\\ \(\begin{aligned} 1 \text{~m}^2 & =10000 \text{~cm}^2 \\ \therefore 1 \text{~cm}^2 & =\frac{1}{10000} \text{~m}^2 \\ 540 \text{~cm}^2 & =\frac{540}{10000} \text{~m}^2 \\ & =0.054 \text{~m}^2\end{aligned}\) \end{multicols}

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