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Year 8 Maths Area and Perimeter

Area of Circles

20 practice questions 1 video lesson Theory + worked examples

The area of a circle depends only on its radius: \(A = \pi r^2\). This NSW Year 8 maths subtopic (NESA outcome MA4‑ARE‑C‑01) shows where the formula comes from and uses it with a given radius or diameter, giving answers in terms of \(\pi\) or rounded with the \(\pi\) key.

You will find the area of a ring such as a washer, the region left when a circle is cut from a rectangle, and a radius or diameter from a given area or circumference. You will also see why doubling the radius makes the area four times as large, decide whether one large pizza beats two smaller ones, and find how much of a lawn a sprinkler misses. It is part of Year 8 Area and Perimeter.

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Theory

The area of a circle is \(A = \pi r^2\): square the radius first, then multiply by \(\pi\). A circle with diameter \(12\) cm has \(r = 6\) cm, so \(A = 36\pi \approx 113.10~\text{cm}^2\). This Year 8 maths page shows how.

\(A = \pi r^2\), where \(r\) is the radius. Work out \(r^2 = r \times r\) first, then multiply by \(\pi\) (\(\pi \approx 3.14159\)).

Where it comes from. A circle fits inside a square of side \(2r\), area \(4r^2\), and fills a bit more than three quarters of it: about \(3.14r^2\). Or cut the circle into many equal sectors and lay them head to tail: they make a shape close to a parallelogram with base half the circumference, \(\pi r\), and height \(r\), so \(A = \pi r \times r = \pi r^2\).

Given the diameter? Halve it first: \(r = \dfrac{d}{2}\).

Exact or rounded. An exact area keeps \(\pi\); otherwise use the \(\pi\) key and round as asked. Area is in square units.

A ring (annulus) is the big circle take away the small circle: \(A = \pi R^2 - \pi r^2\). When a circle is cut out of another shape, subtract; when it is added on, add.

Working backwards: \(r^2 = A \div \pi\), so \(r = \sqrt{A \div \pi}\). Scaling: a radius \(3\) times as long gives an area \(3^2 = 9\) times as large.

Circle inside a square A circle of radius r inside a dashed square of side 2r. The square has area 4r squared and the circle fills a bit more than three quarters of it. r2rsquare = 4r², circle = πr²
The circle fills a bit more than three quarters of the square of side \(2r\), so its area is a bit more than \(3r^2\): \(A = \pi r^2\).
A ring Two circles with the same centre, radii R and r. The shaded ring between them has area pi R squared minus pi r squared. Rrring = πR² − πr²
A ring is the big circle take away the small one.

Area of a circle:

\[ A = \pi r^2 \]
A = r squared
\[ r = \sqrt{\dfrac{A}{\pi}} \]
r = square root of A /
r² is not 2r. Multiply the radius by itself; and \(\pi r^2\) is not \((\pi r)^2\).
Do not round part way. From an area of \(7~\text{m}^2\), \(r = 1.4927\ldots\); using \(1.49\) for the circumference gives \(9.36\) m instead of \(9.38\) m.

How to find the area of a circle

  1. Find the radius (halve a diameter).
  2. Square it, then multiply by \(\pi\).
  3. Give an exact answer, or round at the end, in square units.
Example 1 — Exact area
Find the exact area of a circle with radius \(11\) cm.
Solution
\(A\)\(=\)\(\pi \times 11^2 = 121\pi\)
121 cm

\(121\pi~\text{cm}^2\)

Example 2 — From a diameter
Find the area of a circle with a diameter of \(12\) cm, to \(2\) decimal places.
Solution
\(r\)\(=\)\(12 \div 2 = 6\)
\(A\)\(=\)\(\pi \times 6^2 = 36\pi\)
\(\)\(=\)\(113.097\ldots\)
113.10 cm

\(113.10~\text{cm}^2\)

Example 3 — Exact, then rounded
A circle has a radius of \(8\) cm. Find its area
(i) in terms of \(\pi\)
(ii) to \(2\) decimal places
Solution
\(A\)\(=\)\(\pi \times 8^2 = 64\pi\)
\(\)\(=\)\(201.06\ldots\)
64 cm 201.06 cm

(i) \(64\pi~\text{cm}^2\)
(ii) \(201.06~\text{cm}^2\)

Example 4 — Halve, then subtract
A round trapdoor \(2.4\) m across is cut in a deck \(3\) m by \(2.5\) m. Find
(i) the area of the trapdoor
(ii) the area of deck left
each to \(2\) decimal places.
Solution
\(A_1\)\(=\)\(\pi \times 1.2^2 = 4.523\ldots\)
\(A\)\(=\)\(7.5 - 4.523\ldots = 2.976\ldots\)
4.52 m 2.98 m

(i) \(4.52~\text{m}^2\)
(ii) \(2.98~\text{m}^2\)

Example 5 — Paving around a pond
A circular pond has a radius of \(1.5\) m. Paving \(0.5\) m wide goes all the way around it. Find the area of the paving, to \(2\) decimal places.
Solution
\(R\)\(=\)\(1.5 + 0.5 = 2\)
\(A\)\(=\)\(\pi \times 2^2 - \pi \times 1.5^2\)
\(\)\(=\)\(1.75\pi = 5.497\ldots\)
5.50 m

\(5.50~\text{m}^2\)

Example 6 — Back from the area
A round trampoline mat has an area of \(7~\text{m}^2\). Find
(i) its radius
(ii) the length of padding around its edge
each to \(2\) decimal places.
Solution
\(r^2\)\(=\)\(7 \div \pi = 2.228\ldots\)
\(r\)\(=\)\(1.4927\ldots\)
\(C\)\(=\)\(2\pi \times 1.4927\ldots = 9.378\ldots\)
1.49 m 9.38 m

(i) \(1.49\) m
(ii) \(9.38\) m, using the unrounded radius.

Common pitfalls

Using the diameter as the radius. Halve it first, or the area is four times too big.
Doubling instead of squaring. \(r^2 = r \times r\), not \(2r\).
Wrong units. Area is in square units, such as \(\text{cm}^2\).
Changing units after squaring. Change the lengths to the needed unit before you square.

Frequently asked questions

What is the formula for the area of a circle?

\(A = \pi r^2\).

How do I find the area from the diameter?

Halve the diameter to get the radius, then use \(A = \pi r^2\).

How do I find the radius from the area?

Divide the area by \(\pi\), then take the square root.

How do I find the area of a ring?

Big circle minus small circle: \(\pi R^2 - \pi r^2\).

If the radius is halved, what happens to the area?

It becomes \(\dfrac{1}{4}\) as large.