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Year 8 Maths Investigating Data

Shape of Data, Outliers and Best Measure of Centre

20 practice questions 0 video lessons Theory + worked examples

Before calculating anything, look at the shape of the data. In NSW Year 8 maths (NESA outcome MA4‑DAT‑C‑02) a set is described as symmetrical, positively skewed (tail to the right) or negatively skewed (tail to the left), together with its peaks, clusters, gaps and outliers.

You will measure how far an outlier pulls the mean while the median barely moves, then choose the best summary: the mean for marks that sit close together, the median for skewed data such as house prices, and the mode for the most common size. Examples include a 95 cm mulloway among small fish, a $2.4 million waterfront home and a batter’s innings of 142. It is part of Year 8 Investigating Data.

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Theory

Look at the shape before calculating. An outlier, a value far from the rest, drags the mean towards itself but hardly moves the median. For stays of \(2, 2, 3, 3, 4, 4, 5, 5, 6\) and \(46\) nights, the mean is \(8\) but the median is \(4\). This Year 8 maths page shows how to choose.

Shape. Data is symmetrical when the two halves are close to mirror images, positively skewed when the tail stretches to the right (high values), and negatively skewed when the tail stretches to the left (low values). The tail names the skew.

Peaks. No mode is uniform, one mode is unimodal, two modes is bimodal. Also describe clusters (values bunched together), gaps (stretches with no values) and outliers, with a reason in context.

What an outlier does. The mean is pulled towards it, because every value is added in. The median barely moves, because it depends only on the middle values. The mode usually does not change. The range grows a lot.

Skew and order. Positively skewed usually gives mean \(>\) median; negatively skewed gives mean \(<\) median; symmetrical gives mean \(\approx\) median. It is a guide to check, not a law.

Working with a total: total \(=\) mean \(\times\) number of values. To remove a value, subtract it from the total and divide by one fewer.

Comparing two sets: compare their centres, their spreads and their shapes, in context.

Symmetrical A histogram of 24 values from 1 to 7 rising to a peak at 4 and falling again in the same way: the mean and the median are both 4. 0 2 4 6 8 10 1 2 3 4 5 6 7
Symmetrical: the halves match, so the mean and the median are both \(4\).
Positively skewed A histogram of 24 values from 1 to 7 with most values low and a tail to the right. A dashed red line marks the mean, about 2.7; a dotted green line marks the median, 2. 0 2 4 6 8 10 1 2 3 4 5 6 7 meanmedian
A long tail on the right pulls the mean (dashed, about \(2.7\)) above the median (dotted, \(2\)).
Negatively skewed A histogram of 24 values from 1 to 7 with most values high and a tail to the left. A dashed red line marks the mean, about 5.3; a dotted green line marks the median, 6. 0 2 4 6 8 10 1 2 3 4 5 6 7 meanmedian
A long tail on the left pulls the mean (dashed, about \(5.3\)) below the median (dotted, \(6\)).

Which measure of centre?

The dataBest measureWhy
close together, no outliersmeanit uses every value
has an outlier, or is strongly skewedmedianan outlier barely moves it
sizes or categories; the most common is wantedmodethe mean may not be a real size
An outlier is not always a mistake. Check it, give a reason for it, and say so clearly if you leave it out of a calculation.
The mean need not be a value anyone has. A mean of \(6.5\) goals is fine; check where it lands against the data before quoting it.

Describing and summarising data

  1. Describe the shape: symmetrical or skewed (name the tail), the number of peaks, clusters, gaps and outliers.
  2. Calculate the mean and the median (with and without any outlier).
  3. Choose: mean for close data, median with an outlier or strong skew, mode for the most common size or category.
  4. Explain the choice in context.
Example 1 — Describing the shape
The dot plot shows the lorikeets counted in the school grounds each morning for \(19\) days.
(i) Describe the shape.
(ii) Unimodal or bimodal?
(iii) Name the gap and the outlier.
Lorikeets counted each morning A dot plot of 19 mornings: 0 lorikeets 5 dots, 1 six dots, 2 four dots, 3 two dots, 4 one dot, none at 5 or 6, and one dot at 7. 012345678 Lorikeets counted
Solution

The stacks hold \(5, 6, 4, 2, 1\) and \(1\) dots.

(i) Positively skewed: the dots bunch at the left and the tail is on the right.
(ii) Unimodal (one tallest stack, at \(1\)).
(iii) A gap at \(5\) and \(6\); the lone \(7\) is an outlier, perhaps a flock passing through.

Example 2 — Mean against median
Ten bookings at a caravan park lasted \(2, 2, 3, 3, 4, 4, 5, 5, 6\) and \(46\) nights. Find
(i) the mean
(ii) the median
(iii) the mean without the outlier
(iv) the better measure for a typical booking.
Solution
\(\text{Total}\)\(=\)\(80\)
\(\text{Mean}\)\(=\)\(\dfrac{80}{10} = 8\)
\(\text{Median}\)\(=\)\(\dfrac{4 + 4}{2} = 4\)
\(\dfrac{80 - 46}{9}\)\(=\)\(\dfrac{34}{9} \approx 3.8\)
843.8

(i) \(8\) nights
(ii) \(4\) nights
(iii) about \(3.8\) nights
(iv) The median: removing the outlier drops the mean from \(8\) to \(3.8\), but the median does not move.

Example 3 — One more value
Eight jars of honey have a mean mass of \(460\) g. A ninth jar of \(640\) g, heavier than all the others, is added. Find
(i) the total of the first eight
(ii) the mean of all nine
(iii) the rise in the mean.
Solution
\(460 \times 8\)\(=\)\(3680\)
\(\dfrac{3680 + 640}{9}\)\(=\)\(\dfrac{4320}{9} = 480\)
\(480 - 460\)\(=\)\(20\)
3680 g 480 g 20 g

(i) \(3680\) g
(ii) \(480\) g
(iii) \(20\) g. The median hardly changes: the heaviest jar moves the middle of the ordered list along only half a place.

Example 4 — Choosing the measure
Which measure should be quoted, and why?
(i) \(22\) measurements of the same steel rod, all between \(1.82\) m and \(1.86\) m.
(ii) \(15\) second-hand bikes: one at \(\$4200\), the rest between \(\$80\) and \(\$350\).
(iii) A shop choosing which shoe size to order most.
Solution

(i) Mean: the readings are close with no outlier, and the mean uses all \(22\).
(ii) Median: the \(\$4200\) bike would drag the mean above almost every price.
(iii) Mode: a mean shoe size such as \(8.3\) is not a size the shop can order.

Common pitfalls

Naming the skew by the peak. Positively skewed data has most values on the left and its thin tail on the right.
Quoting the mean of skewed data as typical. When one value is far away, most values can sit below (or above) the mean.
Deleting outliers without a reason. Keep an outlier unless there is a good reason, and say when you leave it out.
Forgetting to divide by one fewer. After removing a value from \(10\), divide the new total by \(9\).

Frequently asked questions

What is an outlier?

A value that is far away from the rest of the data.

How does an outlier affect the mean and the median?

It pulls the mean towards itself, sometimes a long way, but changes the median very little.

What does positively skewed mean?

Most of the data is at the low end and the tail stretches out to the high values.

When should I use the median instead of the mean?

When the data has an outlier or is strongly skewed, such as house prices or wages.

When is the mode the best measure?

When you want the most common size or category, such as the shoe size a shop sells most.