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Year 8 Maths Investigating Data

Organising and Displaying Data

20 practice questions 2 video lessons Theory + worked examples

Organising and Displaying Data in NSW Year 8 maths (NESA outcome MA4‑DAT‑C‑01) starts with a frequency table, using tallies and class intervals of equal width that do not overlap, then turns the table into a graph.

You will draw and read sector graphs, with each angle found from \(\frac{\text{frequency}}{\text{total}} \times 360^\circ\), divided bar graphs, dot plots and stem-and-leaf plots, find a modal class and choose the best graph for a set of data. You will also spot a misleading picture graph and give every display a title, labels, a scale and a source. Rainfall, travel to school and household water use are typical examples. It is part of Year 8 Investigating Data.

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Theory

Organise raw data in a frequency table first, then choose a display that suits it. In a sector graph, each angle is \(\dfrac{\text{frequency}}{\text{total}} \times 360^\circ\): \(10\) white jelly beans out of \(40\) take \(\dfrac{10}{40} \times 360^\circ = 90^\circ\). This Year 8 maths page shows how.

A frequency table lists each value or category once, with a tally and a frequency. The frequencies add to the number of pieces of data, which is a useful check.

Class intervals. When there are many different numbers, group them into classes of equal width, such as \(0\)–\(9\), \(10\)–\(19\), \(20\)–\(29\). Classes must not overlap, so every value lands in exactly one class. For measured data, \(2\)–\({<}3\) means from \(2\) up to but not including \(3\). The modal class has the largest frequency.

Sector graph (pie chart): sector angle \(= \dfrac{\text{frequency}}{\text{total}} \times 360^\circ\), and the angles add to \(360^\circ\). For percentages, angle \(=\) percentage \(\div 100 \times 360^\circ\). Read it backwards to get a count or a percentage from an angle.

Divided bar graph. One bar stands for the whole. A part’s length is \(\dfrac{\text{frequency}}{\text{total}} \times\) the bar length (or angle \(\div 360^\circ \times\) bar length).

Column graph and histogram. A column graph shows categories, with gaps between the columns. A histogram shows grouped numbers, and its columns touch because the classes join.

Dot plot and stem-and-leaf plot. A dot plot shows one dot per value; the total of the data is each value times its number of dots, added. A stem-and-leaf plot splits each value into a stem and a leaf, with the leaves in order and a key such as \(4 \mid 3 = 4.3\) kg.

Label it. Every display needs a title, axis labels with units, a scale in equal steps, and a key for a stem-and-leaf plot or a picture graph.

Canteen drinks A column graph of four drinks with gaps between the columns: water 9, juice 6, milk 4, soft drink 3 students. 0 2 4 6 8 10 Water Juice Milk Soft Drink Students
A column graph of categories, drawn with gaps between the columns.
Bag masses A histogram of school bag masses in 1 kg classes from 1 to 6 kg, with touching columns: 3, 7, 9, 5 and 2 bags. 0 2 4 6 8 10 1 2 3 4 5 6 Mass (kg) Bags
A histogram of grouped masses in \(1\) kg classes: the columns touch because \(1\)–\({<}2\) runs straight into \(2\)–\({<}3\).
Pets per student A dot plot: 0 pets 3 dots, 1 pet 5 dots, 2 pets 4 dots, 3 pets 2 dots. 0123 Number of pets
A dot plot: \(14\) students, and \(0 \times 3 + 1 \times 5 + 2 \times 4 + 3 \times 2 = 19\) pets altogether.

Which display?

DisplayBest for
Column graphcategories (with gaps)
Sector graphparts of a whole
Divided bar graphparts of a whole
Dot plotsmall sets of numbers
Stem-and-leaf plotnumbers, keeping every value
Histogramgrouped numbers (no gaps)
Line graphchange over time
Classes must not overlap. \(5\)–\(10\) and \(10\)–\(15\) both hold \(10\). Use \(5\)–\(9\) and \(10\)–\(14\).
Pictures scaled two ways mislead. Tripling the width and the height of a symbol makes it cover nine times the area, so three times the sales looks nine times as big. Always read the scale.

Organising data

  1. Tally each value or category in a frequency table (group into classes if needed).
  2. Count the tallies and check the frequencies add to the total.

Sector graphs and divided bars

  1. Find each fraction: frequency \(\div\) total.
  2. Multiply by \(360^\circ\) for an angle, or by the bar length for a bar.
  3. Check the angles add to \(360^\circ\) (or the lengths to the bar).
  4. Label every part and give the graph a title.
Example 1 — A divided bar graph
The colours of the jelly beans in a jar were counted: White \(10\), Black \(6\), Green \(8\), Blue \(12\), Red \(4\). Display the data as a divided bar graph. Which colour occurs most often?
Solution

There are \(10 + 6 + 8 + 12 + 4 = 40\) jelly beans. As decimals: white \(0.25\), black \(0.15\), green \(0.2\), blue \(0.3\) and red \(0.1\) of the bar.

Jelly bean colours as a divided bar A divided bar graph of 40 jelly beans: White 25%, Black 15%, Green 20%, Blue 30%, Red 10%. White Black Green Blue Red 0%50%100%

Blue occurs most often (\(30\%\) of the bar).

Example 2 — A sector graph
Display the jelly bean data from Example 1 as a sector graph. Which colour occurs least?
Solution
Jelly bean colours as a sector graph A sector graph of 40 jelly beans: White 90 degrees, Black 54, Green 72, Blue 108 and Red 36. White90° Black54° Green72° Blue108° Red36°
\(\text{White}\)\(=\)\(0.25 \times 360^\circ = 90^\circ\)
\(\text{Black}\)\(=\)\(0.15 \times 360^\circ = 54^\circ\)
\(\text{Green}\)\(=\)\(0.20 \times 360^\circ = 72^\circ\)
\(\text{Blue}\)\(=\)\(0.30 \times 360^\circ = 108^\circ\)
\(\text{Red}\)\(=\)\(0.10 \times 360^\circ = 36^\circ\)
90+54+72+108+36=360

The angles add to \(360^\circ\). Red occurs least.

Example 3 — A frequency table
\(16\) students named what they did most in the holidays: beach, home, beach, camping, family, home, beach, home, camping, beach, family, home, beach, camping, home, beach. Make a frequency table. Which answer is the most common?
Solution

Tally each answer in turn, then count the tallies.

\(\text{Beach}\)\(=\)\(6\)
\(\text{Home}\)\(=\)\(5\)
\(\text{Camping}\)\(=\)\(3\)
\(\text{Family}\)\(=\)\(2\)
\(6 + 5 + 3 + 2\)\(=\)\(16\)
6+5+3+2=16

The frequencies add to \(16\). The most common answer is beach.

Example 4 — Angles and bar lengths
\(40\) students chose one elective: music \(13\), drama \(11\), coding \(9\), photography \(7\).
(i) Find the angle of the music sector.
(ii) On a divided bar graph \(12\) cm long, how long is the coding part?
Solution
\(\dfrac{13}{40} \times 360^\circ\)\(=\)\(13 \times 9^\circ = 117^\circ\)
\(\dfrac{9}{40} \times 12\)\(=\)\(9 \times 0.3 = 2.7\)
1172.7 cm

(i) \(117^\circ\). All four angles: \(117 + 99 + 81 + 63 = 360\).
(ii) \(2.7\) cm

Example 5 — Grouping in classes
\(12\) students said how many messages they sent yesterday: \(4\), \(13\), \(23\), \(7\), \(15\), \(31\), \(17\), \(9\), \(26\), \(14\), \(2\), \(19\). Group them in the classes \(0\)–\(9\), \(10\)–\(19\), \(20\)–\(29\), \(30\)–\(39\).
(i) Name the modal class.
(ii) How many sent \(20\) or more?
Solution
\(0\text{ to }9\)\(\)\(4,\ 7,\ 9,\ 2 \to 4\)
\(10\text{ to }19\)\(\)\(13,\ 15,\ 17,\ 14,\ 19 \to 5\)
\(20\text{ to }29\)\(\)\(23,\ 26 \to 2\)
\(30\text{ to }39\)\(\)\(31 \to 1\)
4+5+2+1=12

The frequencies add to \(12\).
(i) \(10\)–\(19\)
(ii) \(2 + 1 = 3\) students

Example 6 — Reading a sector graph
A surf club has four age groups. The sector angles are U13 \(108^\circ\), U15 \(72^\circ\), Open \(96^\circ\), and U17 is not given. \(27\) members are U13.
(i) Find the U17 angle.
(ii) How many members does the club have?
(iii) What percentage are U15?
Solution
\(108 + 72 + 96\)\(=\)\(276\)
\(360 - 276\)\(=\)\(84\)
\(108 \div 27\)\(=\)\(4^\circ \text{ per member}\)
\(360 \div 4\)\(=\)\(90\)
\(\dfrac{72}{360} \times 100\%\)\(=\)\(20\%\)
8490 members 20

(i) \(84^\circ\)
(ii) \(90\) members
(iii) \(20\%\)

Example 7 — A stem-and-leaf plot
Eight students’ scores out of \(50\) were \(23\), \(41\), \(35\), \(28\), \(39\), \(44\), \(30\), \(26\). Draw an ordered stem-and-leaf plot.
Solution

The tens digit is the stem and the units digit is the leaf. Put the leaves of each stem in order.

StemLeaf
23 6 8
30 5 9
41 4

Key: \(2 \mid 3 = 23\). There are \(8\) leaves, one for each score.

Common pitfalls

Forgetting the total. Sector angles need frequency \(\div\) total, so add the frequencies first.
Gaps in a histogram. The classes of a histogram join, so the columns touch; a column graph of categories has gaps.
Comparing graphs with different scales. Read each graph against its own scale before comparing the heights of columns.
No key on a stem-and-leaf plot. Without a key, \(4 \mid 3\) could mean \(43\) or \(4.3\).

Frequently asked questions

How do you work out the angle for a sector graph?

Divide the frequency by the total and multiply by \(360^\circ\): \(15\) out of \(60\) is \(\dfrac{15}{60} \times 360^\circ = 90^\circ\).

What is the difference between a column graph and a histogram?

A column graph shows categories and has gaps; a histogram shows grouped numerical data and its columns touch.

What is a class interval?

A group of values of equal width, such as 10 to 19, used when there are many different numbers.

What is the modal class?

The class interval with the largest frequency.

What should every graph have?

A title, labelled axes with units, an even scale, and a key where one is needed.