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Year 8 Maths Algebra

Adding and Subtracting Terms

20 practice questions 2 video lessons Theory + worked examples

Like terms have exactly the same pronumeral part, such as \(5xy\) and \(-2yx\), and only like terms can be added or subtracted. In NSW Year 8 maths you simplify by combining the coefficients and keeping the pronumeral part as it is (NESA outcome MA4‑ALG‑C‑01).

You will collect like terms in expressions with negatives, squared terms and several pronumerals, such as \(7x^2 + 5x - 6x^2 - 7x\), and leave unlike terms alone. You will use the commutative and associative properties to move each term with its sign, and check answers by substituting a friendly number. Adding two clothing orders for a netball club works in exactly the same way. It is part of Year 8 Algebra.

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Theory

Only like terms can be added or subtracted. Like terms have exactly the same pronumeral part: \(3x\) and \(2x\), \(4y^2\) and \(y^2\), \(2xy\) and \(4yx\). Add or subtract the coefficients and keep the pronumeral part. This Year 8 maths page shows how to collect like terms.

Every term has a coefficient (the number in front) and a pronumeral part (the pronumerals with their indices). In \(-7gh\) the coefficient is \(-7\) and the pronumeral part is \(gh\). A term with no number in front has coefficient \(1\): \(v = 1v\) and \(-v = -1v\).

Like terms have the same pronumeral part, pronumeral for pronumeral and index for index. \(3x\) and \(2x\), \(4y^2\) and \(y^2\), and \(2xy\) and \(4yx\) are like terms. \(2x\) and \(3y\), and \(2xy^2\) and \(x^2y\), are not.

The order of multiplying does not matter (the commutative property), so \(yx\) is the same as \(xy\). Terms can also be swapped and regrouped when adding (the commutative and associative properties), which is why like terms can be moved next to each other.

To simplify: group the like terms, moving each term with the sign in front of it; add or subtract the coefficients and keep the pronumeral part, \(9t - 4t = 5t\); leave any term with no like term as it is. Answers are usually written with the highest index first.

Check by substituting a friendly number for each pronumeral: the expression and the answer must give the same value.

Grouping like terms The expression 8c + 3d - 2c + 7 - 5d is rearranged so the c terms, the d terms and the constant sit together. It simplifies to 6c - 2d + 7. 8c+3d−2c+7−5deach term moves with the sign in front of it 8c−2c+3d−5d+7group: 8c − 2c = 6c, 3d − 5d = −2d, 7 stays
\(8c + 3d - 2c + 7 - 5d = 6c - 2d + 7\). The constant \(7\) has no like term, so it stays.

Coefficient and pronumeral part:

TermCoefficientPronumeral part
\(6k\)\(6\)\(k\)
\(-k\)\(-1\)\(k\)
\(6k^2\)\(6\)\(k^2\)
\(tk\)\(1\)\(kt\)
\(6\)\(6\)none (a constant)
Unlike terms stay apart. \(4p + 3q\) is already simplest; it is not \(7pq\).
A square is a different kind of term. \(5d^2 + 2d\) cannot be simplified.
The sign belongs to the term after it. In \(8h - 5g + 2h\) the middle term is \(-5g\): the answer is \(10h - 5g\).

How to collect like terms

  1. Find the like terms (same pronumeral part; \(xy = yx\)).
  2. Group them, each with the sign in front of it.
  3. Add or subtract the coefficients; keep the pronumeral part.
  4. Check by substituting numbers.
Example 1 — Squares and plain terms
Simplify \(2x^2 + 3x + x^2 + 4x\).
Solution

Group the like terms: \(2x^2 + x^2 + 3x + 4x\).

\(2x^2 + x^2\)\(=\)\(3x^2\)
\(3x + 4x\)\(=\)\(7x\)
2 x + x +3 x +4 x =3 x +7 x

\(3x^2 + 7x\)

Example 2 — Swapped pronumerals
Simplify \(2xy + 4yx + x + y\).
Solution

Write \(4yx\) as \(4xy\): \(2xy + 4xy + x + y\).

\(2xy + 4xy\)\(=\)\(6xy\)
2 xy +4 xy + x + y =6 xy + x + y

\(6xy + x + y\) (\(yx\) is the same as \(xy\))

Example 3 — One group of like terms
Simplify
(i) \(7t + t - 3t\)
(ii) \(-5w - 4w\)
Solution
\(7t + t - 3t\)\(=\)\((7 + 1 - 3)t = 5t\)
\(-5w - 4w\)\(=\)\((-5 - 4)w = -9w\)
5 t −9 w

(i) \(5t\). Check with \(t = 4\): \(28 + 4 - 12 = 20\) and \(5 \times 4 = 20\).
(ii) \(-9w\)

Example 4 — Two groups and constants
Simplify \(9g - 7 - 4g + 2h + 5\).
Solution
\(\)\(=\)\(9g - 4g + 2h - 7 + 5\)
\(\)\(=\)\(5g + 2h - 2\)
5 g +2 h −2

\(5g + 2h - 2\). Check with \(g = 3\), \(h = 4\): \(27 - 7 - 12 + 8 + 5 = 21\) and \(15 + 8 - 2 = 21\).

Example 5 — Squares and swapped pronumerals
Simplify \(4k^2 + 3vk - k^2 - 5kv\).
Solution
\(4k^2 - k^2\)\(=\)\(3k^2\)
\(3kv - 5kv\)\(=\)\(-2kv\)
3 k −2 kv

\(3k^2 - 2kv\). Check with \(k = 2\), \(v = 5\): \(16 + 30 - 4 - 50 = -8\) and \(12 - 20 = -8\).

Example 6 — Three groups at once
Simplify \(6n^2 - 5n + 2 - n^2 + 8n - 9\).
Solution
\(6n^2 - n^2\)\(=\)\(5n^2\)
\(-5n + 8n\)\(=\)\(3n\)
\(2 - 9\)\(=\)\(-7\)
5 n +3 n −7

\(5n^2 + 3n - 7\). Check with \(n = 2\): \(24 - 10 + 2 - 4 + 16 - 9 = 19\) and \(20 + 6 - 7 = 19\).

Common pitfalls

Adding unlike terms. \(2x + 3y\) is not \(5xy\).
Joining a square with a plain term. \(x^2 + x\) is not \(2x^2\) or \(x^3\).
Losing a minus sign. Move each term together with the sign in front of it.
Forgetting the hidden 1. \(5a - a = 4a\), not \(5\).

Frequently asked questions

What are like terms?

Terms with exactly the same pronumeral part, such as \(3ab\) and \(-5ba\).

How do you add like terms?

Add the coefficients and keep the pronumeral part: \(4m + 7m = 11m\).

Are xy and yx like terms?

Yes. The order of multiplying does not matter, so \(xy = yx\).

Are x squared and x like terms?

No. \(x^2\) and \(x\) have different indices, so \(3x^2 + 2x\) stays as it is.

How can I check my answer?

Substitute small numbers into the question and the answer; they must give the same value.