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Year 8 Maths Algebra

Multiplying Terms

20 practice questions 1 video lesson Theory + worked examples

To multiply algebraic terms in NSW Year 8 maths, multiply the coefficients and then the pronumerals (NESA outcome MA4‑ALG‑C‑01). A pronumeral multiplied by itself is written as a power, so \(3y \times 6y = 18y^2\), and the sign comes from counting the negative factors.

You will multiply two or three terms with negative coefficients and write the pronumerals in alphabetical order, as in \(2x^2 \times (-y) \times 4y = -8x^2y^2\). You will also simplify a product and then collect it with a like term. The area of a rectangular garden bed and the volume of a storage box shaped like a rectangular prism are both products of terms. It is part of Year 8 Algebra.

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Theory

To multiply terms, multiply the numbers first, then the pronumerals. A pronumeral multiplied by itself is written as a power: \(2x \times 3x = 2 \times 3 \times x \times x = 6x^2\). This Year 8 maths page shows how, with negative signs and several factors.

Multiplying can be done in any order (commutative) and any grouping (associative), so a product can be rearranged into numbers together and pronumerals together.

Three steps. Multiply the coefficients, watching the signs. Write the pronumerals in alphabetical order. A pronumeral that appears more than once becomes a power: \(d \times d = d^2\), \(d^2 \times d = d^3\).

A term with no number in front has coefficient \(1\), so \(-y\) means \(-1 \times y\).

Signs. Count the negative factors: an even number gives a positive answer, an odd number a negative answer.

Writing \(\times\) between every factor makes counting easy: \(2ab \times 5bc = 2 \times a \times b \times 5 \times b \times c = 10ab^2c\).

Area and volume. Area of a rectangle \(=\) length \(\times\) width; volume of a box \(=\) length \(\times\) width \(\times\) height. A crate \(3a\) m by \(2b\) m by \(4a\) m has volume \(24a^2b\) m\(^3\).

A 4t by 3t rectangle A rectangle 4t long and 3t wide divided into 12 small squares, each t by t with area t squared. So 4t times 3t is 12t squared. t²4t3t
The rectangle is \(4t\) by \(3t\), so it holds \(12\) small squares, each \(t\) by \(t\) with area \(t^2\). So \(4t \times 3t = 12t^2\).

Numbers first, then pronumerals:

ProductNumbersAnswer
\(5a \times 4b\)\(20\)\(20ab\)
\(5a \times 4a\)\(20\)\(20a^2\)
\(-5a \times 4ab\)\(-20\)\(-20a^2b\)
\(-a \times (-4b)\)\(4\)\(4ab\)
Multiplying is not adding. \(5r \times 2r = 10r^2\), but \(5r + 2r = 7r\).
Count the negative signs. \((-2u) \times (-3v) \times (-2) = -12uv\).

How to multiply terms

  1. Multiply the coefficients and decide the sign.
  2. Write the pronumerals in alphabetical order.
  3. Count each repeated pronumeral and write it as a power.
Example 1 — Three different pronumerals
Simplify \(4a \times 2b \times c\).
Solution
\(4a \times 2b \times c\)\(=\)\(4 \times 2 \times a \times b \times c\)
\(\)\(=\)\(8abc\)
8 abc

\(8abc\)

Example 2 — A repeated pronumeral
Simplify \(6p \times 3q \times 2p\).
Solution

\(6p \times 3q \times 2p = 6 \times 3 \times 2 \times p \times p \times q\)

\(6 \times 3 \times 2\)\(=\)\(36\)
\(p \times p \times q\)\(=\)\(p^2q\)
36 p q

\(36p^2q\)

Example 3 — Numbers then pronumerals
Simplify
(i) \(5u \times 4v\)
(ii) \(6e \times 4e\)
Solution
\(5u \times 4v\)\(=\)\(20uv\)
\(6e \times 4e\)\(=\)\(24e^2\)
20 uv 24 e

(i) \(20uv\)
(ii) \(24e^2\). Check with \(e = 3\): \(18 \times 12 = 216\) and \(24 \times 9 = 216\).

Example 4 — Negative coefficients
Simplify
(i) \(-4h \times 6k\)
(ii) \((-5w) \times (-3w)\)
Solution
\(-4h \times 6k\)\(=\)\(-24hk\)
\((-5w) \times (-3w)\)\(=\)\(15w^2\)
−24 hk 15 w

(i) One negative: \(-24hk\)
(ii) Two negatives: \(15w^2\). Check with \(w = 2\): \(-10 \times (-6) = 60 = 15 \times 4\).

Example 5 — Three factors
Simplify \(2ts \times 5r \times (-3t)\).
Solution
\(2 \times 5 \times (-3)\)\(=\)\(-30\)
\(r \times s \times t \times t\)\(=\)\(rst^2\)
−30 rst

\(-30rst^2\). Check with \(r = 2\), \(s = 3\), \(t = 4\): \(24 \times 10 \times (-12) = -2880\) and \(-30 \times 2 \times 3 \times 16 = -2880\).

Example 6 — Area of a courtyard
A courtyard is \(5x\) m long and \(2xy\) m wide. A sandpit \(2x\) m by \(xy\) m sits in one corner. Find the paved area left over.
Solution
\(5x \times 2xy\)\(=\)\(10x^2y\)
\(2x \times xy\)\(=\)\(2x^2y\)
\(10x^2y - 2x^2y\)\(=\)\(8x^2y\)
8 x y m

\(8x^2y\) m\(^2\). Check with \(x = 2\), \(y = 3\): \(120 - 24 = 96\) and \(8 \times 4 \times 3 = 96\).

Common pitfalls

Adding instead of multiplying. \(3a \times 2a = 6a^2\), not \(5a\) or \(6a\).
Forgetting the hidden \(-1\). \(-w \times 4w = -4w^2\).
Writing pronumerals out of order. Write \(6abc\), not \(6bca\).
Wrong sign with three negatives. An odd number of negatives gives a negative answer.

Frequently asked questions

How do you multiply algebraic terms?

Multiply the numbers, then the pronumerals: \(3a \times 4b = 12ab\).

What is x times x?

\(x^2\), because \(x\) is used as a factor twice.

What is a negative term times a negative term?

Positive: \(-2m \times (-5n) = 10mn\).

Why write pronumerals in alphabetical order?

It makes like terms easy to spot: \(ba\) and \(ab\) are both written \(ab\).

How do you find the area of a rectangle with algebraic sides?

Multiply length by width: \(3m \times 2n = 6mn\).