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Year 8 Maths Algebra

Dividing Terms

20 practice questions 1 video lesson Theory + worked examples

Dividing algebraic terms in NSW Year 8 maths means writing the division as a fraction and cancelling what the top and bottom share (NESA outcome MA4‑ALG‑C‑01). For example, \(6ab \div 2a = 3b\), because \(6 \div 2 = 3\) and the \(a\) cancels.

You will simplify quotients with negative signs, powers and several pronumerals, such as \(16x^2y \div 4xy^2\), where the answer may stay as a fraction. You will work out a product on the top before cancelling and use the order of operations in mixed expressions. Finding the length of a rectangle from its area and its width is a division of terms. It is part of Year 8 Algebra.

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Theory

To divide terms, divide (or simplify) the numbers, then cancel the pronumerals that are on both the top and the bottom. With powers of the same pronumeral, subtract the indices: \(9x^3 \div 3x = 3x^{3-1} = 3x^2\). This Year 8 maths page shows how.

Write the division as a fraction, first term on top: \(20cd \div 5c = \dfrac{20cd}{5c}\).

Expand the top and bottom so every factor shows. Divide the numbers by their HCF. Cancel each pronumeral that is on both the top and the bottom, because a pronumeral divided by itself is \(1\). A pronumeral only on the top stays on top; one only on the bottom stays on the bottom.

Powers. The same pronumeral to different powers: subtract the indices, \(x^3 \div x^1 = x^{3-1} = x^2\). If the bigger power is on the bottom, what is left stays on the bottom: \(\dfrac{k}{k^3} = \dfrac{1}{k^2}\).

Signs. Same signs give a positive answer; different signs a negative one. A minus sign in front of a fraction belongs to the whole fraction.

Order. The fraction bar groups: work out a product on top first. \(\times\) and \(\div\) are done left to right, before \(+\) and \(-\): \(12 - 9m \div 3 = 12 - 3m\).

Cancelling a division of terms The fraction 20 times p times p times q over 8 times p times q. The numbers 20 and 8 cancel by their HCF 4 to 5 over 2; one p and the q cancel, leaving 5p over 2. 20 × p × p × q ―――――――― 8 × p × q 20 ÷ 4 = 5 = 5p ÷ 2 8 ÷ 4 = 2
\(\dfrac{20p^2q}{8pq}\): the numbers cancel by their HCF \(4\) to \(\dfrac{5}{2}\); one \(p\) and the \(q\) cancel, leaving \(\dfrac{5p}{2}\).

What cancels:

FractionExpandedCancels to
\(\dfrac{k}{k}\)\(\dfrac{k}{k}\)\(1\)
\(\dfrac{k^3}{k}\)\(\dfrac{k \times k \times k}{k}\)\(k^2\)
\(\dfrac{k}{k^3}\)\(\dfrac{k}{k \times k \times k}\)\(\dfrac{1}{k^2}\)
A pronumeral divided by itself is 1, not 0. \(9v \div v = 9\).
Cancel only what is on both the top and the bottom. \(20c \div 8d = \dfrac{5c}{2d}\).

How to divide terms

  1. Write it as a fraction and decide the sign.
  2. Divide the numbers by their HCF.
  3. Cancel pronumerals (subtract the indices of a repeated pronumeral).
  4. Check by substituting numbers.
Example 1 — Subtract the powers
Simplify \(9x^3 \div 3x\).
Solution
\(9x^3 \div 3x\)\(=\)\((9 \div 3) \times x^3 \div x^1\)
\(\)\(=\)\(3x^{3-1} = 3x^2\)
3 x

\(3x^2\)

Example 2 — A pronumeral that stays
Simplify \(8x^2y \div 4x\).
Solution
\(8x^2y \div 4x\)\(=\)\((8 \div 4) \times (x^2 \div x) \times y\)
\(\)\(=\)\(2xy\)
2 xy

\(2xy\) (the \(y\) is only on the top)

Example 3 — A fraction to cancel
Simplify \(\dfrac{15yx^2}{3xy}\).
Solution
\(\dfrac{15yx^2}{3xy}\)\(=\)\(5 \times \dfrac{x^2y}{xy}\)
\(\)\(=\)\(5x\)
5 x

\(5x\): one \(x\) and the \(y\) cancel.

Example 4 — Signs
Simplify
(i) \(\dfrac{-28k^2}{7k}\)
(ii) \(\dfrac{-30w}{-5w}\)
Solution
\(\dfrac{-28k^2}{7k}\)\(=\)\(-4k\)
\(\dfrac{-30w}{-5w}\)\(=\)\(6\)
−4 k 6

(i) \(-4k\). Check with \(k = 3\): \(-252 \div 21 = -12\).
(ii) \(6\) (every pronumeral cancels)

Example 5 — Pronumerals on both sides
Simplify \(\dfrac{18e^2f}{4ef^2}\).
Solution
\(\dfrac{18e^2f}{4ef^2}\)\(=\)\(\dfrac{18 \times e \times e \times f}{4 \times e \times f \times f}\)
\(\)\(=\)\(\dfrac{9e}{2f}\)
9 e /(2 f )

\(\dfrac{9e}{2f}\). Check with \(e = 2\), \(f = 3\): \(216 \div 72 = 3\) and \(\dfrac{18}{6} = 3\).

Example 6 — Mixed operations
Simplify
(i) \(18n \div (-6) \times 2n\)
(ii) \(20p^2 - \dfrac{15p^3}{5p}\)
Solution
\(18n \div (-6)\)\(=\)\(-3n\)
\(-3n \times 2n\)\(=\)\(-6n^2\)
\(20p^2 - 3p^2\)\(=\)\(17p^2\)
−6 n 17 p

(i) \(-6n^2\) (left to right)
(ii) \(\dfrac{15p^3}{5p} = 3p^2\), so \(17p^2\)

Common pitfalls

Writing 0 when a pronumeral cancels. \(6m \div 6m = 1\).
Cancelling different pronumerals. \(\dfrac{8a}{4b} = \dfrac{2a}{b}\); \(a\) and \(b\) do not cancel.
Writing a coefficient of 1. \(\dfrac{3a}{9b} = \dfrac{a}{3b}\), not \(\dfrac{1a}{3b}\).
Dividing only part of an expression. \(12 - 9m \div 3 = 12 - 3m\).

Frequently asked questions

How do you divide algebraic terms?

Write it as a fraction, divide the numbers, then cancel pronumerals: \(12ab \div 4a = 3b\).

What is x cubed divided by x?

\(x^2\): subtract the indices, \(3 - 1 = 2\).

What happens when the same term is on the top and the bottom?

It cancels to \(1\): \(\dfrac{5y}{5y} = 1\).

Can the answer be a fraction?

Yes: \(14m \div 4n = \dfrac{7m}{2n}\).

What is a negative divided by a negative?

Positive: \(\dfrac{-12t}{-4} = 3t\).