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Year 7 Maths Area and Volume

Area of Composite Shapes

20 practice questions 1 video lesson Theory + worked examples

A composite shape is made from rectangles, triangles and parallelograms joined together, or a large shape with a piece removed. In NSW Year 7 maths (NESA outcome MA4‑ARE‑C‑01) you find its area by splitting it into simple parts.

You will add the parts or subtract a cut-out, work out missing lengths on L-shaped and stepped figures first, check with a second way of splitting, and find a missing length when the total area is known. Lawns with ponds, paths around gardens and shed walls with doors are typical examples. It is part of Year 7 Area and Volume.

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Theory

A composite shape is made of two or more simple shapes joined together. Its area is the total of the parts (split and add), or a big shape minus the part that is missing (take away). This Year 7 maths page shows both methods, how to find missing lengths and how to check one method with another.

Method 1: add the parts. Split the shape with a dashed line into simple shapes. Find each area on its own line, then add: \(A = A_1 + A_2\).

Method 2: take away. Find the area of the whole big shape, then subtract the missing part (a cut-out, a pond, a door): \(A = A_1 - A_2\).

Find missing lengths first. In a shape with all right angles, opposite sides match: in the figure in Diagrams, bottom \(=\) top \(+\) step, so \(10 = 6 + 4\), and left \(=\) right \(+\) step, so \(8 = 5 + 3\).

Use the right formula for each part: rectangle \(A = l \times w\); square \(A = s \times s\); triangle \(A = \dfrac{1}{2} \times b \times h\); parallelogram \(A = b \times h\).

Know the total area? Work backwards: subtract the part you can find, then divide what is left by the side you know.

Composite shape split across A 10 by 8 shape with a 4 by 3 corner missing at the top right. A dashed line across at height 5 splits it into rectangle A (10 by 5) and rectangle B (6 by 3). 10 8 6 3 4 5 A B
Split across: \(10 \times 5 + 6 \times 3 = 50 + 18 = 68\). Split down at \(6\): \(6 \times 8 + 4 \times 5 = 48 + 20 = 68\). Take away the missing corner: \(10 \times 8 - 4 \times 3 = 80 - 12 = 68\). Every way gives \(68~\text{cm}^2\).

Two methods:

\[ A = A_1 + A_2 \quad \text{(split and add)} \]
A = A 1+ A 2( split and add )
\[ A = A_1 - A_2 \quad \text{(take away)} \]
A = A 1− A 2( take away )
Count each part once. The split lines must not overlap. Splitting across uses the 6 by 3 top, not 6 by 8.
Halve only the triangles. Rectangles and parallelograms are not halved. Give the answer in square units.

How to find the area of a composite shape

  1. Find any missing lengths.
  2. Split into simple shapes (or see the big shape minus a missing part).
  3. Find each area with its own formula.
  4. Add (or subtract), then check with another method.
Example 1 — Parallelogram and triangle
Find the area of the shape (lengths in units).
Parallelogram ABDE and triangle DBC A shape made of parallelogram ABDE (top AB = 4, height AF = 5) and triangle DBC with base DC = 6. A B C D E F 4 6 5
Solution
\(4 \times 5\)\(=\)\(20\)
\(\dfrac{1}{2} \times 6 \times 5\)\(=\)\(15\)
\(20 + 15\)\(=\)\(35\)
parallelogram ABDE 4×5=20, triangle DBC 1/2×6×5=15,20+15=35

Area \(= 35\) square units.

Example 2 — Square minus a triangle
Find the area of the shape (lengths in units).
Square with a triangle cut out of the top Square ABCD with side 6 has triangle AED cut out of the top. E is 3 units above the middle of BC. A B C D E 6 6 3
Solution
\(6 \times 6\)\(=\)\(36\)
\(\dfrac{1}{2} \times 6 \times (6 - 3)\)\(=\)\(9\)
\(36 - 9\)\(=\)\(27\)
square 6×6=36, triangle AED 1/2×6×(6−3)=9,36−9=27

The triangle has height \(6 - 3 = 3\). Area \(= 27\) square units.

Example 3 — Split into rectangles
An L-shape has bottom \(11\) cm and left side \(8\) cm. The right side is \(4\) cm and the top is \(5\) cm. All angles are right angles. Find its area.
L-shape split down An L-shape: bottom 11, right 4, top 5, left 8. A dashed line down from the inside corner splits it into A (5 by 8) and B (6 by 4). 11 cm 8 cm 5 cm 4 cm A B
Solution
\(11 - 5\)\(=\)\(6\)
\(5 \times 8\)\(=\)\(40\)
\(6 \times 4\)\(=\)\(24\)
\(40 + 24\)\(=\)\(64\)
11−5=6, A =5×8=40, B =6×4=24,40+24=64

\(64~\text{cm}^2\). Check: \(11 \times 8 - 6 \times 4 = 88 - 24 = 64\).

Example 4 — Take away a hole
A picture frame is \(30\) cm by \(24\) cm. The opening for the photo is \(20\) cm by \(14\) cm. Find the area of the frame.
Solution
\(30 \times 24\)\(=\)\(720\)
\(20 \times 14\)\(=\)\(280\)
\(720 - 280\)\(=\)\(440\)
30×24=720,20×14=280,720−280=440

\(440~\text{cm}^2\)

Example 5 — Lawn and cost
A backyard is \(12\) m by \(8\) m. A right-angled triangular garden bed fills one corner: \(6\) m along one fence and \(4\) m along the other. The rest is lawn. Turf costs \(\$15\) per square metre. Find the cost of turf for the lawn.
Solution
\(12 \times 8\)\(=\)\(96\)
\(\dfrac{1}{2} \times 6 \times 4\)\(=\)\(12\)
\(96 - 12\)\(=\)\(84\)
\(84 \times 15\)\(=\)\(1260\)
12×8=96,1/2×6×4=12,96−12=84,84×15=1260

Lawn \(84~\text{m}^2\); the turf costs \(\$1260\).

Example 6 — Steps
The side of a set of \(3\) concrete steps is drawn as a staircase. Each step is \(40\) cm deep and \(25\) cm high. Find the area of the side.
Solution
\(40 \times 25\)\(=\)\(1000\)
\(1000 \times (1 + 2 + 3)\)\(=\)\(6000\)
one block 40×25=1000, columns of 1,2 and 3 blocks 1000×6=6000

Split into columns of \(1\), \(2\) and \(3\) blocks, each block \(1000~\text{cm}^2\): \(6000~\text{cm}^2\).

Example 7 — Working backwards
An L-shaped room has a total area of \(45~\text{m}^2\). Part A is \(27~\text{m}^2\). Part B is a rectangle \(6\) m wide. How long is part B?
Solution
\(45 - 27\)\(=\)\(18\)
\(18 \div 6\)\(=\)\(3\)
45−27=18,18÷6=3

Part B is \(3\) m long.

Common pitfalls

Guessing lengths. Diagrams are often not to scale. Work out missing lengths from the ones given.
Overlapping parts. Each piece of the shape must be counted exactly once.
Halving rectangles. Only triangles use the half.
Adding a hole. A hole, pond or door is taken away, not added.

Frequently asked questions

What is a composite shape?

A shape made of two or more simple shapes joined together.

How do you find the area of a composite shape?

Split it into simple shapes and add their areas, or take the missing part away from a bigger shape.

How do you find a missing length?

Opposite sides match: the total length one way equals the total the other way.

Do both methods give the same answer?

Yes. Use one to check the other.

How do you find the area of a frame?

Area of the whole rectangle minus the area of the opening.