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Year 7 Maths Angles

Proving Parallel Lines

20 practice questions 1 video lesson Theory + worked examples

Proving Parallel Lines turns the angle rules around: instead of using parallel lines to find angles, you use angles to decide whether lines are parallel. In NSW Year 7 maths (NESA outcome MA4‑ANG‑C‑01) this reversed rule is called the converse.

You will test whether corresponding or alternate angles are equal, or whether co-interior angles add to \(180^\circ\), then write a conclusion with its reason. You will also find the value that would make two lines parallel and judge an argument about two roads crossed by a highway. This subtopic is part of Year 7 Angles.

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Practice questions

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Theory

To prove two lines are parallel, show that a pair of corresponding angles are equal, a pair of alternate angles are equal, or a pair of co-interior angles add to \(180^\circ\). This Year 7 maths page sets out the three steps and works through parallel, not-parallel and two-step proofs.

Until now the arrow marks told you the lines were parallel, and you found the angles. Now the angles tell you whether the lines are parallel. This is the converse of each rule.

Two lines are parallel if alternate angles are equal, or corresponding angles are equal, or co-interior angles are supplementary (add to \(180^\circ\)).

Three steps. (1) Locate the two angles and name the pair. (2) Test: are they equal, or do they add to \(180^\circ\)? (3) Write the conclusion with its reason.

If the test fails, the lines are not parallel: “The co-interior angles add to \(175^\circ\), not \(180^\circ\), so \(AB\) is not parallel to \(CD\).”

Alternate angles of 64 degrees Lines AB and CD cut by a transversal; 64 degrees below AB on the left and 64 degrees above CD on the right. 64° 64° A B C D
Parallel. Alternate angles: \(64^\circ = 64^\circ\). The alternate angles are equal, so \(AB \parallel CD\).
Co-interior angles of 100 and 75 degrees Lines AB and CD cut by a transversal; 100 degrees below AB on the right and 75 degrees above CD on the right. CD tilts slightly so the lines would meet far to the right. 100° 75° A B C D
Not parallel. Co-interior angles: \(100^\circ + 75^\circ = 175^\circ \ne 180^\circ\). The lines slowly get closer and would meet far to the right.

If ..., then write ...:

IfThen write
corresponding angles are equalThe corresponding angles are equal, so \(AB \parallel CD\).
alternate angles are equalThe alternate angles are equal, so \(AB \parallel CD\).
co-interior angles add to \(180^\circ\)The co-interior angles are supplementary, so \(AB \parallel CD\).
Don’t trust your eyes. Lines can look parallel when the angles differ by only \(1^\circ\) or \(2^\circ\). Use the angle sizes, not the picture.
Vertically opposite angles prove nothing. They are always equal, whether or not the lines are parallel.

How to prove two lines are parallel

  1. Locate the two angles and name the pair (corresponding, alternate or co-interior).
  2. Test: equal (corresponding, alternate) or adding to \(180^\circ\) (co-interior)?
  3. Conclude with the reason, or say the lines are not parallel.
Example 1 — Alternate angles
Is \(AB \parallel CD\)? Give a reason.
Two angles of 73 degrees Lines AB and CD cut by a transversal; 73 degrees below AB on the left and 73 degrees above CD on the right. 73° 73° A B C D
Solution

Both angles are between the lines, on opposite sides: alternate angles. Test: \(73^\circ = 73^\circ\).

Yes. The alternate angles are equal, so \(AB \parallel CD\).

Example 2 — A not-parallel case
Is \(AB \parallel CD\)? Give a reason.
96 and 81 degrees Lines AB and CD cut by a transversal; 96 degrees below AB on the right and 81 degrees above CD on the right. 96° 81° A B C D
Solution

Both angles are between the lines, on the same side: co-interior angles.

\(96 + 81\)\(=\)\(177\)
96+81=177

No. \(177 \ne 180\): the co-interior angles are not supplementary, so \(AB\) is not parallel to \(CD\).

Example 3 — Fixing a naming slip
Lines \(PQ\) and \(RS\) are cut by transversal \(EF\) at \(K\) and \(L\). \(\angle QKL = 100^\circ\) and \(\angle KLS = 85^\circ\). Is \(PQ \parallel RS\)?
100 and 85 degrees Lines PQ and RS cut by transversal EF at K and L. Angle QKL is 100 degrees and angle KLS is 85 degrees, both between the lines on the right. 100° 85° P Q R S E F K L
Solution

Name each angle with its vertex in the middle: the vertex is the crossing point (\(K\) or \(L\)), not the end of the transversal. \(\angle QKL\) and \(\angle KLS\) are co-interior.

\(100 + 85\)\(=\)\(185\)
100+85=185

\(185 \ne 180\), so \(PQ\) is not parallel to \(RS\).

Example 4 — Make the lines parallel
What value of \(x\) would make \(AB \parallel CD\)?
75 and x + 20 Lines AB and CD cut by a transversal; 75 degrees below AB on the left and (x + 20) degrees above CD on the right. 75° (x+20)° A B C D
Solution

The angles are alternate. For \(AB \parallel CD\) they must be equal.

\(x + 20\)\(=\)\(75\)
\(x\)\(=\)\(55\)
x +20=75, x =55

\(x = 55\). Check: \(55 + 20 = 75\).

Example 5 — A two-step proof
\(\angle EGB = 68^\circ\) and \(\angle CHF = 68^\circ\). Prove that \(AB \parallel CD\).
Angles EGB and CHF Lines AB and CD cut by EF at G and H. Angle EGB (above AB on the right) is 68 degrees; angle CHF (below CD on the left) is 68 degrees. 68° 68° A B C D E F G H
Solution

\(\angle EGB\) and \(\angle CHF\) are not a pair yet. Vertically opposite angles are equal: \(\angle AGH = \angle EGB = 68^\circ\). \(\angle AGH\) and \(\angle CHF\) are both below their line, left of \(EF\): corresponding angles.

\(\angle AGH = \angle CHF = 68^\circ\). The corresponding angles are equal, so \(AB \parallel CD\).

Example 6 — Shelves and sides
(i) A brace makes \(58^\circ\) with a top shelf and \(122^\circ\) with a bottom shelf, both on the same side of the brace, between the shelves. Are the shelves parallel?
(ii) Quadrilateral \(ABCD\) has \(\angle A = 55^\circ\), \(\angle B = 120^\circ\), \(\angle C = 60^\circ\) and \(\angle D = 125^\circ\). Which sides are parallel?
Solution
\(58 + 122\)\(=\)\(180\)
\(55 + 125\)\(=\)\(180\)
\(55 + 120\)\(=\)\(175\)
58+122=180,55+125=180,55+120=175

(i) Yes: the co-interior angles are supplementary.
(ii) \(AD\) is a transversal for \(AB\) and \(DC\): \(\angle A + \angle D = 180^\circ\), so \(AB \parallel DC\). \(\angle A + \angle B = 175^\circ\), so \(AD\) is not parallel to \(BC\). Only \(AB \parallel DC\).

Common pitfalls

Trusting the picture. Lines that look parallel may not be. Use the angle sizes.
Using vertically opposite angles. They are always equal, so they prove nothing about parallel lines.
“Adds to 180°” for the wrong pair. Only co-interior angles must add to \(180^\circ\). \(117^\circ + 63^\circ = 180^\circ\) proves nothing if the angles are alternate.
No conclusion. Finish with a sentence: “The alternate angles are equal, so \(AB \parallel CD\).”

Frequently asked questions

How do you prove two lines are parallel?

Show corresponding angles are equal, alternate angles are equal, or co-interior angles add to 180°.

What does converse mean here?

The angle rule used backwards: the angles show the lines are parallel.

Can vertically opposite angles prove lines are parallel?

No. They are always equal.

How do you show lines are not parallel?

Show a pair of alternate or corresponding angles are not equal, or co-interior angles do not add to \(180^\circ\).

What value makes two lines parallel?

The value that makes the alternate or corresponding angles equal, or the co-interior angles add to 180°.