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Year 7 Maths Angles

Alternate Angles on Parallel Lines

20 practice questions 1 video lesson Theory + worked examples

Alternate angles lie between two lines, on opposite sides of a transversal. This NSW Year 7 maths subtopic (NESA outcome MA4‑ANG‑C‑01) shows that they are equal whenever the two lines are parallel.

You will find alternate pairs by their Z shape, work out missing angles from diagrams and from named points such as \(\angle AXY\), and write a correct reason for each answer. Harder questions place a point between two parallel lines and ask for the angle there. The rails and a diagonal brace of a gate make the same shape. This subtopic is part of Year 7 Angles.

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Theory

Alternate angles lie between two lines, on opposite sides of a transversal. If the lines are parallel, alternate angles are equal. This Year 7 maths page shows how to spot alternate angles (a Z shape) and use them with reasons, including an extra parallel line through a point.

A transversal crossing two lines makes \(8\) angles. The \(4\) angles between the two lines are \(c\), \(d\), \(e\) and \(f\).

Alternate angles are between the lines and on opposite sides of the transversal: \(c\) and \(f\), and \(d\) and \(e\). Together an alternate pair makes a Z shape (which may be back to front).

The rule. Arrow marks show the lines are parallel. Then alternate angles on parallel lines are equal.

With named points (a transversal meets \(AB\) at \(X\) and \(CD\) at \(Y\)), name the parallel lines: “alternate angles, \(AB \parallel CD\)”: \(\angle XYD = \angle AXY\).

Alternate angles c and f Two parallel lines cut by a transversal with angles a to h. c (below the top line, left) and f (above the bottom line, right) are red: they are between the lines on opposite sides. a b c d e f g h A B C D
\(c\) and \(f\) are both between the lines, on opposite sides of the transversal: a Z shape, so \(c = f\). The other alternate pair is \(d\) and \(e\).

Alternate pairs (between the lines, opposite sides):

PairTop crossingBottom crossing
first pair\(c\) (below, left)\(f\) (above, right)
second pair\(d\) (below, right)\(e\) (above, left)
\[ \text{Alternate angles on parallel lines are equal} \]
Alternate angles on parallel lines are equal
An extra parallel line. For a point between two parallel lines, draw a third parallel line through it. It makes two pairs of alternate angles.
A triangle between parallel lines. A line through one corner of a triangle, parallel to the opposite side, makes a pair of alternate angles with each of the other two sides.

How to use alternate angles

  1. Check that the lines are parallel.
  2. Check both angles are between the lines, on opposite sides of the transversal.
  3. Write the reason and set them equal.
  4. Finish with other angle facts if needed.
Example 1 — Find an alternate angle
Find the value of \(a\).
Alternate angles 66 and a Parallel lines. 66 degrees below the top line on the left; a above the bottom line on the right. 66° a°
Solution

\(66^\circ\): between the lines, left. \(a^\circ\): between the lines, right. Opposite sides: a Z shape. Alternate angles on parallel lines are equal.

\(a = 66\)

Example 2 — Two steps
Find the values of \(a\) and \(b\).
Angles 114, a and b Parallel lines. 114 degrees below the top line on the right; a above the bottom line on the left; b above the bottom line on the right. 114° a° b°
Solution

\(a^\circ\) and \(114^\circ\) are alternate. \(b^\circ\) and \(a^\circ\) are on a straight line.

\(a\)\(=\)\(114\)
\(b\)\(=\)\(180 - 114 = 66\)
a =114, b =180−114=66

\(a = 114\), \(b = 66\)

Example 3 — Vertically opposite, then alternate
\(PQ \parallel RS\) and \(\angle SVW = 108^\circ\). Find the size of \(\angle QUV\).
Angle SVW is 108 degrees Parallel lines PQ and RS cut by transversal TW at U and V. Angle SVW, below RS on the right, is 108 degrees. 108° P Q R S T W U V
Solution
\(\angle RVU\)\(=\)\(\angle SVW = 108^\circ\)
\(\angle QUV\)\(=\)\(\angle RVU = 108^\circ\)
RVU = SVW =108, QUV = RVU =108

Vertically opposite angles are equal, then alternate angles, \(PQ \parallel RS\). \(\angle QUV = 108^\circ\).

Example 4 — Straight line, then alternate
\(AB \parallel CD\) and \(\angle DGH = 75^\circ\). Find the size of \(\angle AFG\).
Angle DGH is 75 degrees Parallel lines AB and CD cut by transversal EH at F and G. Angle DGH, below CD on the right, is 75 degrees. 75° A B C D E H F G
Solution
\(\angle FGD\)\(=\)\(180^\circ - 75^\circ = 105^\circ\)
\(\angle AFG\)\(=\)\(\angle FGD = 105^\circ\)
FGD =180−75=105, AFG = FGD =105

Angles on a straight line add to \(180^\circ\), then alternate angles, \(AB \parallel CD\). \(\angle AFG = 105^\circ\).

Example 5 — Naming the angles
\(AB \parallel CD\) and \(\angle AGE = 74^\circ\). Find \(\angle BGH\), \(\angle GHC\) and \(\angle GHD\).
Angle AGE is 74 degrees Parallel lines AB and CD cut by transversal EF at G and H. Angle AGE, above AB on the left, is 74 degrees. 74° A B C D E F G H
Solution
\(\angle BGH\)\(=\)\(\angle AGE = 74^\circ\)
\(\angle GHC\)\(=\)\(\angle BGH = 74^\circ\)
\(\angle GHD\)\(=\)\(180^\circ - 74^\circ = 106^\circ\)
BGH = AGE =74, GHC = BGH =74, GHD =180−74=106

Vertically opposite angles are equal; alternate angles, \(AB \parallel CD\); angles on a straight line add to \(180^\circ\).

Example 6 — Draw an extra parallel line
\(AB \parallel CD\) and \(X\) is a point between them. Find the value of \(x\).
Point X between parallel lines Parallel lines AB (top) and CD (bottom). X is between them, joined to A and to C. Angle BAX is 38 degrees, angle DCX is 47 degrees and angle AXC is x degrees. A dashed line XY through X is parallel to both. 38° 47° x° A B C D X Y
Solution

Draw \(XY\) through \(X\), parallel to \(AB\) and \(CD\) (dashed). It splits \(x^\circ\) into two parts. Alternate angles, \(AB \parallel XY\): the top part is \(38^\circ\). Alternate angles, \(XY \parallel CD\): the bottom part is \(47^\circ\).

\(x\)\(=\)\(38 + 47 = 85\)
x =38+47=85

\(x = 85\)

Example 7 — A triangle between parallel lines
\(PQ \parallel BC\). Find \(x\), \(y\) and \(z\).
Triangle ABC with PQ parallel to BC Line PQ through A is parallel to BC. Angle ABC is 55 degrees, angle ACB is 65 degrees; x, y and z are the angles at A between PQ and AB, between AB and AC, and between AC and PQ. 55° 65° x° y° z° A B C P Q
Solution

\(x\) and \(\angle ABC\) are alternate (\(PQ \parallel BC\)); so are \(z\) and \(\angle ACB\). Then \(x\), \(y\) and \(z\) make a straight angle at \(A\).

\(x\)\(=\)\(55\)
\(z\)\(=\)\(65\)
\(y\)\(=\)\(180 - 55 - 65 = 60\)
x =55, z =65, y =180−55−65=60

\(x = 55\), \(y = 60\), \(z = 65\)

Common pitfalls

Angles outside the lines. \(a\) and \(h\) are on opposite sides but outside the lines, so they are not alternate angles.
Same side is not alternate. \(d\) and \(f\) are between the lines on the same side. They are co-interior and add to \(180^\circ\).
No arrow marks. With no arrow marks and no ∥ statement, alternate angles do not have to be equal.
Leaving out the reason. Write the reason, naming the parallel lines, before each equation.

Frequently asked questions

What are alternate angles?

Angles between two lines, on opposite sides of a transversal.

Are alternate angles always equal?

Only when the lines are parallel.

What shape do alternate angles make?

A Z shape, which may be back to front.

How do you find an angle at a point between two parallel lines?

Draw a third parallel line through the point and use two pairs of alternate angles.

What reason do you write?

Alternate angles on parallel lines are equal (or: alternate angles, \(AB \parallel CD\)).