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Year 7 Maths Algebra and Equations

Equations - Guess and Check

20 practice questions 1 video lesson Theory + worked examples

An equation is a number sentence with an equals sign, and its solution is the value that makes both sides match. This NSW Year 7 maths subtopic (NESA outcome MA4‑EQU‑C‑01) explains how an equation differs from an expression and solves equations by trial.

You will use guess and check: try a value, work out the left-hand side, compare it with the right-hand side and adjust. For \(3x + 5 = 26\), \(x = 5\) is too small and \(x = 8\) too big, so try \(x = 7\). You will also test whether a given number is a solution, the same reasoning you use when sharing a budget evenly. This subtopic is part of Year 7 Algebra and Equations.

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Theory

An equation is a number sentence with an equals sign. Its solution is the number that makes both sides equal. This Year 7 maths page shows how to test a solution and how to solve equations by guess, check and improve, using each result to make a better guess.

\(3x + 5\) is an expression: it has no equals sign. \(3x + 5 = 26\) is an equation: it says the two sides are equal. The left-hand side (LHS) is \(3x + 5\) and the right-hand side (RHS) is \(26\).

Solving an equation means finding the value of the pronumeral that makes LHS \(=\) RHS. That value is the solution.

To test whether a number is a solution, substitute it. If LHS \(=\) RHS it is a solution; if not, it is not.

Guesses for 3x + 5 = 26 A number line from 4 to 9. The guess 5 gives 20, too small. The guess 8 gives 29, too big. The guess 7 gives 26, correct. 456789 20 29 26 ✓
Solving \(3x + 5 = 26\). \(x = 5\) gives \(20\), too small, so go bigger. \(x = 8\) gives \(29\), too big. The solution lies between \(5\) and \(8\): \(x = 7\) gives exactly \(26\).

Guess, check, improve:

  1. Guess a value for the pronumeral.
  2. Substitute it and work out the LHS.
  3. Compare with the RHS: too small or too big? Use this to choose a better guess.
  4. Repeat until LHS \(=\) RHS, then check.
Taking away turns the rule around. In \(20 - 3m = 8\), a bigger \(m\) takes more away, so the LHS gets smaller: \(m = 2\) gives \(14\) (too big), \(m = 5\) gives \(5\) (too small), \(m = 4\) gives \(8\).
Brackets and fraction lines group. In \(\dfrac{x + 2}{5} = 3\), add \(2\) to the guess first, then divide by \(5\): \(x = 13\) gives \(\dfrac{15}{5} = 3\).

How to solve by guess and check

  1. Make a first guess and work out the LHS (order of operations).
  2. Decide: is the LHS too small or too big?
  3. Improve the guess in the right direction.
  4. Stop when LHS \(=\) RHS, then write the solution.
Example 1 — Is it a solution?
(i) Is \(x = 6\) a solution of \(4x - 7 = 19\)?
(ii) Is \(y = 4\) a solution of \(3y + 2 = 14\)?
Solution
\(4 \times 6 - 7\)\(=\)\(17\)
\(3 \times 4 + 2\)\(=\)\(14\)
4×6−7=17,3×4+2=14

(i) No: \(17 \ne 19\).
(ii) Yes: LHS \(= 14 =\) RHS.

Example 2 — Guess and check
Use guess and check to solve \(2x + 4 = 14\).
Solution
\(2 \times 4 + 4\)\(=\)\(12 \text{ (too small)}\)
\(2 \times 5 + 4\)\(=\)\(14 \;\checkmark\)
2×4+4=12 too small ,2×5+4=14

\(x = 5\)

Example 3 — Guess, check, improve
Use guess and check to solve \(5x + 3 = 38\).
Solution
\(5 \times 5 + 3\)\(=\)\(28 \text{ (too small)}\)
\(5 \times 8 + 3\)\(=\)\(43 \text{ (too big)}\)
\(5 \times 7 + 3\)\(=\)\(38 \;\checkmark\)
5×5+3=28 too small ,5×8+3=43 too big ,5×7+3=38

The solution is between \(5\) and \(8\): \(x = 7\).

Example 4 — Taking away
Use guess and check to solve \(14 - 2m = 8\).
Solution
\(14 - 2 \times 2\)\(=\)\(10 \text{ (too big)}\)
\(14 - 2 \times 3\)\(=\)\(8 \;\checkmark\)
14−2×2=10 too big ,14−2×3=8

A bigger \(m\) makes the LHS smaller, so after \(10\) (too big) try a bigger \(m\). \(m = 3\).

Example 5 — Brackets and fractions
Use guess and check to solve
(i) \(3(x - 2) = 21\)
(ii) \(\dfrac{a}{4} + 1 = 6\)
Solution
\(3 \times (5 - 2)\)\(=\)\(9 \text{ (too small)}\)
\(3 \times (10 - 2)\)\(=\)\(24 \text{ (too big)}\)
\(3 \times (9 - 2)\)\(=\)\(21 \;\checkmark\)
\(\dfrac{20}{4} + 1\)\(=\)\(6 \;\checkmark\)
3×(5−2)=9,3×(10−2)=24,3×(9−2)=21,20/4+1=6

(i) \(x = 9\)
(ii) Try multiples of \(4\): \(a = 20\).

Example 6 — Consecutive integers
Three consecutive integers add to \(45\). Let the smallest be \(x\). Write an equation, then use guess and check to find the three integers.
Solution

The next two integers are \(x + 1\) and \(x + 2\), so \(x + (x + 1) + (x + 2) = 45\).

\(10 + 11 + 12\)\(=\)\(33 \text{ (too small)}\)
\(15 + 16 + 17\)\(=\)\(48 \text{ (too big)}\)
\(14 + 15 + 16\)\(=\)\(45 \;\checkmark\)
10+11+12=33,15+16+17=48,14+15+16=45

The integers are \(14\), \(15\) and \(16\).

Common pitfalls

Ignoring the order of operations. For \(x = 7\), \(3x + 5 = 3 \times 7 + 5 = 26\). Multiply first, then add.
Guessing in the wrong direction. When the pronumeral is taken away, a bigger guess makes the LHS smaller.
Stopping too early. A guess is only the solution when LHS = RHS exactly.
Mixing up expressions and equations. \(3x + 5\) cannot be solved: it has no equals sign.

Frequently asked questions

What is the difference between an expression and an equation?

An equation has an equals sign; an expression does not.

What is the solution of an equation?

The value of the pronumeral that makes the left-hand side equal to the right-hand side.

How do you check if a number is a solution?

Substitute it. If LHS \(=\) RHS, it is a solution.

How does guess and check work?

Guess, work out the left-hand side, see if it is too big or too small, then improve the guess.

What are consecutive integers?

Integers that follow each other, such as \(14\), \(15\), \(16\): \(x\), \(x + 1\), \(x + 2\).