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Year 7 Maths Algebra and Equations

Distributive Law

20 practice questions 1 video lesson Theory + worked examples

The distributive law says that to multiply a bracket you multiply every part inside it, then add or subtract the results. In NSW Year 7 maths (NESA outcome MA4‑ALG‑C‑01) it is used first with numbers and then with pronumerals, so \(2(x + 5)\) becomes \(2x + 10\).

You will split awkward numbers into friendly sums or differences, for example \(18 \times 12 = 18 \times (10 + 2) = 216\) or \(72 \times (100 - 1)\), and link the law to a rectangle’s area when it is cut into two parts. Then you start expanding brackets. It is handy for pricing 12 items at $49 each without a calculator. This subtopic is part of Year 7 Algebra and Equations.

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Theory

The distributive law says: to multiply a group in brackets, multiply every part inside the brackets, then add (or subtract) the results. \(a \times (b + c) = a \times b + a \times c\). This Year 7 maths page shows the law as an area model, uses it for quick mental multiplication and expands brackets with pronumerals.

Brackets hold a group together. \(3 \times (20 + 7)\) means \(3\) lots of the whole group \(20 + 7\).

With a sum: \(a \times (b + c) = a \times b + a \times c\)
With a difference: \(a \times (b - c) = a \times b - a \times c\)

Mental maths. Split the harder number into a friendly sum or difference, then multiply each part: \(18 \times 12 = 18 \times (10 + 2) = 180 + 36 = 216\) and \(17 \times 9 = 17 \times (10 - 1) = 170 - 17 = 153\).

The split number can come first too: \((10 + 5) \times 6 = 60 + 30 = 90\).

With pronumerals the law is written without \(\times\) signs: \(a(b + c) = ab + ac\). Removing the brackets is called expanding: \(2(x + 5) = 2x + 10\).

Area model for 3 times 27 A rectangle 3 high and 27 long split into a 3 by 20 part with area 60 and a 3 by 7 part with area 21. 203 × 20 = 60 721 3 3 × 27 = 60 + 21 = 81
The whole area equals the two parts added: \(3 \times 27 = 3 \times 20 + 3 \times 7 = 60 + 21 = 81\).
Area model for a times b plus c A rectangle a high split into a part b wide with area ab and a part c wide with area ac. bab cac a a(b + c) = ab + ac
The same picture with pronumerals: \(a(b + c) = ab + ac\).

Quick rules from the distributive law:

To multiply byExample
\(9 = 10 - 1\): times \(10\), take away the number\(13 \times 9 = 130 - 13 = 117\)
\(11 = 10 + 1\): times \(10\), add the number\(13 \times 11 = 130 + 13 = 143\)
\(8 = 10 - 2\): times \(10\), take away double\(13 \times 8 = 130 - 26 = 104\)
\(12 = 10 + 2\): times \(10\), add double\(13 \times 12 = 130 + 26 = 156\)
\(101 = 100 + 1\): times \(100\), add the number\(13 \times 101 = 1300 + 13 = 1313\)
\(99 = 100 - 1\): times \(100\), take away the number\(13 \times 99 = 1300 - 13 = 1287\)
Multiply every part. \(6 \times (10 + 3) = 60 + 18 = 78\), not \(60 + 3\).
Two-digit numbers. Split into a multiple of ten plus or minus a small number: \(23 \times 31 = 23 \times (30 + 1) = 690 + 23 = 713\).

How to use the distributive law

  1. Split one number into a friendly sum or difference (\(99 = 100 - 1\)).
  2. Multiply every part by the other number.
  3. Add (or subtract) the results.
  4. Check the size with an estimate.
Example 1 — Three parts
The straight of a running track is \(6\) m wide and \(125\) m long. Split \(125\) into three friendly parts to find its area.
Solution
Running track area model A strip 6 metres wide split into parts 100, 20 and 5 metres long with areas 600, 120 and 30 square metres. Not to scale. 100 m600 20 m120 5 m30 6 m
\(6 \times 125\)\(=\)\(6 \times (100 + 20 + 5)\)
\(\)\(=\)\(600 + 120 + 30\)
\(\)\(=\)\(750\)
6×125=6×(100+20+5)=600+120+30=750

The area is \(750\) m².

Example 2 — Split into a sum
Use the distributive law to evaluate
(i) \(23 \times 11\)
(ii) \(32 \times 101\)
Solution
\(23 \times 11\)\(=\)\(23 \times (10 + 1)\)
\(\)\(=\)\(230 + 23 = 253\)
\(32 \times 101\)\(=\)\(32 \times (100 + 1)\)
\(\)\(=\)\(3200 + 32 = 3232\)
23×11=230+23=253,32×101=3200+32=3232

(i) \(253\)
(ii) \(3232\)

Example 3 — Split into a difference
Use the distributive law to evaluate
(i) \(7 \times 99\)
(ii) \(16 \times 99\)
Solution
\(7 \times 99\)\(=\)\(7 \times (100 - 1)\)
\(\)\(=\)\(700 - 7 = 693\)
\(16 \times 99\)\(=\)\(16 \times (100 - 1)\)
\(\)\(=\)\(1600 - 16 = 1584\)
7×99=700−7=693,16×99=1600−16=1584

(i) \(693\)
(ii) \(1584\)

Example 4 — Times 8 and times 12
Evaluate
(i) \(23 \times 8\)
(ii) \(14 \times 12\)
Solution
\(23 \times 8\)\(=\)\(23 \times (10 - 2)\)
\(\)\(=\)\(230 - 46 = 184\)
\(14 \times 12\)\(=\)\(14 \times (10 + 2)\)
\(\)\(=\)\(140 + 28 = 168\)
23×8=230−46=184,14×12=140+28=168

(i) \(184\)
(ii) \(168\)

Example 5 — Money
Tickets to a netball final cost \(\$39\) each. Find the cost of \(15\) tickets.
Solution
\(15 \times 39\)\(=\)\(15 \times (40 - 1)\)
\(\)\(=\)\(600 - 15\)
\(\)\(=\)\(585\)
15×39=15×(40−1)=600−15=585

The tickets cost \(\$585\).

Example 6 — Two-digit numbers
Evaluate
(i) \(26 \times 19\)
(ii) \(34 \times 102\)
Solution
\(26 \times 19\)\(=\)\(26 \times (20 - 1)\)
\(\)\(=\)\(520 - 26 = 494\)
\(34 \times 102\)\(=\)\(34 \times (100 + 2)\)
\(\)\(=\)\(3400 + 68 = 3468\)
26×19=520−26=494,34×102=3400+68=3468

(i) \(494\)
(ii) \(3468\)

Example 7 — Expanding brackets
Expand \(5(2k - 3)\). Check your answer with \(k = 4\).
Solution
\(5(2k - 3)\)\(=\)\(5 \times 2k - 5 \times 3\)
\(\)\(=\)\(10k - 15\)
5(2 k −3)=10 k −15

\(10k\) and \(15\) are not like terms, so stop here. Check with \(k = 4\): \(5 \times (8 - 3) = 25\) and \(40 - 15 = 25\). So \(5(2k - 3) = 10k - 15\).

Common pitfalls

Multiplying only the first part. \(6 \times (10 + 3) = 60 + 18 = 78\), not \(60 + 3\).
Subtracting just 1. \(24 \times 99 = 2400 - 24 = 2376\), not \(2400 - 1\).
Joining unlike terms. \(3(a + 4) = 3a + 12\). It cannot be simplified to \(15a\).
Splitting the wrong way. Times \(8\) is times \(10\) take away double the number, not take away \(2\).

Frequently asked questions

What is the distributive law?

\(a(b + c) = ab + ac\): multiply every part inside the brackets, then add.

How do you multiply by 99 in your head?

Multiply by \(100\), then take away the number once. \(16 \times 99 = 1600 - 16 = 1584\).

How do you multiply by 11 in your head?

Multiply by \(10\), then add the number. \(23 \times 11 = 230 + 23 = 253\).

What does expanding mean?

Removing brackets by multiplying every term inside. \(2(x + 5) = 2x + 10\).

Why does the area model show the distributive law?

The area of the whole rectangle equals the areas of its parts added together.