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Year 8 Maths Fractions and Percentages

Percentage of a Quantity

20 practice questions 2 video lessons Theory + worked examples

Percentage of a Quantity in NSW Year 8 maths (NESA outcome MA4‑FRC‑C‑01) uses a decimal multiplier: divide the percentage by 100, then multiply, so 62% of 250 is \(0.62 \times 250 = 155\).

You will find percentages above 100% and below 1%, change units, add 10% GST to a price, apply two percentages one after the other, work out a real estate agent’s commission and round money to the nearest cent. You will also compare a percentage discount with a dollar discount and decide which pack of mince is better value. It is part of Year 8 Fractions and Percentages.

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Theory

To find a percentage of a quantity, divide the percentage by \(100\) to get a decimal multiplier, then multiply: \(62\%\) of \(250\) is \(0.62 \times 250 = 155\). Per cent means out of \(100\) and ‘of’ means times. This Year 8 maths page shows how.

The decimal multiplier. Divide the percentage by \(100\): \(9\% = 0.09\), \(74\% = 0.74\), \(118\% = 1.18\), \(3.5\% = 0.035\), \(0.4\% = 0.004\). Then multiply the quantity by it.

Fractional percentages. Change the mixed numeral to an improper fraction and divide by \(100\): \(7\dfrac{1}{2}\% = \dfrac{15}{2} \div 100\).

Size check. A multiplier below \(1\) gives less than the quantity; above \(1\) gives more. \(118\%\) of an amount is bigger than the amount; \(0.4\%\) of it is tiny.

The part left is \((100 - p)\%\) of the quantity: if \(72\%\) is used, \(28\%\) is left.

Change the unit first when the answer needs a different one, then multiply.

GST (Goods and Services Tax) is \(10\%\) of the price before tax, added on top. The price including GST is \(110\%\) of it, so multiply by \(1.1\).

Two percentages in a row. The second is taken of the new amount. In one step, multiply the multipliers: \(15\%\) off then \(10\%\) off is \(0.85 \times 0.9 = 0.765\), so \(76.5\%\) is left, a discount of \(23.5\%\), not \(25\%\).

Commission is a payment worked out as a percentage of a sale, so it is found the same way.

Comparing deals. A percentage discount and a dollar discount can be compared only when both are in dollars. Money is rounded to the nearest cent (two decimal places). Better value. Divide each price by its quantity to get a price per kilogram (or per litre), round to the cent, and choose the lower one.

62 percent of 250 A bar for 250 marked from 0% to 100%; 62% of it is shaded, which is 0.62 times 250 = 155. 0.62 × 250 0 155 250
\(62\%\) of the bar for \(250\) is \(0.62 \times 250 = 155\).
Two discounts in a row Three columns: 100% at the start, 85% after 15% off, and 76.5% after a further 10% off the new price. 0 20 40 60 80 100 start 100 15% off 85 then 10% off 76.5
After \(15\%\) off, \(85\%\) is left. A further \(10\%\) off is taken from that smaller amount: \(0.9 \times 85\% = 76.5\%\).

Percentages as multipliers:

PercentageMultiplierAnswer is
\(9\%\)\(0.09\)smaller
\(74\%\)\(0.74\)smaller
\(118\%\)\(1.18\)bigger
\(3.5\%\)\(0.035\)smaller
\(0.4\%\)\(0.004\)tiny
SituationMultiplier
\(p\%\) of an amount\(p \div 100\)
\(p\%\) is used, the rest is left\((100 - p) \div 100\)
add 10% GST\(1.1\)
\(a\%\) off, then \(b\%\) offmultiply the two multipliers
\(4\%\) is \(0.04\), not \(0.4\). The zero keeps the place; \(0.4\) would find \(40\%\), ten times too much.
A second discount is of the new price. \(\$260\) with \(30\%\) off, then a further \(15\%\) off: \(0.85 \times 0.7 \times 260 = \$154.70\). Taking \(45\%\) off \(\$260\) gives \(\$143\), which is wrong.

Finding a percentage of a quantity

  1. Change the quantity to the unit the answer needs.
  2. Write the percentage as a decimal (divide by \(100\)).
  3. Multiply the quantity by the decimal.
  4. Round money to the nearest cent and check the size.

Percentages in a row

  1. Write each change as a multiplier (\(20\%\) off \(\to 0.8\), \(10\%\) on \(\to 1.1\)).
  2. Apply them one after another, or multiply them together first.
Example 1 — Fractional percentages
(i) Find \(7\dfrac{1}{2}\%\) of \(3\) hours, in minutes.
(ii) Find \(3\dfrac{1}{3}\%\) of \(\$300\).
Solution

(i) \(3\) hours \(= 180\) minutes.

\(7\dfrac{1}{2}\% \times 180\)\(=\)\(\dfrac{15}{2} \times \dfrac{1}{100} \times 180\)
\(\)\(=\)\(15 \times \dfrac{90}{100}\)
\(\)\(=\)\(13.5\)
\(3\dfrac{1}{3}\% \times 300\)\(=\)\(\dfrac{10}{3} \times \dfrac{300}{100}\)
\(\)\(=\)\(\dfrac{10}{3} \times 3 = 10\)
13.5 minutes $10

(i) \(13.5\) minutes
(ii) \(\$10\)

Example 2 — Change the unit
A jug holds \(1.8\) L of iced tea. \(45\%\) of it is poured into cups. How many millilitres are poured?
Solution
\(1.8 \times 1000\)\(=\)\(1800~\text{mL}\)
\(0.45 \times 1800\)\(=\)\(810\)
0.45×1800=810 mL

\(810\) mL is poured. Check: \(55\%\) is left, \(0.55 \times 1800 = 990\), and \(810 + 990 = 1800\).

Example 3 — Adding GST
A gym charges \(\$58\) a month before GST. Find the monthly charge including \(10\%\) GST.
Solution
\(1.1 \times 58\)\(=\)\(63.8\)
\(58 + 0.1 \times 58\)\(=\)\(58 + 5.8 = 63.8\)
1.1×58=63.80

\(\$63.80\) a month.

Example 4 — Two percentages in a row
A newsagent ordered \(400\) magazines in March. In April the order fell by \(25\%\), and in May it rose by \(20\%\). How many magazines were ordered in May?
Solution
\(0.75 \times 400\)\(=\)\(300\)
\(1.2 \times 300\)\(=\)\(360\)
\(0.75 \times 1.2\)\(=\)\(0.9\)
0.75×1.2×400=360

\(360\) magazines. May is \(90\%\) of March: down \(10\%\) overall, not down \(5\%\).

Example 5 — Rounding to the cent
Tia earns \(\$726.40\) a week. Her employer pays superannuation of \(11.5\%\) of her wage. How much super is paid, to the nearest cent?
Solution
\(11.5\%\)\(=\)\(0.115\)
\(0.115 \times 726.40\)\(=\)\(83.536\)
0.115×726.40=83.536≈83.54

\(83.536 \approx 83.54\), so \(\$83.54\). Estimate: \(10\%\) is about \(\$73\), so \(11.5\%\) is a little over \(\$80\).

Example 6 — Deals, parts and commission
(i) A scooter costs \(\$300\). Shop A offers \(25\%\) off; Shop B offers \(\$70\) off. Which saves more?
(ii) A school has \(800\) students. \(60\%\) are in the junior school and \(35\%\) of those play a sport. How many junior students play a sport?
(iii) An agent earns \(3\%\) commission on a \(\$450\,000\) sale. Find the commission.
Solution
\(0.25 \times 300\)\(=\)\(75\)
\(0.35 \times 0.6 \times 800\)\(=\)\(168\)
\(0.03 \times 450\,000\)\(=\)\(13\,500\)
$75>$70168$13500

(i) Shop A saves \(\$75\), which is \(\$5\) more than Shop B.
(ii) \(168\) students
(iii) \(\$13\,500\)

Common pitfalls

Dropping the place-holding zero. \(6\%\) is \(0.06\). Using \(0.6\) finds \(60\%\).
Adding percentages in a row. \(25\%\) off then \(10\%\) off is \(0.75 \times 0.9 = 0.675\), so \(32.5\%\) off, not \(35\%\).
Giving the GST as the price. With \(10\%\) GST, a \(\$320\) job costs \(1.1 \times 320 = \$352\). The \(\$32\) is the tax, not the total.
Comparing a percentage with dollars. Work out the percentage discount in dollars before comparing it with a dollar discount.

Frequently asked questions

How do I find a percentage of an amount?

Write the percentage as a decimal and multiply: \(35\%\) of \(80\) is \(0.35 \times 80 = 28\).

How do I add GST to a price?

Multiply the price before GST by \(1.1\), because the price with GST is \(110\%\) of it.

Why is 25% off then 10% off not 35% off?

The second discount is taken from the smaller sale price, so it removes less than 10% of the original price.

How do I find a percentage like 12 1/2%?

Change it to an improper fraction and divide by \(100\): \(12\dfrac{1}{2}\% = \dfrac{25}{2} \div 100 = \dfrac{1}{8}\).

How do I round money?

Round to two decimal places, the nearest cent: \(\$83.536 \approx \$83.54\).