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Year 7 Maths Ratios, Rates and Time

Travel Graphs

20 practice questions 1 video lesson Theory + worked examples

A travel graph, or distance–time graph, shows how far someone is from their starting point as time passes. In NSW Year 7 maths, students learn to read the story a graph tells and to work out speeds from it (NESA outcome MA4‑RAT‑C‑01).

You will read distances and times from points, explain what an upward, flat or downward section means, calculate the speed of each section and compare steepness, find the average speed for a whole trip including stops, and spot where two travellers meet. A family drive to a lake and back is a typical example. This subtopic is part of Year 7 Ratios, Rates and Time.

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Theory

A travel graph (a distance-time graph) shows how far someone is from their starting point as time goes by. A line going up means moving away, a flat line means stopped, and a line going down means coming back. The steeper the line, the faster the speed. This Year 7 maths page shows how to read, draw and find speeds from travel graphs.

Time goes across the horizontal axis. Distance from the start goes up the vertical axis. Always read the axis labels and units first.

Reading a point. Go up from the time to the line, then across to the distance axis. If the time axis shows clock times, count on between them to find the time taken.

Reading the shape. A line going up means moving away. A flat line means stopped: time passes but the distance does not change. A line going down means coming back towards the start.

Speed of a section \(=\) distance \(\div\) time, using the two ends of the section. The steeper the line, the faster. For km/h, change minutes to hours first (\(30\) min \(= 0.5\) h, \(45\) min \(= 0.75\) h). For m/s, use metres and seconds: \(120\) m in \(15\) s is \(8\) m/s, and \(8 \times 3.6 = 28.8\) km/h.

Average speed for a whole trip \(=\) total distance \(\div\) total time, with the stops included.

Two travellers on one graph. Where the two lines cross, they are at the same place at the same time.

Travel graph of a car trip Distance from home against time in hours: up to 45 km at 1.5 h, flat to 2.5 h, up to 80 km at 3 h, then up to 105 km at 4 h. 0 20 40 60 80 100 120 0 0.5 1 1.5 2 2.5 3 3.5 4 30 km/h stopped 70 km/h 25 km/h Time (hours) Distance (km)
A car trip: \(45\) km in \(1.5\) h (\(45 \div 1.5 = 30\) km/h), stopped for \(1\) h, then \(35\) km in \(30\) min (\(35 \div 0.5 = 70\) km/h, the steepest part), then \(25\) km more in \(1\) h (\(25\) km/h).
Two travellers between towns 80 km apart Distance from town A against hours after 8 am: the cyclist (orange) from 0 km at 0 h to 80 km at 4 h; the driver (blue) from 80 km at 1 h to 0 km at 2 h. The lines cross at 1.6 h, 32 km. 0 20 40 60 80 0 1 2 3 4 cyclist driver Hours after 8 am Distance from town A (km)
Towns A and B are \(80\) km apart. The lines cross at about 09:36, \(32\) km from town A: that is where and when the cyclist and the driver pass each other.

What the line tells you:

The line ...means ...
goes upmoving away
is flatstopped
goes downcoming back
is steeperfaster
is less steepslower
\[ \text{speed} = \text{distance} \div \text{time} \]
speed = distance ÷ time
\[ \text{average speed} = \text{total distance} \div \text{total time} \]
average speed = total distance ÷ total time
A travel graph is not a picture of the road. A line going up is not a hill. It means the distance from the start is getting bigger.
Do not average the speeds. Out at \(40\) km/h for \(3\) h and back at \(60\) km/h for \(2\) h: the average speed is \(240 \div 5 = 48\) km/h, not \(50\) km/h.

How to find the speed of a section

  1. Read the distance and the time at both ends of the section.
  2. Subtract to find the distance and the time for that section.
  3. Change minutes to hours (for km/h).
  4. Divide: speed \(=\) distance \(\div\) time.

How to draw a travel graph

  1. Write a point (time, distance) for the end of each stage.
  2. Plot the points, starting at \((0, 0)\), and join them with straight lines.
Example 1 — Reading a travel graph
Leo rides his scooter to a friend’s place, stays, then rides home.
(i) How far from home is he after \(10\) min?
(ii) At which two times is he \(600\) m from home?
(iii) How long does he stay?
Leo scooter trip Distance from home in metres against time in minutes: up to 1000 m at 20 min, flat until 40 min, back to 0 m at 60 min. 0 200 400 600 800 1000 1200 0 20 40 60 Time (minutes) Distance (m)
Solution

(i) Up from \(10\) min to the line, then across: halfway to \(1000\) m.
(ii) Across from \(600\) m, the line is met twice: on the way out at \(12\) min, and on the way back at \(48\) min.
(iii) The flat section runs from \(20\) min to \(40\) min.

\(40 - 20\)\(=\)\(20\)
after 10 min 500 m 600 m at 12 min and 48 min stay 40−20=20 min

(i) \(500\) m
(ii) \(12\) min and \(48\) min
(iii) \(20\) min

Example 2 — Speed of each section
The graph shows a bike ride in sections A, B and C. Find the speed in each section, in km/h. Which section is fastest?
Bike ride in sections A, B and C Distance in km against time in minutes: section A up to 16 km at 48 min, section B flat to 60 min, section C up to 28 km at 84 min. 0 8 16 24 32 0 12 24 36 48 60 72 84 A B C Time (minutes) Distance (km)
Solution
\(16 \div 0.8\)\(=\)\(20\)
\(12 \div 0.4\)\(=\)\(30\)
A 16 km in 48 min =0.8 h ,20 km / h B stopped C 12 km in 24 min =0.4 h ,30 km / h

A: \(16\) km in \(48\) min \(= 0.8\) h, so \(20\) km/h. B: flat, so stopped (\(0\) km/h). C: \(28 - 16 = 12\) km in \(84 - 60 = 24\) min \(= 0.4\) h, so \(30\) km/h. C is fastest (the steepest).

Example 3 — Drawing a travel graph
Sam rides \(12\) km from home to the beach in \(40\) minutes. He stays for \(20\) minutes, then rides straight home in \(30\) minutes.
(i) Draw the travel graph.
(ii) Find his speed home.
Solution

(i) The points are \((0, 0)\), \((40, 12)\), \((60, 12)\) and \((90, 0)\), joined with straight lines:

Sam ride to the beach and home Distance in km against time in minutes: points (0, 0), (40, 12), (60, 12), (90, 0) joined. 0 4 8 12 0 30 60 90 Time (minutes) Distance (km)
\(12 \div 0.5\)\(=\)\(24\)
12 km in 30 min =0.5 h ,24 km / h

(ii) \(12\) km in \(0.5\) h: \(24\) km/h.

Example 4 — Average speed for a return trip
A bus takes a class to a museum and back.
(i) Find the speed each way.
(ii) Find the average speed for the whole trip.
Bus trip to a museum and back Distance in km against time in hours: up to 90 km at 1.5 h, flat until 3 h, back to 0 km at 4 h. 0 20 40 60 80 100 0 0.5 1 1.5 2 2.5 3 3.5 4 Time (hours) Distance (km)
Solution
\(90 \div 1.5\)\(=\)\(60\)
\(90 \div 1\)\(=\)\(90\)
\(180 \div 4\)\(=\)\(45\)
out 90÷1.5=60 km / h , back 90÷1=90 km / h , average 180÷4=45 km / h

(i) \(60\) km/h out and \(90\) km/h back
(ii) \(45\) km/h (total distance \(\div\) total time, with the stop), not \((60 + 90) \div 2 = 75\).

Example 5 — Two travellers
Use the graph in Diagrams. Towns A and B are \(80\) km apart. A cyclist leaves town A at 08:00 and reaches town B at 12:00. A driver leaves town B at 09:00 and reaches town A at 10:00.
(i) Find each speed.
(ii) When and where do they pass?
Solution
\(80 \div 4\)\(=\)\(20\)
\(80 \div 1\)\(=\)\(80\)
cyclist 20 km / h , driver 80 km / h they pass at about 0936,32 km from town A

(i) Cyclist \(20\) km/h, driver \(80\) km/h.
(ii) Where the lines cross: about 09:36, \(32\) km from town A. (Check: the cyclist rides \(20 \times 1.6 = 32\) km in \(1.6\) h.)

Example 6 — Metres per second
A sprinter’s graph is a straight line from \((0\text{ s}, 0\text{ m})\) to \((15\text{ s}, 120\text{ m})\). Find the speed in m/s and in km/h.
Solution
\(120 \div 15\)\(=\)\(8\)
\(8 \times 3.6\)\(=\)\(28.8\)
120÷15=8 m / s ,8×3.6=28.8 km / h

\(8\) m/s, which is \(28.8\) km/h.

Common pitfalls

Minutes as hours. \(20\) km in \(30\) min is \(20 \div 0.5 = 40\) km/h, not \(20 \div 30\).
Reading the wrong axis. Time is across; distance is up.
Leaving out the stop in the average. Total time includes the time stopped.
Thinking down means downhill. Down means coming back towards the start.

Frequently asked questions

What does a flat line on a travel graph mean?

The person is stopped: time passes but the distance does not change.

How do you find speed from a travel graph?

Divide the distance for a section by the time for that section.

What does a steeper line mean?

A faster speed: more distance in the same time.

How do you find the average speed for a whole trip?

Divide the total distance by the total time, including stops.

What does it mean when two lines cross?

The two travellers are at the same place at the same time.