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Year 7 Maths Integers

Adding Integers

20 practice questions 1 video lesson Theory + worked examples

Adding Integers shows what happens when you add positive and negative numbers in NSW Year 7 maths (NESA outcome MA4‑INT‑C‑01). On a number line, start at the first number and jump right to add a positive or left to add a negative, so \(3 + (-8) = -5\).

You will add integers with the same and with different signs using their size (distance from zero), work out sums of three numbers, find a missing number, and write directed number sentences for overdrawn bank accounts, rising temperatures and world time zones, such as finding the hour in another city. It is part of Year 7 Integers.

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Theory

To add an integer, start at the first number on a number line and jump by the second: right for a positive, left for a negative. This Year 7 maths page shows how to add integers on a number line, the rules for same signs and different signs, how to add three integers and how to find a missing number.

Adding a positive moves right: \(-3 + 8 = -3 + 3 + 5 = 5\).

Adding a negative is the same as subtracting, so it moves left: \(3 + (-8) = 3 - 8 = -5\).

The size (or magnitude) of an integer is its distance from zero. The size of \(-6\) is \(6\).

In \(3 + (-8)\) the \(+\) is an operation (add) and the \(-\) in \((-8)\) shows a position (left of zero). Brackets keep the two signs apart.

A number and its opposite add to zero: \(-7 + 7 = 0\).

Minus 2 plus 5 on a number line A number line from minus 4 to 5. A blue dot at minus 2 and a jump of plus 5 to the right ending at a red dot on 3. −4−3−2−1012345 +5
\(-2 + 5 = 3\): adding \(5\) jumps \(5\) right.
One plus minus 4 on a number line A number line from minus 5 to 4. A blue dot at 1 and a jump of 4 to the left ending at a red dot on minus 3. −5−4−3−2−101234 +(−4)
\(1 + (-4) = -3\): adding \(-4\) jumps \(4\) left.

Adding by the signs:

Same signs: add the sizes and keep the sign.

\[ -5 + (-4) = -9 \]
−5+(−4)=−9

Different signs: subtract the sizes and keep the sign of the larger size.

\[ -13 + 5 = -(13 - 5) = -8 \]
−13+5=−(13−5)=−8
\[ a + (-b) = a - b \]
a +(− b )= a − b
\[ a + (-a) = 0 \]
a +(− a )=0
Different signs: the answer takes the sign of the number with the larger size. \(-9 + 4 = -5\), because \(9 > 4\).
Missing number: find the jump from the known part to the answer. In \(-3 + \square = 5\), count up \(3\) to \(0\), then \(5\) more: the jump is \(8\) right, so \(\square = 8\).

How to add on a number line

  1. Start at the first number.
  2. Jump right for a positive, left for a negative.
  3. Cross zero in two steps: to \(0\), then the rest.

How to add with the sign rules

  1. Same signs: add the sizes and keep the sign.
  2. Different signs: subtract the smaller size from the larger, and use the sign of the larger size.
  3. Three or more numbers: work left to right, or add all the negatives and all the positives first.

How to find a missing number

  1. Add the numbers you know.
  2. Find the jump from that total to the answer: right is positive, left is negative.
  3. Check by putting your number back in.
Example 1 — On a number line
Use a number line to work out \(-4 + 6\).
Minus 4 plus 6 A number line from minus 5 to 3. A jump of 4 from minus 4 to 0, then a jump of 2 from 0 to 2. −5−4−3−2−10123 +4 +2
Solution
\(-4 + 6\)\(=\)\(-4 + 4 + 2\)
\(\)\(=\)\(2\)
−4+6=−4+4+2=2

\(2\)

Example 2 — Use the signs
Work out
(i) \(-5 + (-8)\)
(ii) \(-14 + 9\)
(iii) \(11 + (-11)\)
Solution
\(-5 + (-8)\)\(=\)\(-5 - 8 = -13\)
\(-14 + 9\)\(=\)\(-(14 - 9) = -5\)
\(11 + (-11)\)\(=\)\(0\)
−5+(−8)=−13,−14+9=−5,11+(−11)=0

(i) Same signs: \(-13\)
(ii) Different signs, \(14 > 9\): \(-5\)
(iii) Opposites: \(0\)

Example 3 — Three integers
Work out \(-9 + 17 + (-6)\).
Solution
\(-9 + 17\)\(=\)\(8\)
\(8 + (-6)\)\(=\)\(2\)
−9+17=8,8+(−6)=2

Work left to right: \(2\).

Example 4 — Missing number
Find the missing number.
(i) \(-6 + (-2) + \square = 3\)
(ii) \(7 + \square = -4\)
Solution

(i) \(-6 + (-2) = -8\). From \(-8\) to \(3\): \(8\) up to \(0\), then \(3\) more, a jump of \(11\) right.
(ii) From \(7\) to \(-4\): \(7\) down to \(0\), then \(4\) more, a jump of \(11\) left.

\(-8 + 11\)\(=\)\(3\)
\(7 + (-11)\)\(=\)\(-4\)
−8+11=3,7+(−11)=−4

(i) \(11\)
(ii) \(-11\)

Example 5 — Bank balance
Leo’s account balance is \(-\$28\). He deposits \(\$45\), then a fee of \(\$6\) is added as \(-6\). What is his balance now?
Solution
\(-28 + 45\)\(=\)\(17\)
\(17 + (-6)\)\(=\)\(11\)
−28+45=17,17+(−6)=11

His balance is \(\$11\).

Example 6 — Time zones
Local time \(=\) UTC time \(+\) offset. A city has an offset of \(+10\) and another has an offset of \(-5\). When it is hour \(20\) (8 pm) in the first city, what time is it in the second?
Solution

First undo the \(+10\) by adding its opposite, \(-10\). Then add the second offset.

\(20 + (-10)\)\(=\)\(10\)
\(10 + (-5)\)\(=\)\(5\)
20+(−10)=10,10+(−5)=5

It is hour \(5\), which is 5 am, in the second city.

Common pitfalls

Two negatives added stay negative. \(-4 + (-3) = -7\), not \(7\). Both jumps go left.
Wrong sign with different signs. \(-9 + 4 = -5\), not \(5\), because \(9\) is bigger than \(4\).
Ignoring the brackets. \(3 + (-8)\) means add negative \(8\), so jump left: \(-5\).
Forgetting opposites cancel. \(-7 + 7 = 0\). A number and its opposite add to zero.

Frequently asked questions

What happens when you add a negative number?

It is the same as subtracting. \(3 + (-8) = 3 - 8 = -5\).

What is the rule for adding two negatives?

Add the sizes and keep the negative sign. \(-5 + (-4) = -9\).

What if the signs are different?

Subtract the sizes and use the sign of the larger size. \(-13 + 5 = -8\).

What do a number and its opposite add to?

Zero. \(-7 + 7 = 0\).

How do you find a missing number in a sum?

Find the jump from the known total to the answer. From \(-8\) to \(3\) is \(11\) right, so the missing number is \(11\).