Resources For Teachers For Tutors For Students & Parents Pricing
Year 12 Maths Standard 1 (2027) Relative frequency and probability

Complementary Events

20 practice questions 0 video lessons Theory + worked examples

Learn about complementary events for NSW Year 12 Mathematics Standard 1 (NESA outcome MST-12-S1-07). An event’s complement is that event not happening — and since the two together cover every outcome, their probabilities add to 1.

You will use the rule \(P(\text{not } A) = 1 - P(A)\) to find the chance that something does not happen, working with fractions, decimals and percentages, and answer “not” and “at least one” questions quickly — such as the chance a flight is not delayed.

Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

Complementary events are an event and its opposite, “not \(A\)”. This Year 12 Standard 1 (NSW) guide shows how the rule \(P(\text{not }A)=1-P(A)\) works with fractions, decimals and percentages, and how to solve “neither” and “at least one” questions quickly.

The complement of an event \(A\) is the event “\(A\) does not happen”, written “not \(A\)”. Every outcome is either in \(A\) or in not \(A\), never both.

Because an event and its complement cover every outcome with no overlap, their probabilities add to \(1\). So \(P(\text{not }A)=1-P(A)\), and also \(P(A)=1-P(\text{not }A)\).

Two events are complementary when together they fill the whole sample space with no overlap, e.g. “even” \(\{2,4,6\}\) and “odd” \(\{1,3,5\}\) on a die. Use the complement when “not” is quicker to find: “at least one” is the complement of “none”.

An event and its complement on the probability scaleP(A) = 0.28 and P(not A) = 0.72 fill the whole bar from 0 to 1.whole sample space: probability 1P(A)P(not A)00.280.51P(not A) = 1 βˆ’ 0.28 = 0.72
An event and its complement split the scale from \(0\) to \(1\): whatever \(A\) does not take, not \(A\) takes.
Complementary and not complementary events on a dieEven and odd fill all six faces with no overlap. Less than 3 and more than 3 leave the 3 out.even and odd: complementary123456less than 3 and more than 3: not complementary1234563 is left out
Even and odd are complementary. “Less than \(3\)” and “more than \(3\)” are not — the \(3\) is missing.

An event and its complement add to \(1\):

\[P(A)+P(\text{not }A)=1\]
P(A)+P(not A)=1

Rearranged, this is the complement rule:

\[P(\text{not }A)=1-P(A)\qquad P(A)=1-P(\text{not }A)\]
P(not A)=1−P(A)

With fractions, write \(1\) as a matching fraction: \(1-\dfrac{1}{6}=\dfrac{6}{6}-\dfrac{1}{6}=\dfrac{5}{6}\). With decimals subtract from \(1\) (\(1-0.3=0.7\)); with percentages subtract from \(100\%\) (\(100\%-8\%=92\%\)).

\[P(\text{at least one})=1-P(\text{none})\]
P(at least one)=1−P(none)
Neither. “Neither \(A\) nor \(B\)” is \(1-P(A\text{ or }B)\). When \(A\) and \(B\) cannot both happen, first add \(P(A)+P(B)\), then subtract from \(1\).

How to use the complement

  1. Name the event and its complement. For “at least one”, the complement is “none”.
  2. Find the probability that is easier to work out, as a fraction, decimal or percentage.
  3. Subtract from \(1\) (or from \(100\%\)), and check the two probabilities add back to \(1\).
Example 1 β€” Letters of a word
Each letter of the word PARRAMATTA is written on a card and one card is drawn at random. Find the probability that the card is not an A.
Solution

Count the letters and the A’s, find \(P(\text{A})\), then take the complement.

\(n(S)\)\(=\)\(10\)
\(n(\text{A})\)\(=\)\(4\)
\(P(\text{A})\)\(=\)\(\dfrac{4}{10}=\dfrac{2}{5}\)
\(P(\text{not A})\)\(=\)\(1-\dfrac{2}{5}\)
\(\)\(=\)\(\dfrac{5}{5}-\dfrac{2}{5}=\dfrac{3}{5}\)
1−25=35

\(P(\text{not A})=\dfrac{3}{5}\).

Example 2 β€” Decimals, both ways
(i) The probability that a train is late is \(0.12\). Find the probability that it is not late.
(ii) On another line, \(P(\text{not late})=0.93\). Find \(P(\text{late})\).
Solution

The two probabilities add to \(1\), so subtract from \(1\) each time.

\(\text{(i) }P(\text{not late})\)\(=\)\(1-0.12=0.88\)
\(\text{(ii) }P(\text{late})\)\(=\)\(1-P(\text{not late})\)
\(\)\(=\)\(1-0.93=0.07\)
1−0.12=0.88

(i) \(0.88\)   (ii) \(0.07\)

Example 3 β€” Neither, with percentages
In a crate of fruit, \(30\%\) are apples, \(45\%\) are oranges and the rest are pears. One piece is taken at random. Find the probability, as a percentage, that it is (i) not an orange (ii) neither an apple nor an orange.
Solution

Percentages add to \(100\%\), so subtract from \(100\%\).

\(\text{(i) }P(\text{not orange})\)\(=\)\(100\%-45\%=55\%\)
\(\text{(ii) }P(\text{apple or orange})\)\(=\)\(30\%+45\%=75\%\)
\(P(\text{neither})\)\(=\)\(100\%-75\%=25\%\)
100%−75%=25%

(i) \(55\%\)   (ii) \(25\%\)

Example 4 β€” At least one
Two fair dice are rolled, giving \(36\) equally likely outcomes. Find the probability of at least one even number.
Solution

The complement of “at least one even” is “no even”, i.e. both dice odd. Each die has \(3\) odd faces, so \(3\times3=9\) of the \(36\) outcomes are odd–odd.

\(n(\text{no even})\)\(=\)\(3\times3=9\)
\(P(\text{no even})\)\(=\)\(\dfrac{9}{36}=\dfrac{1}{4}\)
\(P(\text{at least one even})\)\(=\)\(1-\dfrac{1}{4}=\dfrac{3}{4}\)
1−14=34

\(P(\text{at least one even})=\dfrac{3}{4}\).

Common pitfalls

Subtract from 1 (or 100%), not from the number of outcomes. \(P(\text{rain})=0.4\) gives \(P(\text{no rain})=0.6\), never \(100-0.4\): subtract a decimal from \(1\) and a percentage from \(100\%\).
“At least one” pairs with “none”. Its complement is “none”, not “exactly one”. For “neither \(A\) nor \(B\)”, add \(P(A)+P(B)\) first (when they cannot both happen), then subtract from \(1\).
Watch for events that leave something out. On a die, “less than \(3\)” and “more than \(3\)” are not complementary — the \(3\) is missing.

Frequently asked questions

What is a complementary event?

The complement of an event A is the event that A does not happen, written not A. Together A and not A cover every outcome with no overlap, so their probabilities add to 1.

What is the formula for the complement of an event?

P(not A) = 1 minus P(A). With percentages it is 100 percent minus P(A). For example, a 0.12 chance of a late train gives a 0.88 chance it is not late.

How do you find the probability of at least one?

Find the probability of none, then subtract it from 1. For two dice, the chance of no even number is 9 over 36, which is 1 quarter, so the chance of at least one even number is 3 quarters.

How do you find the probability of neither A nor B?

Add P(A) and P(B) when they cannot both happen, then subtract from 1. If 30 percent are apples and 45 percent are oranges, then 25 percent are neither.

Are even and odd complementary events?

Yes. On a die, even is {2, 4, 6} and odd is {1, 3, 5}. Together they cover all six outcomes with no overlap, so P(even) + P(odd) = 1.

Do P(A) and P(not A) always add to 1?

Yes. An event and its complement include every outcome in the sample space exactly once, so their probabilities always add to 1, or 100 percent.