Resources For Teachers For Tutors For Students & Parents Pricing
Year 12 Maths Standard 1 (2027) Algebraic relationships

Exponential Graphs of Practical Situations

20 practice questions 0 video lessons Theory + worked examples

Explore exponential graphs of practical situations for NSW Year 12 Mathematics Standard 1 (NESA outcome MST-12-S1-01). When an amount is multiplied by the same number each step — doubling, tripling or halving — its graph is a curve, not a straight line, like algae spreading across a pond.

You will draw an exponential graph from a table of values, find the starting value and the multiplier, tell growth from decay, and read the graph to make predictions — for example bacteria in a dish, an online post spreading, or a medicine leaving the body.

Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

When a quantity is multiplied by the same number each step β€” doubling, tripling or halving β€” it is exponential. This NSW Year 12 Mathematics Standard 1 guide shows how to find the multiplier, read growth and decay curves, and tell exponential patterns from linear ones.

In an exponential situation the amount is multiplied by the same number each step β€” it doubles, triples or halves each hour, day or year. Plotting a table of values gives a smooth curve, not a straight line.

The starting value is the amount at time 0, where the curve meets the vertical axis. The number you multiply by each step is the multiplier.

Growth (multiplier more than 1, such as doubling) makes the curve rise more and more steeply. Decay (multiplier less than 1, such as halving) makes the curve fall, then flatten towards 0 β€” it gets closer and closer to 0 but never reaches it.

Exponential growth7 bacteria doubling each hour: 7, 14, 28, 56, 112, a curve rising faster and faster t N 1 2 3 4 20 40 60 80 100 120 7 28 56 112
Growth, \(\times 2\) each hour: 7, 14, 28, 56, 112 β€” rising faster and faster.
Exponential decay96 mg halving each hour: 96, 48, 24, 12, 6, 3, a curve falling and levelling off towards 0 t M 1 2 3 4 5 20 40 60 80 100 96 48 24 12
Decay, \(\div 2\) each hour: 96, 48, 24, 12, 6, 3 β€” falling towards 0.

Each step multiplies by the same number:

\[\text{next value} = \text{previous value} \times \text{multiplier}\]
next value=previous valueΓ—multiplier

Table test β€” divide each value by the one before it:

\[\text{multiplier} = \dfrac{\text{value}}{\text{previous value}}\]
multiplier=valueprevious value
\(t\)012345
Growth \(N\) (\(\times 2\))7142856112
Decay \(M\) (\(\div 2\))9648241263
Linear or exponential? Linear tables add the same amount each step; exponential tables multiply by the same number each step.

How to work with an exponential situation

  1. Find the starting value at time 0 (divide back if you only know later values).
  2. Test the table: divide each value by the one before. The same answer each time is the multiplier.
  3. Predict by continuing to multiply (or divide) step by step, or read across and down on the curve.
  4. Describe the graph: growth rises more and more steeply; decay falls and flattens towards 0.
Example 1 β€” Find the multiplier
Is the pattern exponential? Find the multiplier and the next value.
\(x\)01234
\(y\)41236108?
Solution

Divide each value by the one before.

\(12\div 4\)\(=\)\(3\)
\(36\div 12\)\(=\)\(3\)
\(108\div 36\)\(=\)\(3\)
\(y\)\(=\)\(108\times 3=324\)
108Γ—3=324

Same multiplier, so the pattern is exponential (growth). Multiplier 3; the missing value is 324.

Example 2 β€” Read a growth curve
Mould covers 5 cm\(^2\) of a loaf and the area doubles each day. The graph shows the area \(A\) after \(t\) days. (a) Find the area after 4 days. (b) After how many days is the area 40 cm\(^2\)?
Solution

Keep doubling from the start. For (b), go across from 40 to the curve, then down.

Example 2Mould area doubling from 5: 40 square cm at day 3 and 80 at day 4 t A 1 2 3 4 20 40 60 80
\(\text{day } 0,1,2,3,4\)\(\colon\)\(5,\ 10,\ 20,\ 40,\ 80\)
5,10,20,40,80

(a) 80 cm\(^2\); (b) after 3 days.

Example 3 β€” Read a decay curve
A patient takes 200 mg of a medicine. The amount \(M\) in the body halves each hour. (a) How much is left after 3 hours? (b) After 4 hours? (c) Describe the graph.
Solution

Keep halving from the start.

Example 3Medicine halving from 200 mg: 100, 50, 25, 12.5 t M 1 2 3 4 5 25 50 100 150 200
\(t=1\colon\ M\)\(=\)\(200\div 2=100\)
\(t=2\colon\ M\)\(=\)\(100\div 2=50\)
\(t=3\colon\ M\)\(=\)\(50\div 2=25\)
\(t=4\colon\ M\)\(=\)\(25\div 2=12.5\)
25Γ·2=12.5

(a) 25 mg; (b) 12.5 mg; (c) a curve that falls and flattens towards 0 (exponential decay).

Example 4 β€” Linear or exponential?
Which table is linear and which is exponential? Predict the next value in each.
\(t\)0123
Table A25811
Table B261854
Solution

A: \(5-2=8-5=11-8=3\), the same amount is added. B: \(6\div 2=18\div 6=54\div 18=3\), the same multiplier.

Example 4Table A (2, 5, 8, 11) lies on a straight line; table B (2, 6, 18, 54) curves upwards t y 1 2 3 10 20 30 40 50 60 A B
\(\text{A next}\)\(=\)\(11+3=14\)
\(\text{B next}\)\(=\)\(54\times 3=162\)
54Γ—3=162

A is linear (next 14); B is exponential (next 162).

Common pitfalls

Doubling means \(\times 2\), not \(+2\). 7, 14, 28, 56 β€” not 7, 9, 11, 13.
The starting value is at time 0. If you only know later values, halve (or divide) back: \(28\to 14\to 7\).
An exponential curve is not a straight line. Equal time steps do not give equal jumps, so read the curve carefully against the grid.

Frequently asked questions

What is an exponential graph in real life?

It shows an amount that is multiplied by the same number each step, such as bacteria doubling each hour or a medicine halving each hour. The graph is a curve, not a straight line.

How do you tell if a table is exponential or linear?

Divide each value by the one before it. If you get the same answer each time, the table is exponential and that answer is the multiplier. If instead the same amount is added each time, it is linear.

What is the difference between exponential growth and decay?

In growth the multiplier is more than 1, so the curve rises more and more steeply. In decay the multiplier is less than 1, so the curve falls and levels off towards 0.

Does exponential decay ever reach zero?

No. Halving keeps making the amount smaller, so the curve gets closer and closer to 0 but never reaches it or goes below it.

How do you find the starting value of an exponential pattern?

The starting value is the amount at time 0, where the curve meets the vertical axis. If you only know later values, divide back by the multiplier, for example 28, then 14, then 7.