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Year 12 Maths Extension 1 (2027) Vectors

Operating with vectors in two dimensions

20 practice questions 2 video lessons Theory + worked examples

Learn operating with vectors in two dimensions for NSW Year 12 Mathematics Extension 1 (NESA outcome ME1-12-02). Vectors can be scaled, added and subtracted, combining geometric quantities such as displacements and velocities into a single resultant.

You will learn scalar multiplication, addition and subtraction using the triangle and parallelogram laws, how to test whether two vectors are parallel, and how to find a unit vector in a given direction β€” essential vector operations used across Extension 1.

Practice 20 questions
Practice questions

Every question with a fully worked solution.

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Watch 2 video(s)
  • Are The Two Vectors Parallel, Orthogonal, or Neither? Watch
  • Parallel and Perpendicular Vectors with Worked Examples Watch
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Theory

Vectors add and subtract componentwise and scale by a scalar. Two vectors are parallel when a=kb, and ai+bj is perpendicular to βˆ’bi+aj. This NSW Year 12 Mathematics Extension 1 topic is NESA outcome ME1-12-02.

Vectors are added or subtracted componentwise, and scaled by multiplying each component by a scalar. For a=x1i+y1j, b=x2i+y2j and scalar k:

aΒ±b=(x1Β±x2)i+(y1Β±y2)j,ka=kx1i+ky1j.

Two non-zero vectors are parallel when a=kb for some scalar k (proportional components). A vector perpendicular to ai+bj is βˆ’bi+aj β€” swap the components and negate one.

NESA link. Part of the Year 12 Introduction to vectors focus area, outcome ME1-12-02 ("operates with 2D and 3D vectors and uses 2D vectors to solve problems involving motion in two dimensions") with MAO-WM-01.

Parallelogram law of additionVectors a and b from a common point, with a plus b the diagonal of the parallelogram they span.aba + b
Addition follows the triangle or parallelogram law.
Scalar multiples of a vectorThe vector a, its double 2a in the same direction, and its negative minus a in the opposite direction.2aaβˆ’a
ka stretches a for k>0 and reverses it for k<0.
aβˆ₯b⟺a=kb⟺x1x2=y1y2,ai+bj βŠ₯ βˆ’bi+aj.
parallel: a = k b (proportional components); perpendicular: swap and negate

Componentwise. Add i with i and j with j; a scalar multiplies every component.

How to operate with vectors

  1. Add or subtract matching components.
  2. Scale by multiplying each component by the scalar.
  3. Test parallel: check the components are proportional, or a=kb.
  4. Build a perpendicular: swap the components and negate one.
Example 1 β€” Linear combination
If a=3iβˆ’j and b=2i+4j, find 2a+3b.
Solution
2a=6iβˆ’2j
3b=6i+12j
2a+3b=12i+10j
2a + 3b = 12i + 10j

2a+3b=12i+10j.

Example 2 β€” Parallel
Find k so that 6i+kj is parallel to 3iβˆ’2j.
Solution

Components must be proportional.

63=kβˆ’2β‡’2=kβˆ’2β‡’k=βˆ’4
k = -4

k=βˆ’4.

Example 3 β€” Perpendicular
Find a vector perpendicular to 5i+2j.
Solution

Swap the components and negate one.

5i+2jβ†’βˆ’2i+5j
perpendicular: -2i + 5j (or 2i - 5j)

For example, βˆ’2i+5j (or 2iβˆ’5j).

Example 4 β€” Subtract and test
Let a=2i+3j, b=iβˆ’4j. Find aβˆ’b and state whether aβˆ₯b.
Solution
aβˆ’b=(2βˆ’1)i+(3+4)j=i+7j

Parallel? 21β‰ 3βˆ’4, so no.

a - b = i + 7j; not parallel

aβˆ’b=i+7j; not parallel.

Common pitfalls

Mixing components. Add i with i and j with j, never across.
Parallel test. Parallel means proportional components (x1x2=y1y2), or a=kb.
Perpendicular sign. Swap the components and negate exactly one: ai+bjβ†’βˆ’bi+aj.
Sign of the scalar. A negative scalar reverses the direction as well as scaling the length.

Frequently asked questions

How do you add vectors in component form?

Add matching components: i with i, j with j.

How do you multiply a vector by a scalar?

Multiply every component by the scalar; a negative scalar reverses direction.

How do you tell if two vectors are parallel?

They are parallel when a=kb, i.e. their components are proportional.

How do you find a perpendicular vector?

Swap the components and negate one: ai+bjβ†’βˆ’bi+aj.

What does a scalar multiple look like?

ka stretches a for k>0 and reverses it for k<0.