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Primary - Stage 3 (Year 5 & 6) Stage 3 (Year 5 & 6) Length, Perimeter & Area

Area of composite figures

20 practice questions 0 video lessons Theory + worked examples
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Theory

A composite figure is built from simpler shapes. Split it into rectangles, find each area with \(\text{length} \times \text{width}\), then add them — or surround it and subtract the missing part.

A composite figure is made from simpler shapes joined together. An L-shape, for example, is two rectangles joined at an edge.

To find its area, split it into rectangles with a straight line. Find each area using \(\text{length} \times \text{width}\).

Then add the areas. Because the pieces do not overlap, the parts add up to the whole.

Sometimes it is easier to start with a large rectangle and subtract a missing corner.

An L-shaped figure split into two rectangles An L-shape split by a dashed line into a bottom rectangle 7 cm by 2 cm labelled A one and a top rectangle 4 cm by 3 cm labelled A two. The two areas add to 26 square centimetres. 7 cm 2 cm 5 cm 4 cm A₁ A₂
\(A_1 = 7 \times 2 = 14\) and \(A_2 = 4 \times 3 = 12\). The total area is \(14 + 12 = 26\,\text{cm}^2\).

There are two ways to reach the same answer.

MethodWhat you do
Split and addcut into rectangles, add the areas
Surround and subtracttake a big rectangle, subtract the missing part
Watch the hidden lengths. A side that is not marked is often the difference between two sides that are.

How to find the area of a composite figure

  1. Split the figure into rectangles with a straight line.
  2. Work out any missing side lengths from the ones you are given.
  3. Find each area with length times width, then add them.
Example 1 — Split the L
An L splits into a \(7 \times 2\) rectangle and a \(4 \times 3\) rectangle. Find the total area.
Solution
\(7 \times 2 + 4 \times 3\)\(=\)\(14 + 12\)
\(=\)\(26\,\text{cm}^2\)
Example 2 — Choose the calculation
An L splits into a \(6 \times 2\) rectangle and a \(4 \times 2\) rectangle. Find its area.
Solution
\(6 \times 2 + 4 \times 2\)\(=\)\(12 + 8\)
\(=\)\(20\,\text{cm}^2\)
Example 3 — Two rectangles
A figure splits into a \(9 \times 3\) rectangle and a \(5 \times 3\) rectangle. Find the total area.
Solution
\(9 \times 3 + 5 \times 3\)\(=\)\(27 + 15\)
\(=\)\(42\,\text{cm}^2\)
Example 4 — Subtract a corner
A \(6 \times 4\) rectangle has a \(2 \times 2\) corner cut out. Find the area left.
Solution
\(6 \times 4 - 2 \times 2\)\(=\)\(24 - 4\)
\(=\)\(20\,\text{cm}^2\)

Common pitfalls

Missing a hidden length. An unmarked side is usually the difference of two given sides.
Double-counting. Split the figure into pieces that do not overlap, and add each area once.
Adding lengths instead of areas. Find each rectangle's area first, then add the areas.

Frequently asked questions

What is a composite figure?

A composite figure is a shape made from simpler shapes joined together, such as an L-shape built from two rectangles.

How do you find the area of an L-shape?

Split it into two rectangles, find each area with length times width, then add the two areas together.

How do I find a missing side length?

A missing side is often the difference of two given sides. For example, if the full height is \(5\,\text{cm}\) and part is \(2\,\text{cm}\), the rest is \(3\,\text{cm}\).

Can I subtract instead of adding?

Yes. You can take the area of a large surrounding rectangle and subtract the area of the missing corner. Both methods give the same answer.

Why do the parts add up to the whole?

The pieces do not overlap and cover the whole figure with no gaps, so their areas add up to the total area.