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Year 5 Maths Multiplication

Distributive property in multiplication

20 practice questions 0 video lessons Theory + worked examples
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Theory

The distributive property lets you split one factor into parts, multiply each part, then add the results: \(8 \times 36 = 8 \times 30 + 8 \times 6\). It also works with subtraction, which is handy for numbers just below a hundred: \(4 \times 99 = 4 \times 100 - 4 \times 1\). This Year 5 maths page explains both, with area-model pictures, word problems and common mistakes.

The distributive property says that multiplying a sum is the same as multiplying each part and adding: \(8 \times (30 + 6) = 8 \times 30 + 8 \times 6\).

Splitting by place value uses tens and ones: \(58 = 50 + 8\). You can also use any split that is easy, such as \(28 = 14 + 14\).

Numbers just below a round number are split with subtraction: \(98 = 100 - 2\), so \(6 \times 98 = 6 \times 100 - 6 \times 2\).

Every part must be multiplied. \(4 \times 73\) is \(4 \times 70 + 4 \times 3\), not \(4 \times 70 + 3\).

Area model for 8 times 36 A rectangle 36 wide and 8 tall split into parts: 8 times 30 is 240, 8 times 6 is 48. Together they make 288. 8 240 30 48 6
\(8 \times 36 = 8 \times 30 + 8 \times 6 = 240 + 48 = 288\).
Area model for 6 times 98 as 6 times 100 minus 6 times 2 A rectangle 6 by 100 with area 600. A strip 6 by 2 of area 12 at the end is removed, leaving 6 times 98, which is 588. 6 600 100 −12
\(6 \times 98 = 600 - 12 = 588\): take a \(6 \times 2\) strip off \(6 \times 100\).

The distributive property with addition and subtraction:

\[ a \times (b + c) = a \times b + a \times c \]
a ×( b + c )= a × b + a × c
\[ a \times (b - c) = a \times b - a \times c \]
a ×( b − c )= a × b − a × c
\[ 8 \times 36 = 240 + 48 = 288 \]
8×36=288
\[ 4 \times 99 = 400 - 4 = 396 \]
4×99=396
Any split works. Splitting \(28\) as \(20 + 8\) or \(14 + 14\) gives the same answer for \(7 \times 28\). Choose the split that is easiest.
Near a hundred? For \(99\), \(98\) or \(199\), multiply by the round number and subtract the small extra.

Split and add

  1. Split the larger factor into tens and ones.
  2. Multiply each part by the other factor.
  3. Add the partial products.

Round and subtract

  1. Round the factor up to a friendly number, such as \(100\).
  2. Multiply by the friendly number.
  3. Subtract the other factor times the amount you rounded by.
Example 1 — Split by place value
Work out \(8 \times 36\).
Solution
\(8 \times 30\)\(=\)\(240\)
\(8 \times 6\)\(=\)\(48\)
\(240 + 48\)\(=\)\(288\)
8×36=288

\(8 \times 36 = 288\).

Example 2 — Missing number
Complete \(6 \times 58 = 6 \times 50 + 6 \times \square\), then find the answer.
Solution
\(6 \times 50\)\(=\)\(300\)
\(6 \times 8\)\(=\)\(48\)
\(300 + 48\)\(=\)\(348\)
6×58=348

The box is \(8\), and \(6 \times 58 = 348\).

Example 3 — Multiplying by 99
Work out \(4 \times 99\).
Solution
\(4 \times 100\)\(=\)\(400\)
\(4 \times 1\)\(=\)\(4\)
\(400 - 4\)\(=\)\(396\)
4×99=396

\(4 \times 99 = 396\).

Example 4 — Near a hundred
Work out each product.
(i) \(6 \times 98\)
(ii) \(3 \times 199\)
Solution
\(600 - 12\)\(=\)\(588\)
\(600 - 3\)\(=\)\(597\)
6×98=588

(i) \(6 \times 100 - 6 \times 2 = 588\).
(ii) \(3 \times 200 - 3 \times 1 = 597\).

Example 5 — Two different splits
Work out \(7 \times 28\) by splitting \(28\) as \(20 + 8\), then as \(14 + 14\).
Solution
\(140 + 56\)\(=\)\(196\)
\(98 + 98\)\(=\)\(196\)
7×28=196

Both splits give \(196\), because both pairs of parts add to \(28\).

Example 6 — Word problem
Tickets cost \(\$15\) each. A class buys \(24\) tickets. What is the total cost?
Solution
\(15 \times 20\)\(=\)\(300\)
\(15 \times 4\)\(=\)\(60\)
\(300 + 60\)\(=\)\(360\)
15×24=360

The total cost is \(\$360\).

Example 7 — Find the mistake
Eli worked out \(4 \times 73\) as \(4 \times 70 + 3\) and got \(283\). What is wrong?
Solution
\(4 \times 70\)\(=\)\(280\)
\(4 \times 3\)\(=\)\(12\)
\(280 + 12\)\(=\)\(292\)
4×73=292

Eli did not multiply the \(3\) by \(4\). The answer is \(292\).

Common pitfalls

Not multiplying every part. \(4 \times 73\) needs \(4 \times 3\), not just \(3\).
Subtracting the wrong amount. \(6 \times 98 = 600 - 6 \times 2 = 588\). Subtracting just \(2\) gives \(598\), which is wrong.
Splitting into digits. \(58\) is \(50 + 8\), not \(5 + 8\).
Adding when you should subtract. When you round up to a friendly number, you subtract the extra.

Frequently asked questions

What is the distributive property?

Multiplying a sum is the same as multiplying each part and adding. \(8 \times 36 = 8 \times 30 + 8 \times 6 = 288\).

How do you multiply by 99 in your head?

Multiply by \(100\), then subtract one lot of the number. \(4 \times 99 = 400 - 4 = 396\).

Does it matter how I split the number?

No. Any parts that add to the number give the same answer. \(7 \times 28\) is \(196\) whether you split \(28\) as \(20 + 8\) or \(14 + 14\).

Can you use subtraction with the distributive property?

Yes. \(6 \times 98 = 6 \times 100 - 6 \times 2 = 588\).

Why is the distributive property useful?

It turns a hard multiplication into easy ones you can do in your head.