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Year 7 Maths Geometry

Angle Sum of a Triangle

20 practice questions 1 video lesson Theory + worked examples
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Theory

The three angles inside any triangle add to \(180^\circ\). This is the angle sum of a triangle. To find a missing angle, add the angles you know and subtract from \(180^\circ\). This Year 7 maths page shows why the rule works and how to use it with right angles, isosceles triangles, straight lines and pronumerals.

For a triangle with angles \(a^\circ\), \(b^\circ\) and \(c^\circ\): \(a + b + c = 180\). Reason: angle sum of a triangle is \(180^\circ\).

Finding a missing angle. Write the equation with its reason, add the known angles, then subtract from \(180\): \(x + 70 + 45 = 180\), so \(x = 180 - 115 = 65\).

Special triangles. Right-angled: the right angle is \(90^\circ\), so the other two angles add to \(90^\circ\). Isosceles: the two base angles are equal, so call both \(x^\circ\). Equilateral: each angle is \(60^\circ\).

Why it is true. Draw a line \(DE\) through \(A\) parallel to \(BC\). Alternate angles on parallel lines are equal, so the angles of the triangle can be copied to \(A\). There they make a straight line, which is \(180^\circ\).

Other angle facts still work. Angles on a straight line add to \(180^\circ\), vertically opposite angles are equal, and angles on parallel lines (alternate, corresponding, co-interior) can give an angle inside the triangle first.

Why the angles of a triangle add to 180 degrees Triangle ABC with line DE drawn through A parallel to BC. The angle a at B equals angle DAB, the angle b at C equals angle EAC, and the three angles at A make a straight line. a° b° c° a° b° A B C D E
\(DE \parallel BC\). \(\angle DAB = a^\circ\) and \(\angle EAC = b^\circ\) (alternate angles, \(DE \parallel BC\)). The three angles at \(A\) make the straight line \(DE\), so \(a + c + b = 180\).
Right-angled triangle: the other two angles add to 90 degrees A right-angled triangle with angles of 90, 56 and 34 degrees. 56° 34°
In a right-angled triangle the two other angles add to \(90^\circ\): \(56 + 34 = 90\). Each one is acute.

The rule, and what it gives for special triangles:

\[ a + b + c = 180 \quad (\text{angle sum of a triangle}) \]
a + b + c =180( angle sum of a triangle )
TriangleFact
right-angledthe other two angles add to \(90^\circ\)
isoscelesbase angles equal: \(x + x + \text{top} = 180\)
equilateraleach angle is \(60^\circ\)
Exactly 180 degrees. \(40^\circ\), \(60^\circ\) and \(90^\circ\) cannot be the angles of a triangle, because \(40 + 60 + 90 = 190\).
Count the right angle. A right-angle mark is \(90^\circ\) even though no number is written.

How to find a missing angle in a triangle

  1. Find any angle you need first (a straight line, a right angle, equal base angles).
  2. Write the equation: the three angles \(= 180\), with the reason.
  3. Add the known angles and subtract from \(180\).
  4. Check that the three angles add to \(180\).

How to solve when the angles have pronumerals

  1. Add the three angles and make them equal to \(180\).
  2. Collect like terms, then solve for the pronumeral.
  3. Substitute back to find each angle.
Example 1 — Find the third angle
Find the value of \(x\).
Triangle with angles 38, 103 and x degrees A triangle with angles of 38 degrees at the left, x degrees at the right and 103 degrees at the top. 38° x° 103°
Solution
\(x + 38 + 103\)\(=\)\(180\)
\(x + 141\)\(=\)\(180\)
\(x\)\(=\)\(180 - 141\)
\(\)\(=\)\(39\)
x +38+103=180, x =180−141=39

\(x = 39\) (angle sum of a triangle is \(180^\circ\)). Check: \(39 + 38 + 103 = 180\).

Example 2 — Angles named with letters
In \(\triangle ABC\), \(\angle BAC = 61^\circ\) and \(\angle ACB = 58^\circ\). Find the value of \(x\).
Triangle ABC with angles 61 and 58 degrees Triangle ABC: angle A is 61 degrees, angle C is 58 degrees, angle B is x. 61° 58° x A B C
Solution
\(x + 61 + 58\)\(=\)\(180\)
\(x + 119\)\(=\)\(180\)
\(x\)\(=\)\(61\)
x +61+58=180, x +119=180, x =61

\(x = 61\), so \(\angle ABC = 61^\circ\). Two angles are equal, so the triangle is isosceles.

Example 3 — The front of a tent
The two sloping sides of a tent are equal and meet at \(52^\circ\) at the top. Find \(x\), the angle each side makes with the ground.
Tent front: isosceles triangle with top angle 52 degrees An isosceles triangle with equal sloping sides meeting at 52 degrees at the top; both base angles are x degrees. 52° x° x°
Solution

The triangle is isosceles, so both base angles are \(x^\circ\).

\(x + x + 52\)\(=\)\(180\)
\(2x\)\(=\)\(128\)
\(x\)\(=\)\(64\)
x + x +52=180,2 x =128, x =64

\(x = 64\). Check: \(64 + 64 + 52 = 180\).

Example 4 — Which angle is 30 degrees?
An isosceles triangle has one angle of \(30^\circ\).
(i) If the \(30^\circ\) angle is between the two equal sides, find each base angle.
(ii) If the \(30^\circ\) angle is a base angle, find the third angle.
Solution
\(180 - 30\)\(=\)\(150\)
\(150 \div 2\)\(=\)\(75\)
\(180 - 30 - 30\)\(=\)\(120\)
180−30=150,150÷2=75180−30−30=120

(i) \(75^\circ\) each
(ii) \(120^\circ\)

Example 5 — Straight line first
In \(\triangle ABC\), \(\angle ABC = 70^\circ\). \(BC\) is extended to \(D\) and \(\angle ACD = 110^\circ\). Find the size of \(\angle BAC\).
Triangle ABC with BC extended to D Triangle ABC with BC extended to D. Angle ABC is 70 degrees and angle ACD outside the triangle is 110 degrees. 70° 110° A B C D
Solution
\(\angle ACB + 110^\circ\)\(=\)\(180^\circ\)
\(\angle ACB\)\(=\)\(70^\circ\)
\(\angle BAC + 70^\circ + 70^\circ\)\(=\)\(180^\circ\)
\(\angle BAC\)\(=\)\(40^\circ\)
ACB +110=180, ACB =70 BAC +70+70=180, BAC =40

\(\angle BAC = 40^\circ\). The first step uses angles on a straight line; the second uses the angle sum of a triangle.

Example 6 — A ladder against a wall
A ladder leans against a vertical wall and makes \(63^\circ\) with the flat ground. Find the angle between the ladder and the wall.
Solution

The wall, the ground and the ladder make a right-angled triangle, so the two other angles add to \(90^\circ\).

\(90 - 63\)\(=\)\(27\)
90−63=27

\(27^\circ\)

Example 7 — Angles with pronumerals
Find \(x\), then the size of each angle. Classify the triangle by its angles.
Triangle with angles 55, 2x and 3x degrees A triangle with angles of 55 degrees, (2x) degrees and (3x) degrees. (2x)° (3x)° 55°
Solution
\(2x + 3x + 55\)\(=\)\(180\)
\(5x\)\(=\)\(125\)
\(x\)\(=\)\(25\)
2 x +3 x +55=180,5 x =125, x =25

\(x = 25\). The angles are \(50^\circ\), \(75^\circ\) and \(55^\circ\) (check: \(50 + 75 + 55 = 180\)). The largest is \(75^\circ\), so the triangle is acute-angled.

Common pitfalls

Using 360 degrees. \(360^\circ\) is for a quadrilateral or a full turn. A triangle is \(180^\circ\).
Forgetting the right angle. Include the \(90^\circ\) in the sum.
The wrong base angles. In an isosceles triangle the equal angles are opposite the equal sides. The angle where the two ticked sides meet is not a base angle.
An angle outside the triangle. If the angle given is outside, first find the inside angle with angles on a straight line.

Frequently asked questions

What do the angles of a triangle add up to?

\(180^\circ\), for every triangle.

How do you find the third angle of a triangle?

Add the two angles you know and subtract from \(180\). For \(38^\circ\) and \(103^\circ\): \(180 - 141 = 39\), so the third angle is \(39^\circ\).

Why do the angles of a triangle add to 180 degrees?

Draw a line through one vertex parallel to the opposite side. Alternate angles copy the other two angles to that vertex, where the three angles make a straight line.

What are the angles of a right-angled isosceles triangle?

\(90^\circ\), \(45^\circ\) and \(45^\circ\).

Can a triangle have two right angles?

No. Two right angles already make \(180^\circ\), leaving nothing for the third angle.