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Year 7 Maths Geometry

Angle Sum of a Quadrilateral

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Theory

The four angles inside any quadrilateral add to \(360^\circ\). This is the angle sum of a quadrilateral. To find a missing angle, add the angles you know and subtract from \(360^\circ\). This Year 7 maths page shows why, and uses the rule with right angles, reflex angles, special quadrilaterals and pronumerals.

For a quadrilateral with angles \(a^\circ\), \(b^\circ\), \(c^\circ\) and \(d^\circ\): \(a + b + c + d = 360\). Reason: angle sum of a quadrilateral is \(360^\circ\).

Why \(360^\circ\)? A diagonal splits any quadrilateral into two triangles. Each triangle has an angle sum of \(180^\circ\), and together the six triangle angles fill the four corners exactly: \(180 + 180 = 360\). This works for a non-convex quadrilateral too, using the diagonal from the reflex angle.

Finding a missing angle. Write the equation and its reason, add the known angles, then subtract from \(360\): \(a + 95 + 120 + 80 = 360\), so \(a = 360 - 295 = 65\).

Special quadrilaterals give more facts. In a parallelogram opposite angles are equal, and angles next to each other are co-interior, so they add to \(180^\circ\). In a kite the two angles between the unequal sides are equal. In an isosceles trapezium the two angles on each parallel side are equal.

The reflex angle counts. In a non-convex quadrilateral the angle at the dent is more than \(180^\circ\). It is one of the four angles.

A diagonal splits a quadrilateral into two triangles Quadrilateral ABCD with diagonal AC dashed. Angles a and b at A, c at B, d and e at C, f at D. b a c d e f A B C D
\(\triangle ABC\) (blue) and \(\triangle ACD\) (purple) each add to \(180^\circ\): \(b + c + d = 180\) and \(a + e + f = 180\). Together \(a + b + c + d + e + f = 360\), and these six angles make the four corners.
Non-convex quadrilateral angles 80, 22, 236 and 22 Arrowhead ABCD with angles 80 degrees at A, 22 degrees at B and D, and a reflex angle of 236 degrees at C. 80° 22° 22° 236° A B C D
A non-convex quadrilateral still adds to \(360^\circ\): \(80 + 22 + 236 + 22 = 360\).

The rule (angle sum of a quadrilateral) and the special cases:

\[ a + b + c + d = 360 \]
a + b + c + d =360
QuadrilateralExtra angle facts
parallelogramopposite angles equal; angles next to each other add to \(180^\circ\)
rectangle, squareevery angle \(90^\circ\)
kitethe angles between the unequal sides are equal
isosceles trapeziumthe two angles on each parallel side are equal
360, not 180. \(180^\circ\) is the angle sum of a triangle. A quadrilateral is two triangles.
Check a set of angles. \(100^\circ\), \(95^\circ\), \(85^\circ\) and \(70^\circ\) cannot be the angles of a quadrilateral, because they add to \(350^\circ\).

How to find a missing angle in a quadrilateral

  1. Read every corner: a right-angle mark is \(90^\circ\); a reflex angle is used as it is.
  2. Write the four angles \(= 360\), with the reason.
  3. Add the known angles and subtract from \(360\).
  4. Check that all four angles add to \(360\).

When the angles have pronumerals

  1. Add the four angles and make them equal to \(360\).
  2. Collect like terms and solve.
  3. Substitute to find each angle.
Example 1 — One missing angle
Find the value of \(a\).
Quadrilateral with a right angle, 67, 118 and a degrees Quadrilateral ABCD with a right angle at A, 67 degrees at B, 118 degrees at C and a degrees at D. 67° 118° a° A B C D
Solution

The right-angle mark at \(A\) shows \(90^\circ\).

\(a + 90 + 67 + 118\)\(=\)\(360\)
\(a + 275\)\(=\)\(360\)
\(a\)\(=\)\(85\)
a +90+67+118=360, a +275=360, a =85

\(a = 85\) (angle sum of a quadrilateral is \(360^\circ\)).

Example 2 — Add the known angles first
Find the value of \(x\).
Quadrilateral with angles 70, 80, 100 and x A quadrilateral with angles of 70 degrees, 80 degrees, 100 degrees and x. 70° 80° 100° x
Solution
\(x + 70 + 80 + 100\)\(=\)\(360\)
\(x + 250\)\(=\)\(360\)
\(x\)\(=\)\(110\)
x +70+80+100=360, x +250=360, x =110

\(x = 110^\circ\)

Example 3 — A reflex angle
Find the value of \(x\).
Non-convex quadrilateral with a reflex angle x Quadrilateral ABCD with angles 58 degrees at A, 42 degrees at B, 33 degrees at D and a reflex angle x at C. 58° 42° x° 33° A B C D
Solution
\(58 + 42 + x + 33\)\(=\)\(360\)
\(x + 133\)\(=\)\(360\)
\(x\)\(=\)\(227\)
58+42+ x +33=360, x +133=360, x =227

\(x = 227\). It is more than \(180\), so it is reflex, as the diagram shows.

Example 4 — Angles of a parallelogram
\(ABCD\) is a parallelogram. Find \(x\), \(y\) and \(z\).
Parallelogram ABCD with angle 64 at A Parallelogram ABCD with arrows on opposite sides. Angle A is 64 degrees; angles B, C and D are x, y and z degrees. 64° x° y° z° A B C D
Solution
\(x + 64\)\(=\)\(180\)
\(x\)\(=\)\(116\)
x +64=180, x =116 y =64, z =116

\(x = 116\) (co-interior angles, \(AD \parallel BC\)). \(y = 64\) and \(z = 116\) (opposite angles of a parallelogram are equal). Check: \(64 + 116 + 64 + 116 = 360\).

Example 5 — Pronumerals in the angles
Find \(x\), then the size of each angle.
Quadrilateral with angles 2x, x + 15, 3x and 105 Quadrilateral ABCD with angles (2x) degrees at A, (x + 15) degrees at B, (3x) degrees at C and 105 degrees at D. (2x)° (x + 15)° (3x)° 105° A B C D
Solution
\(2x + (x + 15) + 3x + 105\)\(=\)\(360\)
\(6x + 120\)\(=\)\(360\)
\(6x\)\(=\)\(240\)
\(x\)\(=\)\(40\)
6 x +120=360,6 x =240, x =40

\(x = 40\). The angles are \(80^\circ\), \(55^\circ\), \(120^\circ\) and \(105^\circ\) (check: they add to \(360\)).

Example 6 — Two right angles
In \(ABCD\), \(\angle DAB = \angle ADC = 90^\circ\), \(\angle ABC = 40^\circ\) and \(\angle BCD = (2x + 10)^\circ\). Find the value of \(x\).
Right trapezium with angles 90, 90, 40 and 2x + 10 Quadrilateral with right angles at A and D, 40 degrees at B and (2x + 10) degrees at C. 40° (2x + 10)° A B C D
Solution
\(2x + 10 + 40 + 90 + 90\)\(=\)\(360\)
\(2x + 230\)\(=\)\(360\)
\(2x\)\(=\)\(130\)
\(x\)\(=\)\(65\)
2 x +10+40+90+90=360,2 x +230=360,2 x =130, x =65

\(x = 65\), so \(\angle BCD = 140^\circ\).

Example 7 — Kite and isosceles trapezium
(i) \(PQRS\) is a kite with \(PQ = PS\) and \(RQ = RS\). \(\angle P = 100^\circ\) and \(\angle R = 60^\circ\). Find \(\angle Q\).
(ii) \(ABCD\) is an isosceles trapezium with \(AB \parallel DC\) and \(AD = BC\). \(\angle D = 70^\circ\). Find \(\angle A\) and \(\angle B\).
Solution
\(360 - 100 - 60\)\(=\)\(200\)
\(200 \div 2\)\(=\)\(100\)
\(180 - 70\)\(=\)\(110\)
360−100−60=200,200÷2=100180−70=110

(i) \(\angle Q = \angle S\) (the angles between the unequal sides), so \(\angle Q = 100^\circ\).
(ii) \(\angle A = 110^\circ\) (co-interior angles, \(AB \parallel DC\)) and \(\angle B = \angle A = 110^\circ\) (isosceles trapezium). Check: \(110 + 110 + 70 + 70 = 360\).

Common pitfalls

Using 180 degrees. A quadrilateral adds to \(360^\circ\).
Leaving out the right angle. A small square in a corner is \(90^\circ\): include it.
Using the outside angle. If an angle is marked outside the shape, first find the inside angle (angles on a straight line add to 180°).
Changing the reflex angle. At a dent the inside angle is more than \(180^\circ\). Use it as it is.

Frequently asked questions

What do the angles of a quadrilateral add up to?

\(360^\circ\).

Why is the angle sum of a quadrilateral 360 degrees?

A diagonal splits it into two triangles, and \(180 + 180 = 360\).

How do you find the missing angle of a quadrilateral?

Add the three known angles and subtract from \(360\). For \(90^\circ\), \(67^\circ\) and \(118^\circ\): \(360 - 275 = 85\), so the angle is \(85^\circ\).

Does the rule work for non-convex quadrilaterals?

Yes. Include the reflex angle: \(80 + 22 + 236 + 22 = 360\).

What angle facts does a parallelogram have?

Opposite angles are equal, and angles next to each other add to \(180^\circ\).