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Year 7 Maths Ratios, Rates and Time

Time Calculations

20 practice questions 1 video lesson Theory + worked examples
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Theory

Time is measured in seconds, minutes, hours, days and weeks. An hour has \(60\) minutes, not \(100\), so time calculations carry and borrow in \(60\)s. This Year 7 maths page shows how to convert units of time, add and subtract hours and minutes, use decimal hours and find elapsed time.

The facts: \(1\) min \(= 60\) s, \(1\) h \(= 60\) min, \(1\) day \(= 24\) h, \(1\) week \(= 7\) days.

Converting. A bigger unit to a smaller unit: multiply (\(3\) min \(= 3 \times 60 = 180\) s). A smaller unit to a bigger unit: divide, and the minutes left over stay as minutes: \(200\) min \(= 3\) h \(20\) min, because \(3 \times 60 = 180\).

Adding. Add the hours and the minutes separately. Then every \(60\) minutes make \(1\) hour: \(3\) h \(75\) min \(= 4\) h \(15\) min.

Subtracting. If there are not enough minutes, borrow \(1\) hour \(= 60\) minutes: \(5\) h \(10\) min \(= 4\) h \(70\) min.

Decimal hours. Minutes to part of an hour: divide by \(60\) (\(30\) min \(= 0.5\) h). Part of an hour to minutes: multiply by \(60\) (\(0.2\) h \(= 12\) min).

Elapsed time (how long from a start to a finish): count on to the next o’clock, then whole hours, then the minutes left.

Chain of time units Boxes week, day, h, min, s joined by arrows: times 7, times 24, times 60, times 60 to the right; divide going back to the left. week day h min s ×7 ÷7 ×24 ÷24 ×60 ÷60 ×60 ÷60 bigger to smaller: × ; smaller to bigger: ÷
Move right along the chain to multiply, left to divide. For example \(2\) days \(= 2 \times 24 = 48\) h.
Counting on from 9:35 am to 2:05 pm A time line with jumps: 25 minutes to 10:00 am, 4 hours to 2:00 pm, 5 minutes to 2:05 pm. 9:35 am 25 min 10:00 am 4 h 2:00 pm 5 min 2:05 pm 25 min + 4 h + 5 min = 4 h 30 min
Elapsed time by counting on: from 9:35 am to 2:05 pm is \(25\) min \(+ 4\) h \(+ 5\) min \(= 4\) h \(30\) min.

Common minutes as decimal hours (minutes ÷ 60):

MinutesHours
\(6\) min\(0.1\) h
\(15\) min\(0.25\) h
\(30\) min\(0.5\) h
\(45\) min\(0.75\) h
An hour is 60 minutes, not 100. \(2.5\) h is \(2\) h \(30\) min, not \(2\) h \(50\) min. And \(1\) h \(20\) min is not \(1.2\) h.
Always simplify the minutes. \(4\) h \(68\) min is not finished: \(68\) min \(= 1\) h \(8\) min, so the answer is \(5\) h \(8\) min.

How to add or subtract hours and minutes

  1. Line up hours with hours and minutes with minutes.
  2. Adding: add each part, then change every \(60\) minutes into \(1\) hour.
  3. Subtracting: if the minutes are too small, borrow \(1\) hour \(= 60\) minutes first.
  4. Check by adding back, or by working in minutes.

How to find elapsed time

  1. Count on from the start to the next o’clock.
  2. Jump whole hours, then the minutes left.
  3. Add the jumps.
Example 1 — Converting
Convert
(i) \(350\) minutes into hours and minutes
(ii) \(2\) days \(5\) hours \(20\) minutes into hours and minutes
Solution
\(5 \times 60\)\(=\)\(300\)
\(350 - 300\)\(=\)\(50\)
\(2 \times 24 + 5\)\(=\)\(53\)
5×60=300,350−300=502×24+5=53

(i) \(5\) h \(50\) min
(ii) \(53\) h \(20\) min (the minutes stay as minutes)

Example 2 — Seconds, minutes and days
(i) How many seconds are there in \(9\) minutes?
(ii) Convert \(285\) minutes into hours and minutes.
(iii) Convert \(1\) day \(7\) h \(40\) min into hours and minutes.
Solution
\(9 \times 60\)\(=\)\(540\)
\(4 \times 60\)\(=\)\(240\)
\(285 - 240\)\(=\)\(45\)
\(24 + 7\)\(=\)\(31\)
9×60=540285=4×60+4524+7=31

(i) \(540\) s
(ii) \(4\) h \(45\) min
(iii) \(31\) h \(40\) min

Example 3 — Add, then subtract
Simplify
(i) \(2\) h \(26\) min \(+\) \(3\) h \(47\) min
(ii) \(4\) h \(4\) min \(-\) \(2\) h \(12\) min
Solution

(i) Hours: \(2 + 3 = 5\). Minutes: \(26 + 47 = 73\) min \(= 1\) h \(13\) min.
(ii) \(4\) min is less than \(12\) min, so borrow: \(4\) h \(4\) min \(= 3\) h \(64\) min.

\(26 + 47\)\(=\)\(73\)
\(64 - 12\)\(=\)\(52\)
\(3 - 2\)\(=\)\(1\)
26+47=73 min =1 h 13 min , total 6 h 13 min 3 h 64 min −2 h 12 min =1 h 52 min

(i) \(6\) h \(13\) min
(ii) \(1\) h \(52\) min

Example 4 — Carrying and borrowing
Work out, with fewer than \(60\) minutes:
(i) \(2\) h \(47\) min \(+\) \(3\) h \(38\) min
(ii) \(7\) h \(20\) min \(-\) \(4\) h \(45\) min
Solution
\(47 + 38\)\(=\)\(85\)
\(80 - 45\)\(=\)\(35\)
47+38=85 min =1 h 25 min , total 6 h 25 min 7 h 20 min =6 h 80 min ,80−45=35,6−4=2

(i) \(85\) min \(= 1\) h \(25\) min, so \(6\) h \(25\) min.
(ii) \(7\) h \(20\) min \(= 6\) h \(80\) min, so \(2\) h \(35\) min. Check: \(2\) h \(35\) min \(+\) \(4\) h \(45\) min \(= 7\) h \(20\) min.

Example 5 — Decimal hours
(i) Write \(3\) h \(45\) min in hours, as a decimal.
(ii) Write \(1.6\) h in hours and minutes.
Solution
\(45 \div 60\)\(=\)\(0.75\)
\(0.6 \times 60\)\(=\)\(36\)
45÷60=0.75, so 3.75 h 0.6×60=36 min

(i) \(3.75\) h
(ii) \(1\) h \(36\) min

Example 6 — A bushwalk
A bushwalk in a national park starts at 9:35 am and finishes at 2:05 pm. The group stops for a \(45\)-minute lunch. How long do they spend walking, in hours, as a decimal?
Solution

Count on from 9:35 am (see the time line in Diagrams): \(25\) min \(+ 4\) h \(+ 5\) min \(= 4\) h \(30\) min. Take away the lunch break, borrowing \(1\) hour: \(3\) h \(90\) min \(- 45\) min.

\(4 \times 60 + 30\)\(=\)\(270\)
\(270 - 45\)\(=\)\(225\)
\(225 \div 60\)\(=\)\(3.75\)
4 h 30 min =270 min ,270−45=225 min =3.75 h

They walk for \(3\) h \(45\) min \(= 3.75\) hours.

Common pitfalls

Borrowing 100. Borrow \(60\) minutes, not \(100\): \(6\) h \(10\) min \(= 5\) h \(70\) min.
Decimal point as minutes. \(1.5\) h is \(1\) h \(30\) min, not \(1\) h \(50\) min.
Not simplifying. An answer with 60 or more minutes is not finished.
Forgetting the minutes when converting days. \(1\) day \(7\) h \(40\) min is \(31\) h \(40\) min: the \(40\) min stays.

Frequently asked questions

How do you convert minutes to hours and minutes?

Divide by \(60\). The whole number is the hours and the remainder is the minutes: \(285\) min \(= 4\) h \(45\) min.

How do you add hours and minutes?

Add the hours and the minutes separately, then change each \(60\) minutes into an hour.

How do you subtract times when there are not enough minutes?

Borrow \(1\) hour and add \(60\) to the minutes.

How do you write minutes as a decimal of an hour?

Divide by \(60\). \(45\) min \(= 0.75\) h.

How do you find how long something takes?

Count on from the start time to the next o’clock, then whole hours, then the minutes left.