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Year 7 Maths Ratios, Rates and Time

Rates (harder)

20 practice questions 1 video lesson Theory + worked examples
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Theory

To convert a rate to new units, write the unit fact first, then change one unit at a time. \(12\) L/min is \(12 \times 60 = 720\) L/h. This Year 7 maths page shows how to change the time unit, the amount unit or both, and the shortcut between m/s and km/h.

Change the time unit. \(12\) L/min means \(12\) L every minute. An hour has \(60\) minutes, so multiply: \(12 \times 60 = 720\) L/h. A longer time gives a bigger amount; a shorter time gives a smaller amount, so divide.

Change the amount unit. Only the amount changes; the time stays the same: \(0.8\) m/h is \(0.8 \times 100 = 80\) cm/h.

Two units change? Change one unit, write the new rate, then change the other. Sometimes both change the same way: \(8\) km/L is \(8000\) m per \(1000\) mL, which is \(8\) m/mL.

Rounding. Round only at the end, to the places asked: \(1000\) kg/h \(= 1000 \div 3600 \approx 0.28\) kg/s (\(2\) decimal places).

m/s and km/h. Multiplying by \(3600\) and then dividing by \(1000\) is the same as multiplying by \(3.6\). So m/s \(\times 3.6 =\) km/h, and km/h \(\div 3.6 =\) m/s.

Hours and minutes. Change the minutes to hours: \(45\) min \(= \dfrac{45}{60}\) h \(= 0.75\) h, so \(1\) h \(45\) min \(= 1.75\) h.

Converting 5 metres per second to kilometres per hour Three boxes joined by arrows: 5 m/s, times 3600 gives 18 000 m/h, divided by 1000 gives 18 km/h. 5 m/s × 3600 18 000 m/h ÷ 1000 18 km/h shortcut: 5 × 3.6 = 18
Change one unit per step: seconds to hours (\(\times 3600\)), then metres to kilometres (\(\div 1000\)). The shortcut gives the same answer: \(5 \times 3.6 = 18\).

Unit facts:

TimeLength, volume, mass
\(1\) min \(= 60\) s\(1\) km \(= 1000\) m
\(1\) h \(= 60\) min \(= 3600\) s\(1\) m \(= 100\) cm
\(1\) day \(= 24\) h\(1\) L \(= 1000\) mL
\(1\) kg \(= 1000\) g
\[ \text{m/s} \times 3.6 = \text{km/h} \]
m / s ×3.6= km / h
\[ \text{km/h} \div 3.6 = \text{m/s} \]
km / h ÷3.6= m / s
Multiply or divide? Ask if the answer should be bigger or smaller. \(360\) mL/min is only \(360 \div 60 = 6\) mL each second, so divide.
Change both units. \(250\) m/min \(= 15\,000\) m/h is only step 1. Divide by \(1000\) to get \(15\) km/h.

How to convert a rate

  1. Write the unit fact for the unit you are changing.
  2. Decide: should the number get bigger or smaller? Multiply or divide.
  3. Change one unit per line and write the new rate each time.
  4. Round only at the end, and check with a shortcut if there is one.
Example 1 — A cost rate
At a market, LED bulbs cost \(\$12.50\) for \(5\) bulbs.
(i) What is the cost rate?
(ii) What is the cost of \(14\) LED bulbs?
Solution
\(12.50 \div 5\)\(=\)\(2.50\)
\(14 \times 2.50\)\(=\)\(35\)
12.50÷5=2.50,14×2.50=35

(i) \(\$2.50\) per bulb
(ii) \(\$35.00\)

Example 2 — Changing the time unit
(i) A sprinkler uses \(18\) L/min. Write this rate in L/h.
(ii) Change \(540\) mL/min to mL/s.
Solution
\(18 \times 60\)\(=\)\(1080\)
\(540 \div 60\)\(=\)\(9\)
18×60=1080 L / h 540÷60=9 mL / s

(i) \(1080\) L/h (an hour is longer, so multiply)
(ii) \(9\) mL/s (a second is shorter, so divide)

Example 3 — Changing both units
A machine packs \(750\) g of nuts per minute. Change this rate to kg/h.
Solution
\(750 \times 60\)\(=\)\(45\,000\)
\(45\,000 \div 1000\)\(=\)\(45\)
750×60=45000 g / h ,45000÷1000=45 kg / h

Step 1: \(45\,000\) g/h. Step 2: \(45\) kg/h.

Example 4 — Metres per second to km/h
Change \(12\) m/s to km/h.
Solution
\(12 \times 3600\)\(=\)\(43\,200\)
\(43\,200 \div 1000\)\(=\)\(43.2\)
12×3600=43200 m / h ,÷1000=43.2 km / h check 12×3.6=43.2

\(43.2\) km/h. Check with the shortcut: \(12 \times 3.6 = 43.2\).

Example 5 — Speed, then m/s
Ava cycles \(54\) km in \(1\) h \(30\) min.
(i) Find her average speed in km/h.
(ii) Change this speed to m/s.
Solution
\(1 + 0.5\)\(=\)\(1.5\)
\(54 \div 1.5\)\(=\)\(36\)
\(36\,000 \div 3600\)\(=\)\(10\)
1 h 30 min =1.5 h ,54÷1.5=36 km / h 36000 m / h ÷3600=10 m / s

(i) \(36\) km/h
(ii) \(10\) m/s (check: \(36 \div 3.6 = 10\))

Example 6 — Rounding at the end
A conveyor moves \(4200\) kg of sand each hour. Change this rate to kg/s, correct to \(2\) decimal places.
Solution
\(4200 \div 3600\)\(=\)\(1.1666\ldots\)
4200÷3600=1.1666, about 1.17 kg / s

\(\approx 1.17\) kg/s

Common pitfalls

Multiplying when you should divide. A shorter time unit gives a smaller number.
Changing only one unit. Read the units asked for and change every unit that differs.
Rounding too early. Keep the full value until the last step.
Hours and minutes as a decimal. \(1\) h \(30\) min is \(1.5\) h, not \(1.3\) h.

Frequently asked questions

How do you change L/min to L/h?

Multiply by \(60\), because an hour has \(60\) minutes. \(18\) L/min is \(1080\) L/h.

How do you change m/s to km/h?

Multiply by \(3.6\). \(25\) m/s is \(90\) km/h.

How do you change km/h to m/s?

Divide by \(3.6\). \(36\) km/h is \(10\) m/s.

How do you convert a rate when both units change?

Change one unit at a time. \(750\) g/min \(= 45\,000\) g/h \(= 45\) kg/h.

How do you write 1 hour 45 minutes in hours?

\(45\) min is \(\dfrac{45}{60} = 0.75\) h, so it is \(1.75\) h.