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Two circles of equal radii of 4 cm are joined by a square of side 4 cm, as shown in the diagram.
(i) Explain why \(\angle AMD = \angle BNC = 60^\circ\).
(ii) Find the exact total area of the figure.
(i) \(\triangle AMD\) and \(\triangle BNC\) are equilateral (ii) \(\left(\dfrac{80\pi}{3}+16+8\sqrt3\right)\text{ cm}^2\)
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