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Year 11 (2025) Maths Advanced Trigonometry

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Question 1
124470

(i) Prove that \(\sec ^2 \theta-2 \tan \theta=(\tan \theta-1)^2\).

(ii) Hence, or otherwise, solve \(\sec ^2 \theta-2 \tan \theta=0\) for \(0 \leq \theta \leq 2 \pi\)

i) True

ii) \(\theta=\dfrac{\pi}{4}, \dfrac{5 \pi}{4}\)

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