Resources For Teachers For Tutors For Students & Parents AI New Pricing
Year 8 Maths Working with Numbers

Order of Operations

20 practice questions 1 video lesson Theory + worked examples
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

Work out grouping symbols first (brackets, the fraction bar and the square root sign), then powers and roots, then multiply and divide from left to right, and add and subtract last, from left to right. This Year 8 maths page uses integers throughout.

1. Simplify inside grouping symbols, starting with the innermost brackets. 2. Work out powers and roots. 3. Multiply and divide from left to right. 4. Add and subtract from left to right.

Three things group: brackets, the fraction bar and the square root sign. Brackets inside brackets are worked from the inside out; the outer pair is often written \([\;]\).

A number against a bracket means multiply: \(-4(2 - 9) = -4 \times (-7) = 28\). The root sign groups everything under it: \(\sqrt{40 + 9} = \sqrt{49} = 7\).

Brackets change the value: \(30 - 4 \times 5 = 10\), but \((30 - 4) \times 5 = 130\).

Substituting. Put each negative value in brackets as you substitute, so \(a^2\) with \(a = -6\) becomes \((-6)^2 = 36\), not \(-6^2\). \(ab\) means \(a \times b\).

Calculators. A calculator does not see a fraction bar. To find a mean, type the brackets: \((-14 + 22 - 5 + 9) \div 4 = 3\). Without them it divides only the last number.

Missing number. Undo the operations in reverse order, then check by working forwards.

The order of operations Four boxes in order: grouping symbols (brackets, root sign, fraction bar), then powers, then multiply and divide from left to right, then add and subtract from left to right. bracketsroot, bar powers × and ÷left to right + and −left to right
Grouping symbols first, then powers, then \(\times\) and \(\div\) from left to right, then \(+\) and \(-\) from left to right.
A fraction bar groups the top and the bottom A fraction with 4 minus negative 2 cubed on top and root 49 minus 3 underneath. The top is 12, the bottom is 4, and 12 divided by 4 is 3. 4 − (−2)³ ――――― √49 − 3 = 4 + 8 = 12 = 7 − 3 = 4 12 ÷ 4 = 3
The bar groups the whole top and the whole bottom. Work out each one, including the power and the root, and divide only at the end.

The order of operations:

StepWhat to do
1Grouping symbols: brackets (inside out), fraction bar, square root sign
2Powers and roots
3\(\times\) and \(\div\), from left to right
4\(+\) and \(-\), from left to right
The bracket decides what is squared. \((-9)^2 = 81\), but \(-9^2 = -81\).
× and ÷ have equal priority. \(-48 \div 8 \times 2 = -6 \times 2 = -12\).

How to evaluate an expression

  1. Work out inside grouping symbols, innermost first.
  2. Work out powers and roots.
  3. Multiply and divide from left to right.
  4. Add and subtract from left to right.

How to work backwards

  1. List the operations in the order they are done.
  2. Undo them in reverse order.
  3. Check by substituting your answer.
Example 1 — Brackets, then multiply
Evaluate \(17 - (4 + 3) \times (-2)\).
Solution

\(17 - (4 + 3) \times (-2)\)

\(\)\(=\)\(17 - 7 \times (-2)\)
\(\)\(=\)\(17 - (-14)\)
\(\)\(=\)\(17 + 14 = 31\)
17−7×(−2)=17+14=31

\(31\)

Example 2 — Brackets inside brackets
Evaluate \((4 - (2 + 1)) + 12 \div 3\).
Solution

\((4 - (2 + 1)) + 12 \div 3\)

\(\)\(=\)\((4 - 3) + 12 \div 3\)
\(\)\(=\)\(1 + 12 \div 3\)
\(\)\(=\)\(1 + 4 = 5\)
(4−3)+4=5

\(5\)

Example 3 — Power, then product
Work out \(7 - 5 \times (-4) + (-3)^2\).
Solution
\((-3)^2\)\(=\)\(9\)
\(5 \times (-4)\)\(=\)\(-20\)
\(7 - (-20) + 9\)\(=\)\(7 + 20 + 9 = 36\)
7+20+9=36

\(36\)

Example 4 — Grouping symbols
Work out
(i) \(-6[5 - (2 - 6)]\)
(ii) \(\sqrt{100 - 36} \times (-5)\)
Solution
\(5 - (2 - 6)\)\(=\)\(5 - (-4) = 9\)
\(-6 \times 9\)\(=\)\(-54\)
\(\sqrt{100 - 36}\)\(=\)\(\sqrt{64} = 8\)
\(8 \times (-5)\)\(=\)\(-40\)
−6×9=−5464×(−5)=−40

(i) \(-54\)
(ii) \(-40\)

Example 5 — Substituting integers
Take \(a = -6\), \(b = 5\) and \(c = -3\). Evaluate
(i) \(a^2 + ab\)
(ii) \(\dfrac{ab}{c} - a\)
Solution
\((-6)^2 + (-6) \times 5\)\(=\)\(36 + (-30)\)
\(\)\(=\)\(6\)
\(\dfrac{(-6) \times 5}{-3} - (-6)\)\(=\)\(10 + 6 = 16\)
36−30=6−30÷(−3)+6=16

(i) \(6\)
(ii) \(16\)

Example 6 — Working backwards
Find the missing integer: \(\dfrac{{?} + 6}{-4} - 3 = 5\).
Solution

Undo \(-3\): the fraction is \(5 + 3 = 8\). Undo \(\div (-4)\): \({?} + 6 = 8 \times (-4) = -32\). Undo \(+6\): \({?} = -32 - 6 = -38\).

\(\dfrac{-38 + 6}{-4} - 3\)\(=\)\(\dfrac{-32}{-4} - 3\)
\(\)\(=\)\(8 - 3 = 5\)
=−38 check (−32)÷(−4)−3=5

\({?} = -38\)

Example 7 — Words and a calculator
(i) At dawn it is \(-6^\circ\)C. The temperature rises \(3^\circ\)C each hour for \(4\) hours, then falls \(2^\circ\)C each hour for \(3\) hours. Find the final temperature.
(ii) Ben wants the mean of \(-14\), \(22\), \(-5\) and \(9\). He types \(-14 + 22 - 5 + 9 \div 4\). What does the calculator show, and what is the mean?
Solution
\(\text{final}\)\(=\)\(-6 + 3 \times 4 - 2 \times 3\)
\(\)\(=\)\(-6 + 12 - 6 = 0\)
\(\text{shown}\)\(=\)\(3 + 2.25 = 5.25\)
\(\text{mean}\)\(=\)\(12 \div 4 = 3\)
final temperature 0 C calculator 5.25 mean 3

(i) \(0^\circ\)C
(ii) It shows \(5.25\), because it divides only the \(9\). The mean is \(3\).

Common pitfalls

Working left to right regardless. \(20 - 4 \times 3\) is \(20 - 12 = 8\), not \(16 \times 3\).
Multiplying before an earlier division. \(-48 \div 8 \times 2 = -12\), not \(-3\).
Losing the bracket on a negative. With \(a = -6\), \(a^2 = 36\), not \(-36\).
Ignoring the fraction bar. \(\dfrac{6 + 18}{6} = 4\), not \(6 + 3\).

Frequently asked questions

What is the order of operations?

Grouping symbols, then powers and roots, then multiply and divide from left to right, then add and subtract from left to right.

Do you multiply before you divide?

No. They have equal priority, so work from left to right: \(12 \div 3 \times 2 = 8\).

Is the fraction bar a grouping symbol?

Yes. Work out the whole top and the whole bottom before dividing.

Why do I put a negative number in brackets when I substitute?

So that the whole number is squared: \((-6)^2 = 36\), but \(-6^2 = -36\).

How do I find a missing number in a calculation?

Undo the operations in reverse order, then check by working forwards.