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Year 8 Maths Fractions and Percentages

The Unitary Method

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Theory

The unitary method finds the value of one unit first (one per cent, or one equal part) and then multiplies up. If \(55\%\) of a crowd is \(20\,119\), then \(1\%\) is \(20\,119 \div 55 = 365.8\) and the whole crowd is \(36\,580\). This Year 8 maths page shows how.

The four steps. Write what you know, find \(1\%\) by dividing by the percentage, find \(100\%\) by multiplying by \(100\), then check by working forwards.

Any percentage, not only \(100\%\). Once \(1\%\) is known, multiply it by the percentage the question asks for.

Fractions work the same way. If \(\dfrac{3}{7}\) of an amount is known, divide by \(3\) for \(\dfrac{1}{7}\), then multiply by \(7\).

Rates too. If \(30\%\) of a job takes \(12\) minutes, then \(1\%\) takes \(0.4\) minutes and the whole job takes \(40\) minutes.

After a change, name the percentage you actually know. A discount or a loss of \(p\%\) leaves \((100 - p)\%\); a rise or a profit of \(p\%\) gives \((100 + p)\%\).

One step instead. Dividing by the multiplier does the same job: after \(20\%\) off, divide by \(0.8\); after an \(8\%\) rise, divide by \(1.08\).

Two changes in a row. Combine them into one percentage first: \(20\%\) off then \(10\%\) off leaves \(0.8 \times 0.9 = 0.72\), so \(72\%\) of the original.

Double number line for the unitary method Percentages on the top line and amounts on the bottom line: 0% is 0, 1% is 3, 16% is 48 and 100% is 300. 0%0 16%48 1%3 100%300
If \(16\%\) is \(48\), then \(1\%\) is \(48 \div 16 = 3\), and \(100\%\) is \(3 \times 100 = 300\). One per cent is the stepping stone between any two percentages.

Name the percentage you know:

SituationThe known amount isDivide by
\(18\%\) of a hall is full\(18\%\)\(18\) (for \(1\%\))
after \(30\%\) off\(70\%\) of the original\(0.7\)
after a \(15\%\) rise\(115\%\) of the original\(1.15\)
after a \(20\%\) loss\(80\%\) of the cost price\(0.8\)
\(\dfrac{5}{9}\) of a book\(5\) ninths\(5\) (for one ninth)
Divide by the percentage, not by 100. If \(24\%\) of a bill is \(\$72\), then \(1\%\) is \(72 \div 24 = \$3\) and the bill is \(\$300\).
The whole is bigger than the part. An answer smaller than the amount you were given means the two steps were swapped.

The unitary method

  1. Write what you know: \(p\%\) of the whole \(=\) amount.
  2. Find \(1\%\): divide the amount by \(p\).
  3. Multiply by \(100\) for the whole, or by any other percentage asked for.
  4. Check by working forwards.

After a discount or a rise

  1. Name the percentage you know: \((100 - p)\%\) after a discount, \((100 + p)\%\) after a rise.
  2. Find \(1\%\), then \(100\%\); or divide by the multiplier.
Example 1 — Back through a discount
Alice buys a dress that has been discounted by \(30\%\). The sale price is \(\$63\). What was the original price?
Solution

After \(30\%\) off, the \(\$63\) is \(70\%\) of the original price.

\(\text{70\%}\)\(=\)\(\$63\)
\(\text{1\%}\)\(=\)\(63 \div 70 = 0.90\)
\(\text{100\%}\)\(=\)\(0.90 \times 100 = 90\)
63÷70×100=90

The original price was \(\$90\). Check: \(0.7 \times 90 = 63\).

Example 2 — Find the whole
(i) There were \(20\,119\) men in the crowd at a tennis match. This is \(55\%\) of the crowd. What was the total attendance?
(ii) A school hall is \(18\%\) full; that is \(63\) people. How many seats does the hall have?
Solution
\(\text{1\%}\)\(=\)\(20\,119 \div 55 = 365.8\)
\(\text{100\%}\)\(=\)\(365.8 \times 100 = 36\,580\)
\(\text{1\%}\)\(=\)\(63 \div 18 = 3.5\)
\(\text{100\%}\)\(=\)\(3.5 \times 100 = 350\)
36580350 seats

(i) \(36\,580\) people
(ii) \(350\) seats. Check: \(0.18 \times 350 = 63\).

Example 3 — Straight to another percentage
In an orchard, \(24\%\) of the trees are apple trees, and there are \(168\) of them. Pear trees make up \(45\%\) of the orchard. How many pear trees are there?
Solution
\(\text{1\%}\)\(=\)\(168 \div 24 = 7\)
\(\text{45\%}\)\(=\)\(7 \times 45 = 315\)
168÷24×45=315

\(315\) pear trees. Check: the orchard has \(700\) trees and \(0.45 \times 700 = 315\).

Example 4 — One part of a fraction, and a rate
(i) Ben has read \(\dfrac{5}{9}\) of a novel, which is \(240\) pages. How many pages does the novel have?
(ii) \(30\%\) of a download takes \(12\) minutes. How long does the whole download take?
Solution
\(\text{one ninth}\)\(=\)\(240 \div 5 = 48\)
\(\text{the whole}\)\(=\)\(48 \times 9 = 432\)
\(\text{1\%}\)\(=\)\(12 \div 30 = 0.4~\text{min}\)
\(\text{100\%}\)\(=\)\(0.4 \times 100 = 40~\text{min}\)
432 pages 40 minutes

(i) \(432\) pages
(ii) \(40\) minutes

Example 5 — Discounts and rises
(i) A jacket is reduced by \(35\%\) and now costs \(\$91\). What was the price before the sale, and how much is saved?
(ii) After an \(8\%\) pay rise, Sam earns \(\$1080\) a fortnight. What did he earn before?
Solution
\(\text{1\%}\)\(=\)\(91 \div 65 = 1.4\)
\(\text{100\%}\)\(=\)\(1.4 \times 100 = 140\)
\(140 - 91\)\(=\)\(49\)
\(1080 \div 1.08\)\(=\)\(1000\)
$140,$49 saved $1000

(i) \(\$140\), saving \(\$49\). In one step: \(91 \div 0.65 = 140\).
(ii) \(\$1000\)

Example 6 — Two changes in a row
A pair of boots was marked down by \(20\%\), then the sale price was cut by a further \(10\%\). The final price is \(\$54\). Find the original price.
Solution
\(0.8 \times 0.9\)\(=\)\(0.72\)
\(54 \div 0.72\)\(=\)\(75\)
0.8×0.9=0.7254÷0.72=75

The final price is \(72\%\) of the original, so the original price was \(\$75\). Check: \(75 \times 0.8 = 60\), then \(60 \times 0.9 = 54\).

Common pitfalls

Adding the discount back on. After \(30\%\) off, \(\$63\) is \(70\%\) of the price. Adding \(30\%\) of \(\$63\) gives \(\$81.90\), not the original \(\$90\).
Dividing by 100 first. If \(24\%\) is \(\$72\), \(72 \div 100\) is \(1\%\) of \(\$72\), not \(1\%\) of the bill.
Adding two discounts. \(20\%\) off then \(10\%\) off leaves \(72\%\), not \(70\%\).
Forgetting what is asked. Read whether the question wants the whole, the saving, or another percentage.

Frequently asked questions

What is the unitary method?

A method that finds the value of one unit (such as 1%) first, then multiplies to find any other amount.

How do I find the whole amount from a percentage?

Divide the amount by the percentage to get \(1\%\), then multiply by \(100\).

How do I find the original price after a discount?

Write the sale price as \((100 - p)\%\) of the original, find \(1\%\), then \(100\%\). Or divide by the multiplier.

Can I use the unitary method with fractions?

Yes. If \(\dfrac{2}{5}\) is \(30\), then \(\dfrac{1}{5}\) is \(15\) and the whole is \(75\).

How do I check my answer?

Work forwards: take the percentage of your answer and see whether you get the amount you were given.