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Year 8 Maths Fractions and Percentages

Expressing Amounts as Fractions and Percentages

20 practice questions 1 video lesson Theory + worked examples
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Theory

To write one amount as a fraction of another, put the part over the whole in the same units and simplify; multiply by \(100\%\) for a percentage. \(28\) out of \(40\) is \(\dfrac{28}{40} = \dfrac{7}{10} = 70\%\). This Year 8 maths page shows how.

Step 1: match the units. Change both amounts to the same unit, usually the smaller one so no decimals are left: cents, grams, millimetres, millilitres, seconds or minutes.

Step 2: part over whole. If the whole is made of two or more groups, add them first: \(14\) red and \(21\) blue beads make \(35\), so red is \(\dfrac{14}{35} = \dfrac{2}{5}\).

Step 3: simplify by dividing the top and the bottom by their HCF.

Step 4: for a percentage, multiply by \(100\%\). \(\dfrac{13}{25} \times 100\% = \dfrac{1300}{25}\% = 52\%\). If the denominator divides into \(100\), make it \(100\): \(\dfrac{13}{25} = \dfrac{52}{100} = 52\%\).

Rounding. When the percentage does not stop, round to the accuracy asked for and write \(\approx\). An exact answer keeps a fractional percentage: \(\dfrac{1}{6} \times 100\% = 16\dfrac{2}{3}\%\).

Choose the right whole. A change, a profit or a loss is compared with the amount before the change: the original price, or the cost price of something bought and sold.

Comparing results out of different totals: change each to a percentage, then compare. The difference between two percentages is measured in percentage points.

Part of a whole A bar for all 80 students: 52 of them shaded, the other 28 not. 52 out of 80 is 13/20, which is 65%. 52 walk or ride 28 0% 65% 100%
\(52\) of the \(80\) students is \(\dfrac{52}{80} = \dfrac{13}{20} = \dfrac{65}{100} = 65\%\) of the bar.
A fall compared with the amount before Two columns: 50 dollars before and 40 dollars after. The fall of 10 dollars is compared with the 50 dollars before. 0 10 20 30 40 50 60 before 50 after 40
The \(\$10\) fall is compared with the amount before: \(\dfrac{10}{50} \times 100\% = 20\%\). Using the \(\$40\) after gives \(25\%\), which answers a different question.

Part over whole, then times 100%:

AmountsFractionPercentage
\(18\) of \(30\)\(\dfrac{18}{30} = \dfrac{3}{5}\)\(60\%\)
\(40\) cm of \(3\) m\(\dfrac{40}{300} = \dfrac{2}{15}\)\(13\dfrac{1}{3}\%\)
\(105\) min of \(5\) h\(\dfrac{105}{300} = \dfrac{7}{20}\)\(35\%\)
\(\$2.40\) of \(\$8\)\(\dfrac{240}{800} = \dfrac{3}{10}\)\(30\%\)
Match the units first. \(40\) cm of \(3\) m is \(\dfrac{40}{300}\), not \(\dfrac{40}{3}\). And \(1\) h \(45\) min is \(105\) minutes, not \(1.45\) hours.
Part on top, whole underneath. \(21\) out of \(60\) is \(\dfrac{21}{60} = \dfrac{7}{20} = 35\%\). The other way up, \(\dfrac{60}{21}\), is more than \(1\) and cannot be a part.

Expressing one amount as a percentage of another

  1. Match the units (change to the smaller unit).
  2. Write part over whole; add groups first if the whole is made of several.
  3. Simplify the fraction.
  4. Multiply by \(100\%\), and round with \(\approx\) only at the end.

Percentage change, profit or loss

  1. Find the change (new \(-\) old, or the profit or loss).
  2. Divide by the original amount (the cost price).
  3. Multiply by \(100\%\).
Example 1 — Fraction and percentage
In a class of \(30\) there are \(12\) boys and \(18\) girls.
(i) What fraction are girls?
(ii) What percentage are boys?
(iii) Annie scored \(28\) out of \(40\) in a test. What percentage is this?
Solution
\(\dfrac{18}{30}\)\(=\)\(\dfrac{6 \times 3}{6 \times 5} = \dfrac{3}{5}\)
\(\dfrac{12}{30} \times 100\%\)\(=\)\(\dfrac{2}{5} \times 100\%\)
\(\)\(=\)\(40\%\)
\(\dfrac{28}{40} \times 100\%\)\(=\)\(\dfrac{7}{10} \times 100\%\)
\(\)\(=\)\(70\%\)
3/54070

(i) \(\dfrac{3}{5}\)
(ii) \(40\%\)
(iii) \(70\%\)

Example 2 — Make the denominator 100
Of the \(80\) students in a year group, \(52\) walk or ride to school.
(i) What fraction is this, in simplest form?
(ii) What percentage is this?
Solution
\(\dfrac{52}{80}\)\(=\)\(\dfrac{13}{20}\)
\(\dfrac{13}{20}\)\(=\)\(\dfrac{65}{100} = 65\%\)
13/20=65

(i) \(\dfrac{13}{20}\) (HCF \(4\))
(ii) \(65\%\)

Example 3 — Two different units
(i) A garden bed is \(2.4\) m long. A \(90\) cm strip of it is planted with herbs. What percentage of the bed is herbs?
(ii) A \(5\) h trip includes \(1\) h \(45\) min of driving on dirt roads. What percentage of the trip is that?
Solution

(i) \(2.4\) m \(= 240\) cm.
(ii) \(5\) h \(= 300\) min and \(1\) h \(45\) min \(= 105\) min.

\(\dfrac{90}{240} \times 100\%\)\(=\)\(\dfrac{3}{8} \times 100\%\)
\(\)\(=\)\(37.5\%\)
\(\dfrac{105}{300} \times 100\%\)\(=\)\(\dfrac{7}{20} \times 100\%\)
\(\)\(=\)\(35\%\)
37.535

(i) \(37.5\%\). Check: \(0.375 \times 240 = 90\).
(ii) \(35\%\)

Example 4 — A rounded percentage
A basketballer scored \(19\) of her \(31\) free throws. What percentage did she score, correct to one decimal place?
Solution
\(\dfrac{19}{31} \times 100\%\)\(=\)\(\dfrac{1900}{31}\%\)
\(\)\(=\)\(61.29\ldots\%\)
\(\)\(\approx\)\(61.3\%\)
1900/31≈61.3

About \(61.3\%\). Estimate: \(19\) is a bit over half of \(31\).

Example 5 — Loss and change on the original
(i) Sam bought a skateboard for \(\$120\) and sold it for \(\$78\). Find his loss as a percentage of the cost price.
(ii) A price rises from \(\$40\) to \(\$50\). Find the percentage increase.
Solution
\(120 - 78\)\(=\)\(42\)
\(\dfrac{42}{120} \times 100\%\)\(=\)\(\dfrac{7}{20} \times 100\% = 35\%\)
\(\dfrac{10}{40} \times 100\%\)\(=\)\(25\%\)
35 loss 25 increase

(i) A \(35\%\) loss. Check: \(0.35 \times 120 = 42\).
(ii) A \(25\%\) increase (the change \(\$10\) over the original \(\$40\)).

Example 6 — Comparing and updating
(i) Kim scored \(33\) out of \(40\) and Lee scored \(41\) out of \(50\). Who did better, and by how many percentage points?
(ii) A \(4000\) L tank is \(75\%\) full. Then \(1000\) L is used. What percentage full is it now?
Solution
\(\dfrac{33}{40} \times 100\%\)\(=\)\(82.5\%\)
\(\dfrac{41}{50} \times 100\%\)\(=\)\(82\%\)
\(0.75 \times 4000 - 1000\)\(=\)\(2000\)
\(\dfrac{2000}{4000} \times 100\%\)\(=\)\(50\%\)
82.5 vs 8250 full

(i) Kim did better by \(0.5\) percentage points.
(ii) \(50\%\) full

Common pitfalls

Mixing units. \(250\) g of \(2\) kg is \(\dfrac{250}{2000} = \dfrac{1}{8} = 12.5\%\), not \(\dfrac{250}{2}\).
Using the new amount as the whole. A rise from \(\$40\) to \(\$50\) is \(\dfrac{10}{40} = 25\%\); a fall from \(\$50\) to \(\$40\) is \(\dfrac{10}{50} = 20\%\).
Rounding too early. \(\dfrac{7}{12} \times 100\% = 58.33\ldots\%\), so \(\approx 58.3\%\). Round once, at the end.
Forgetting to add the groups. For \(8\) apples and \(12\) pears, apples are \(\dfrac{8}{20}\) of the fruit, not \(\dfrac{8}{12}\).

Frequently asked questions

How do I write one amount as a percentage of another?

Write the part over the whole in the same units, then multiply by \(100\%\): \(15\) out of \(60\) is \(\dfrac{15}{60} \times 100\% = 25\%\).

Why must the units be the same?

A fraction compares like with like. 40 cm out of 3 m only makes sense when both are in centimetres.

How do I find a percentage increase?

Divide the increase by the original amount and multiply by \(100\%\).

What is the cost price?

The amount paid for something. A profit or loss percentage is worked out on the cost price.

What is a percentage point?

The difference between two percentages: \(82.5\%\) and \(82\%\) differ by \(0.5\) percentage points.