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Year 7 Maths Fractions

Adding and Subtracting Fractions

20 practice questions 1 video lesson Theory + worked examples
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Theory

Fractions can be added or subtracted only when they have the same denominator. Then add or subtract the numerators and keep the denominator. This Year 7 maths page shows how to find the lowest common denominator, add and subtract fractions, take fractions from a whole and simplify the answer.

Same denominator: add or subtract the numerators and keep the denominator: \(\dfrac{1}{5} + \dfrac{3}{5} + \dfrac{4}{5} = \dfrac{8}{5} = 1\dfrac{3}{5}\). Simplify if you can.

Different denominators: change the fractions to equivalent fractions with the same denominator, then add or subtract: \(\dfrac{1}{5} + \dfrac{3}{4} = \dfrac{4}{20} + \dfrac{15}{20} = \dfrac{19}{20}\).

The lowest common denominator (LCD) is the smallest number both denominators divide into. If one denominator is a multiple of the other, it is the LCD (\(12\) for \(4\) and \(12\)). If their HCF is \(1\), multiply them (\(15\) for \(3\) and \(5\)). Otherwise list multiples (\(18\) for \(6\) and \(9\)).

Taking from a whole: write the whole with the same denominator: \(1 - \dfrac{2}{7} = \dfrac{7}{7} - \dfrac{2}{7} = \dfrac{5}{7}\).

One quarter plus one sixth Three bars of the same length. The first shows 1 quarter shaded, the second 1 sixth shaded and the third is cut into 12 parts with 5 shaded. 14 16 512
One quarter covers \(3\) twelfths and one sixth covers \(2\) twelfths, so \(\dfrac{1}{4} + \dfrac{1}{6} = \dfrac{5}{12}\).

Make the parts the same size first:

\[ \dfrac{2}{9} + \dfrac{5}{9} = \dfrac{2 + 5}{9} = \dfrac{7}{9} \]
2/9+5/9=7/9
\[ \dfrac{1}{2} + \dfrac{1}{5} - \dfrac{1}{10} = \dfrac{5}{10} + \dfrac{2}{10} - \dfrac{1}{10} = \dfrac{3}{5} \]
1/2+1/5−1/10=5/10+2/10−1/10=3/5
\[ 2 - \dfrac{3}{10} = 1 + \dfrac{10}{10} - \dfrac{3}{10} = 1\dfrac{7}{10} \]
2−3/10=17/10
Simplify at the end. \(\dfrac{5}{12} + \dfrac{1}{6} = \dfrac{5}{12} + \dfrac{2}{12} = \dfrac{7}{12}\). Then check whether the answer simplifies, and write improper answers as mixed numerals.
Check the size. A sum must be bigger than each fraction in it: \(\dfrac{1}{2} + \dfrac{1}{3}\) cannot be \(\dfrac{2}{5}\).
A missing numerator. \(\dfrac{1}{6} + \dfrac{\square}{12} = \dfrac{3}{4}\): \(\dfrac{9}{12} - \dfrac{2}{12} = \dfrac{7}{12}\), so \(\square = 7\).

How to add or subtract fractions

  1. Find the LCD of the denominators.
  2. Rename each fraction with the LCD (multiply top and bottom by the same number).
  3. Add or subtract the numerators; keep the denominator.
  4. Simplify, and change an improper answer to a mixed numeral.
Example 1 — Adding with an LCD
Work out \(\dfrac{2}{3} + \dfrac{3}{4}\).
Solution
\(\dfrac{2}{3} + \dfrac{3}{4}\)\(=\)\(\dfrac{8}{12} + \dfrac{9}{12}\)
\(\)\(=\)\(\dfrac{17}{12}\)
\(\)\(=\)\(1\dfrac{5}{12}\)
2/3+3/4=8/12+9/12=17/12=15/12

\(1\dfrac{5}{12}\)

Example 2 — Subtracting
Work out \(\dfrac{2}{3} - \dfrac{5}{9}\).
Solution
\(\dfrac{2}{3} - \dfrac{5}{9}\)\(=\)\(\dfrac{6}{9} - \dfrac{5}{9}\)
\(\)\(=\)\(\dfrac{1}{9}\)
2/3−5/9=6/9−5/9=1/9

\(9\) is a multiple of \(3\), so the LCD is \(9\).

Example 3 — Same denominator
Work out \(\dfrac{11}{12} - \dfrac{5}{12}\) in simplest form.
Solution
\(\dfrac{11}{12} - \dfrac{5}{12}\)\(=\)\(\dfrac{6}{12}\)
\(\)\(=\)\(\dfrac{1}{2}\)
11/12−5/12=6/12=1/2

\(\dfrac{1}{2}\)

Example 4 — Related denominators
Work out \(\dfrac{7}{10} + \dfrac{1}{2}\).
Solution
\(\dfrac{7}{10} + \dfrac{1}{2}\)\(=\)\(\dfrac{7}{10} + \dfrac{5}{10}\)
\(\)\(=\)\(\dfrac{12}{10} = \dfrac{6}{5}\)
\(\)\(=\)\(1\dfrac{1}{5}\)
7/10+1/2=12/10=6/5=11/5

\(1\dfrac{1}{5}\)

Example 5 — List the multiples
Work out \(\dfrac{5}{6} - \dfrac{3}{8}\).
Solution

Multiples of \(6\): \(6, 12, 18, 24\). Multiples of \(8\): \(8, 16, 24\). The LCD is \(24\).

\(\dfrac{5}{6} - \dfrac{3}{8}\)\(=\)\(\dfrac{20}{24} - \dfrac{9}{24}\)
\(\)\(=\)\(\dfrac{11}{24}\)
5/6−3/8=20/24−9/24=11/24

\(\dfrac{11}{24}\)

Example 6 — What is left?
Zoe has a \(2\) L bottle of juice. She pours \(\dfrac{3}{4}\) L for her friends and \(\dfrac{2}{3}\) L for herself. How much is left?
Solution
\(\dfrac{3}{4} + \dfrac{2}{3}\)\(=\)\(\dfrac{9}{12} + \dfrac{8}{12} = \dfrac{17}{12}\)
\(2 - \dfrac{17}{12}\)\(=\)\(\dfrac{24}{12} - \dfrac{17}{12}\)
\(\)\(=\)\(\dfrac{7}{12}\)
3/4+2/3=17/12,2−17/12=7/12

\(\dfrac{7}{12}\) L is left.

Common pitfalls

Adding the denominators. \(\dfrac{1}{2} + \dfrac{1}{3}\) is not \(\dfrac{2}{5}\). It is \(\dfrac{3}{6} + \dfrac{2}{6} = \dfrac{5}{6}\).
Changing only the bottom. \(\dfrac{1}{4} = \dfrac{2}{8}\), not \(\dfrac{1}{8}\).
Not simplifying. \(\dfrac{5}{12} + \dfrac{1}{4} = \dfrac{8}{12} = \dfrac{2}{3}\).
Taking from a whole wrongly. \(1 - \dfrac{2}{7} = \dfrac{7}{7} - \dfrac{2}{7} = \dfrac{5}{7}\), not \(\dfrac{1}{7}\).

Frequently asked questions

Can you add fractions with different denominators?

Only after renaming them with a common denominator.

How do you find the lowest common denominator?

Find the smallest number both denominators divide into. For \(6\) and \(8\) it is \(24\).

Do you add the denominators?

No. Keep the common denominator and add only the numerators.

How do you subtract a fraction from 1?

Write \(1\) with the same denominator. \(1 - \dfrac{2}{7} = \dfrac{5}{7}\).

What if the answer is an improper fraction?

Write it as a mixed numeral. \(\dfrac{17}{12} = 1\dfrac{5}{12}\).