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Year 9 Maths Core Surface Area and Volume

Surface Area of a Prism

20 practice questions 1 video lesson Theory + worked examples

The surface area of a prism is the total area of all its faces, the amount of material needed to cover it. This NSW Year 9 Core maths subtopic is Stage 5 Core content under NESA outcome MA5‑ARE‑C‑01, covering cubes, rectangular and triangular prisms and other right prisms.

You will identify the faces from a diagram or a net, use the two-of-each shortcut for a rectangular prism, and find a triangular prism's surface area as two triangles plus three rectangles, using Pythagoras' theorem for a missing slant edge. You will also leave a face off for an open box or trough, recognise a valid net, work back from a cube's surface area to its edge, and cost the paint for a wooden crate. It is part of Year 9 Core Surface Area and Volume.

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Theory

The surface area of a prism is the total area of all its faces. This Year 9 maths page uses nets to find the surface area of cubes, rectangular prisms and triangular prisms, handles open boxes and missing edges, and works backwards from a surface area to an edge length.

A prism is a solid with two identical, parallel ends joined by flat faces. The shape of the ends is the cross-section. In a right prism, the kind on this page, those faces are rectangles that meet the ends at right angles.

The surface area (SA) is the total area of all the faces. It is measured in square units, such as \(\text{cm}^2\).

A net is the solid unfolded flat. Drawing it shows every face, so none is missed.

A cube has \(6\) faces, a rectangular prism \(6\) and a triangular prism \(5\): \(2\) triangles and \(3\) rectangles. An open solid is missing a face, such as the lid of a box.

Net of a rectangular prismThe net of a rectangular prism: a base with a front, back, two ends and a top folded out around it. Six faces in three matching pairs. base back front end end top
A rectangular prism unfolds into six faces in three matching pairs: \(SA = 2(lb + lh + bh)\).
Net of a triangular prismThe net of a triangular prism: three rectangles side by side, one for each side of the triangle, with a red triangle at each end. 3 rectangles 2 triangles
A triangular prism unfolds into two triangles and three rectangles. Each rectangle's width is one side of the triangle.
\[SA_{\text{cube}} = 6s^2 \qquad SA_{\text{rectangular prism}} = 2(lb + lh + bh)\]
SA=2(lb+lh+bh)

Any right prism, including a triangular, trapezium or L-shaped prism:

\[SA = 2 \times \text{(area of the end)} + \text{(perimeter of the end)} \times \text{length}\]
SA=2×end area+end perimeter×length
A missing edge. If the sloping side of a triangular end is not given, use Pythagoras first. An isosceles end splits into two right-angled triangles to find its height.
Open solids. Leave out the missing face. An open box has \(5\) faces; a trough with no top made from a triangular prism has \(4\).
Cost. Find the surface area, then multiply by the price per square metre. A closed box \(2\) m by \(1.5\) m by \(0.6\) m has \(SA = 2(3 + 1.2 + 0.9) = 10.2 \text{ m}^2\); at $20 per square metre that is $204.

How to find the surface area of a prism

  1. Sketch the net, or list the faces: two ends and one rectangle for each side of the end.
  2. Find any missing lengths, such as a sloping edge, with Pythagoras.
  3. Work out the area of each face. Matching faces can be doubled.
  4. Leave out any face that is not there, such as a missing lid.
  5. Add the areas and give the answer in square units.
Example 1 β€” A rectangular prism
Find the surface area of a rectangular prism \(9\) cm by \(6\) cm by \(4\) cm.
Solution
A rectangular prism 9 cm by 6 cm by 4 cmA closed rectangular prism 9 cm long, 6 cm deep and 4 cm high. 9 cm 6 cm 4 cm

The six faces come in three matching pairs. Work out one of each pair.

\(9 \times 6\)\(=\)\(54\)
\(9 \times 4\)\(=\)\(36\)
\(6 \times 4\)\(=\)\(24\)

Add them, then double.

\(SA\)\(=\)\(2 \times (54 + 36 + 24)\)
\(\)\(=\)\(2 \times 114 = \mathbf{228} \text{ cm}^2\)
SA=2(54+36+24)=228
Example 2 β€” An open box
A box is \(15\) cm long, \(10\) cm wide and \(8\) cm high. It has no lid. Find its surface area.
Solution
An open box 15 cm by 10 cm by 8 cmA box 15 cm long, 10 cm wide and 8 cm high. The top is missing, shown as a dashed red outline. 15 cm 10 cm 8 cm open

With no lid there are five faces, not six. List the ones that are there.

\(\text{base}\)\(=\)\(15 \times 10 = 150\)
\(\text{2 long sides}\)\(=\)\(2 \times 15 \times 8 = 240\)
\(\text{2 ends}\)\(=\)\(2 \times 10 \times 8 = 160\)
\(SA\)\(=\)\(150 + 240 + 160\)
\(\)\(=\)\(\mathbf{550} \text{ cm}^2\)
SA=150+240+160=550

A closed box would add another \(150 \text{ cm}^2\) for the lid.

Example 3 β€” A triangular prism
A triangular prism is \(7\) cm long. Its ends are right-angled triangles with shorter sides \(9\) cm and \(12\) cm. Find its surface area.
Solution
A triangular prism 7 cm long with a 9-12 right-angled endA triangular prism. Each end is a right-angled triangle with shorter sides 9 cm and 12 cm; the sloping side is unknown and marked in red. The prism is 7 cm long. 9 cm 12 cm 7 cm ?

The sloping side of the triangle is not given. Find it with Pythagoras.

\(c^2\)\(=\)\(9^2 + 12^2 = 225\)
\(c\)\(=\)\(15 \text{ cm}\)

Two triangular ends, then three rectangles, each \(7\) cm long.

\(\text{ends}\)\(=\)\(2 \times \dfrac{1}{2} \times 9 \times 12 = 108\)
\(\text{rectangles}\)\(=\)\((9 + 12 + 15) \times 7 = 252\)
\(SA\)\(=\)\(108 + 252 = \mathbf{360} \text{ cm}^2\)
SA=108+36×7=360
Example 4 β€” Cubes, forwards and backwards

(i) Find the surface area of a cube with edges of \(7\) cm.
(ii) Another cube has a surface area of \(384 \text{ cm}^2\). How long is each edge?
Solution
A cube with edge sA cube. Every edge has the same length s. s

(i) A cube has six identical square faces.

\(SA\)\(=\)\(6s^2 = 6 \times 7^2\)
\(\)\(=\)\(6 \times 49 = \mathbf{294} \text{ cm}^2\)

(ii) Undo the steps: divide by \(6\) to get one face, then take the square root.

\(6s^2\)\(=\)\(384\)
\(s^2\)\(=\)\(64\)
\(s\)\(=\)\(\sqrt{64} = \mathbf{8} \text{ cm}\)
6s2=384⇒s=8

Common pitfalls

Count every face. A rectangular prism has six faces, not four. Sketching the net stops one being forgotten.
Open at the top removes one face only. The other five faces are still there.
Use the right widths on a triangular prism. The three rectangles have different widths: one for each side of the triangle, including the sloping side.
Surface area is in square units. Even though the object is solid, its surface area is an area: \(\text{cm}^2\) or \(\text{m}^2\).

Frequently asked questions

What is the surface area of a prism?

It is the total area of all the faces of the prism: the two ends plus the rectangles that join them.

How do you find the surface area of a rectangular prism?

Find the three different faces, add them, then double: \(SA = 2(lb + lh + bh)\). A \(9\) by \(6\) by \(4\) cm prism has \(SA = 228 \text{ cm}^2\).

How do you find the surface area of a triangular prism?

Add the two triangular ends to the three rectangles. Each rectangle is as long as the prism and as wide as one side of the triangle.

What is a net of a prism?

A net is the prism unfolded into a flat shape. It shows every face at once, which makes it easy to add up the surface area.

How do you find the side of a cube from its surface area?

Divide the surface area by \(6\) to get one face, then take the square root. \(384 \div 6 = 64\), so the edge is \(8\) cm.