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Year 9 Maths Advanced Properties of Geometric Figures

Quadrilateral Geometry

20 practice questions 2 video lessons Theory + worked examples

Each special quadrilateral has its own angle and diagonal properties: a parallelogram's opposite angles are equal, a rhombus's diagonals meet at right angles, and a kite has one pair of equal angles. This NSW Year 9 Advanced maths subtopic revises them from Stage 4 (NESA outcome MA4‑GEO‑C‑01).

You will find unknown angles in kites, rhombuses, rectangles, squares and parallelograms, using the angle sum of \(360^\circ\) and giving reasons. You will form equations for angles in a parallelogram and a kite, find an angle made by an equilateral triangle inside a square, prove that opposite angles of a parallelogram are equal, and use an angle bisector to find a length. It is part of Year 9 Advanced Properties of Geometric Figures.

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  • Quadrilateral Geometry - Video - Finding the exterior angle of a quadrilateral Watch
  • Quadrilateral Geometry - Video - Finding Missing Angles in a Parallelogram Watch
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Theory

Every quadrilateral has an angle sum of \(360^\circ\), and the special quadrilaterals add properties of their own: parallel sides, equal sides and diagonals that bisect or meet at right angles. This Year 9 Advanced maths page revises the earlier properties of parallelograms, rectangles, rhombuses, squares, kites and trapeziums, and uses them in multi-step angle problems with a reason for each step.

A quadrilateral is a closed shape with four straight sides. A diagonal splits it into two triangles, so its angles add to \(2 \times 180^\circ = 360^\circ\).

A parallelogram has both pairs of opposite sides parallel. A rectangle is a parallelogram with right angles, a rhombus is a parallelogram with four equal sides, and a square is both. A kite has two pairs of equal adjacent sides. A trapezium has at least one pair of parallel sides.

Most angle questions combine three kinds of fact: parallel lines (alternate angles are equal, co-interior angles add to \(180^\circ\)), triangles (angle sum \(180^\circ\), equal angles opposite equal sides) and the diagonal properties of the shape.

A diagonal of a rectangle or square is cut in half by the other diagonal. So the four half-diagonals are equal, and the diagonals make isosceles triangles. In a rhombus the diagonals also bisect the angles and cross at \(90^\circ\).

In geometry answers, every step needs a short reason in brackets, for example (co-interior angles, \(AB \parallel DC\)).

Angles of a parallelogramParallelogram ABCD with angles 70, 110, 70 and 110 degrees. Opposite angles are equal and each pair of neighbouring angles adds to 180 degrees. 70° 110° 70° 110° A B C D
In a parallelogram, opposite angles are equal and co-interior angles add to \(180^\circ\): \(70^\circ + 110^\circ = 180^\circ\).
Diagonals of a rhombusA rhombus with both diagonals drawn dashed. They cross at right angles, cut each other in half and halve each angle of the rhombus into two equal parts alpha and beta. α α β β
The diagonals of a rhombus meet at right angles and bisect each angle of the rhombus.

Angle facts used in quadrilateral problems:

\[\angle A + \angle B + \angle C + \angle D = 360^\circ\]
A+B+C+D=360°
\[\text{co-interior: } a + b = 180^\circ \qquad \text{alternate: } a = b\]
a+b=180

Properties of the special quadrilaterals:

ShapeSidesAnglesDiagonals
Parallelogramopposite sides parallel and equalopposite angles equalbisect each other
Rectangleopposite sides parallel and equalall \(90^\circ\)equal, bisect each other
Rhombusall four equal, opposite sides parallelopposite angles equalbisect each other at \(90^\circ\), bisect the angles
Squareall four equal, opposite sides parallelall \(90^\circ\)equal, bisect each other at \(90^\circ\), make \(45^\circ\) with the sides
Kitetwo pairs of equal adjacent sidesone pair of equal angles, between the unequal sidesmeet at \(90^\circ\); the axis of symmetry bisects the other diagonal
Trapeziumone pair of parallel sidesco-interior angles between the parallel sides add to \(180^\circ\)no special property
Exterior angle of a triangle. An exterior angle equals the sum of the two interior opposite angles. It is a quick way through a triangle formed by the diagonals.
Angles opposite equal sides are equal. Two equal half-diagonals, or a side of a square next to a side of an equilateral triangle, give an isosceles triangle with equal base angles. It works backwards too: if two angles of a triangle are equal, the sides opposite them are equal. An angle bisector that meets a parallel side often makes two equal angles (alternate angles), and so an isosceles triangle with a length you can find.

How to find an unknown angle in a quadrilateral

  1. Name the shape and mark everything you know on the diagram: parallel sides, equal sides, right angles.
  2. List the properties of that shape that involve angles or diagonals (see the Formulas table).
  3. Find a triangle or a pair of parallel lines that contains the unknown and at least two known facts.
  4. Write each step with its reason. When the angles are expressions, set up one equation and solve it.
  5. Check that the four angles add to \(360^\circ\), or that each triangle adds to \(180^\circ\).

Writing reasons

  1. Parallel lines: (alternate angles, \(AB \parallel DC\)), (co-interior angles, \(AD \parallel BC\)).
  2. Shapes: (opposite angles of a parallelogram), (diagonals of a rhombus bisect its angles), (diagonals of a rectangle are equal and bisect each other).
  3. Triangles: (angle sum of a triangle), (angles opposite equal sides), (exterior angle of a triangle).
  4. To prove a property, start from facts you are given, never from the result you are trying to show. For example, opposite angles of a parallelogram are equal because each one is \(180^\circ\) minus the same neighbouring angle (co-interior angles twice).
Example 1 — Diagonals of a rhombus
\(WXYZ\) is a rhombus with \(\angle ZWX = 76^\circ\). Its diagonals meet at \(M\). Find, giving reasons:
(i) \(\angle WXZ\)
(ii) \(\angle MWX\).
Solution
Rhombus WXYZ with its diagonalsRhombus WXYZ with diagonals WY and XZ crossing at M at right angles. The angle at W is 76 degrees and the angle WXZ is to be found. 76° ? W X Y Z M

(i) First find the whole angle at \(X\), then halve it.

\(\angle WXY\)\(=\)\(180^\circ - 76^\circ\)
\(\)\(=\)\(104^\circ\)

(co-interior angles, \(WZ \parallel XY\))

\(\angle WXZ\)\(=\)\(\dfrac{104^\circ}{2}\)
\(\)\(=\)\(\mathbf{52^\circ}\)

(the diagonals of a rhombus bisect its angles)

∠WXZ=180−762=52

(ii) The diagonal \(WY\) bisects \(\angle ZWX\).

\(\angle MWX\)\(=\)\(\dfrac{76^\circ}{2}\)
\(\)\(=\)\(\mathbf{38^\circ}\)
∠MWX=38

Check in \(\triangle WMX\), where the diagonals meet at \(90^\circ\): \(38^\circ + 52^\circ + 90^\circ = 180^\circ\).

Example 2 — Angles of a kite
\(PQRS\) is a kite with \(PQ = PS\) and \(RQ = RS\). \(\angle QPS = 58^\circ\) and \(\angle QRS = 84^\circ\). Find the size of \(\angle PQR\).
Solution
Kite PQRSKite PQRS with PQ equal to PS and RQ equal to RS. The angle at P is 58 degrees, the angle at R is 84 degrees, and the equal angles at Q and S are marked x. 58° 84° x x P Q R S

A kite has one pair of equal angles: the two between the unequal sides, at \(Q\) and \(S\). Call each one \(x\) and use the angle sum of a quadrilateral.

\(58 + 84 + x + x\)\(=\)\(360\)
\(142 + 2x\)\(=\)\(360\)
\(2x\)\(=\)\(218\)
\(x\)\(=\)\(109\)
58+84+2x=360,x=109

\(\therefore\ \angle PQR = \mathbf{109^\circ}\) (angle sum of a quadrilateral, equal angles of a kite).

The \(58^\circ\) and \(84^\circ\) angles sit on the axis of symmetry \(PR\). They are not equal to each other.

Example 3 — Angles as expressions
\(ABCD\) is a parallelogram with \(\angle DAB = (2x + 15)^\circ\) and \(\angle ABC = (3x - 5)^\circ\). Find \(x\) and all four angles of \(ABCD\).
Solution
Parallelogram ABCD with angles in terms of xParallelogram ABCD. The angle at A is 2x plus 15 degrees and the angle at B is 3x minus 5 degrees. (2x + 15)° (3x − 5)° A B C D

\(\angle DAB\) and \(\angle ABC\) are neighbouring angles, so they are co-interior angles between the parallel sides \(AD\) and \(BC\). They add to \(180^\circ\).

\((2x + 15) + (3x - 5)\)\(=\)\(180\)
\(5x + 10\)\(=\)\(180\)
\(5x\)\(=\)\(170\)
\(x\)\(=\)\(\mathbf{34}\)
2x+15+3x−5=180,x=34
\(\angle DAB\)\(=\)\(2(34) + 15 = 83^\circ\)
\(\angle ABC\)\(=\)\(3(34) - 5 = 97^\circ\)

Opposite angles of a parallelogram are equal, so \(\angle BCD = \mathbf{83^\circ}\) and \(\angle CDA = \mathbf{97^\circ}\).

Check: \(83 + 97 + 83 + 97 = 360\).

Example 4 — Isosceles triangles inside a figure
\(ABCD\) is a square. The equilateral triangle \(DCE\) is drawn on \(DC\), outside the square, and \(E\) is joined to \(A\) and to \(B\). Find \(\angle AEB\), giving reasons.
Solution
Square ABCD with an equilateral triangle DCE outside itSquare ABCD with the equilateral triangle DCE drawn below side DC, outside the square. E is joined to A and to B, and the angle AEB is to be found. All seven marked sides are equal. ? A B C D E

Look for equal sides: \(AD = DC\) (square) and \(DC = DE\) (equilateral triangle), so \(AD = DE\) and \(\triangle ADE\) is isosceles.

\(\angle ADE\)\(=\)\(90^\circ + 60^\circ = 150^\circ\)
\(\angle DEA\)\(=\)\(\dfrac{180^\circ - 150^\circ}{2}\)
\(\)\(=\)\(15^\circ\)

(angles opposite equal sides, angle sum of a triangle)

∠DEA=180−1502=15

In the same way \(\triangle BCE\) is isosceles, so \(\angle CEB = 15^\circ\). The angle of the equilateral triangle at \(E\) is \(60^\circ\).

\(\angle AEB\)\(=\)\(60^\circ - 15^\circ - 15^\circ\)
\(\)\(=\)\(\mathbf{30^\circ}\)
∠AEB=60−15−15=30

Common pitfalls

Kite angles. The equal angles of a kite are the two between the unequal sides. The two angles on the axis of symmetry are usually different.
Rhombus, not rectangle. Only the diagonals of a rhombus or square bisect the angles. The diagonals of a rectangle do not, unless it is a square.
Co-interior or alternate? Co-interior angles sit on the same side of the transversal, between the parallel lines, and add to \(180^\circ\). Alternate angles make a Z shape and are equal. Mixing them up gives \(180^\circ - x\) instead of \(x\).
Halve or double? A diagonal of a rhombus bisects an angle, so each part is half. Check which one the question asks for: the whole angle or one part.
Expressions are not angles. After finding \(x\), substitute back to find the angle the question asks for. \(x = 34\) is not the answer when the angle is \((2x + 15)^\circ\).

Frequently asked questions

What are the properties of a rhombus?

A rhombus has four equal sides and both pairs of opposite sides parallel. Its opposite angles are equal, and its diagonals bisect each other at right angles and bisect the angles of the rhombus.

Do the diagonals of a rectangle bisect its angles?

No. The diagonals of a rectangle are equal and bisect each other, but they only bisect the angles when the rectangle is a square. They do make isosceles triangles, because the four half-diagonals are equal.

What is the difference between a kite and a rhombus?

A kite has two pairs of equal sides that are next to each other. A rhombus has all four sides equal. Every rhombus is a kite, but most kites are not rhombuses because their sides are not all equal and they have no parallel sides.

How do you find a missing angle in a quadrilateral?

Add the known angles and subtract from \(360^\circ\). If the angles are expressions, add them, set the total equal to \(360\) and solve. For special quadrilaterals use their properties too, such as equal opposite angles in a parallelogram.

Is a square a rhombus?

Yes. A square has four equal sides, so it is a rhombus. It is also a rectangle, a parallelogram and a kite, so it has every property of those shapes.

Why are opposite angles of a parallelogram equal?

Each angle and its neighbour are co-interior angles between parallel sides, so they add to \(180^\circ\). Two opposite angles are both \(180^\circ\) minus the same neighbouring angle, so they are equal.