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Year 9 Maths Advanced Properties of Geometric Figures

Line and Rotational Symmetry

20 practice questions 2 video lessons Theory + worked examples

A shape has line symmetry if a fold line makes the two halves match, and rotational symmetry of order \(n\) if it fits onto itself \(n\) times in one full turn. This NSW Year 9 Advanced maths subtopic covers symmetry in shapes and graphs (NESA outcome MA5‑LIN‑P‑01).

You will state the order of rotational symmetry and the axes of symmetry of polygons, letters, quadrilaterals and tetrominoes, and find the smallest angle of turn. You will describe the symmetry of the graphs of \(y = x^2 - 4\), \(y = x^3\) and \(y = \frac{1}{x}\), use symmetry to find points on a parabola, complete a pattern with order \(4\), and explain why two perpendicular lines of symmetry give a half-turn. It is part of Year 9 Advanced Properties of Geometric Figures.

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  • Line and Rotational Symmetry - Video - Lines of Symmetry Watch
  • Line and Rotational Symmetry - Video - Order of Rotational Symmetry Watch
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Theory

A shape has line symmetry when a mirror line folds it onto itself, and rotational symmetry when a turn of less than \(360^\circ\) fits it onto itself. This Year 9 Advanced maths page covers the order of rotational symmetry, axes of symmetry of regular polygons, and the symmetry of graphs such as parabolas, cubics and hyperbolas, using coordinates. It is useful if you are heading for Advanced maths.

A shape has line symmetry if it can be folded along a line so that the two halves match exactly. That line is an axis of symmetry (or line of symmetry). A shape can have none, one or several.

A shape has rotational symmetry if a turn about a fixed point, the centre of rotation, fits it exactly onto itself before a full turn. The order of rotational symmetry is the number of times it fits onto itself in one full turn of \(360^\circ\), counting the full turn. A shape that only fits after a full turn has order \(1\), which means no rotational symmetry.

A regular polygon with \(n\) sides has \(n\) axes of symmetry and rotational symmetry of order \(n\). If \(n\) is odd, each axis joins a vertex to the midpoint of the opposite side. If \(n\) is even, half the axes join opposite vertices and half join the midpoints of opposite sides.

Graphs on the number plane can be symmetric too. A parabola has one vertical axis of symmetry through its turning point. Rotational symmetry of order \(2\) about the origin is also called point symmetry: every point \((x, y)\) on the graph has a partner \((-x, -y)\).

Line symmetry and rotational symmetry are separate properties. A shape can have one without the other.

Symmetries of a regular octagonA regular octagon with its eight axes of symmetry drawn dashed: four through opposite vertices and four through the midpoints of opposite sides. A curved arrow about the centre shows a turn of 45 degrees, which fits the octagon onto itself. 45Β°
A regular octagon has \(8\) axes of symmetry and rotational symmetry of order \(8\): it fits onto itself every \(\dfrac{360^\circ}{8} = 45^\circ\).
A parallelogram has rotational symmetry of order 2A parallelogram with its diagonals dashed. A half-turn of 180 degrees about the point where the diagonals cross fits it onto itself, but no mirror line does. 180Β°
This parallelogram fits onto itself after a half-turn about its centre (order \(2\)), but it has no axis of symmetry.

If a shape has rotational symmetry of order \(n\), the smallest turn that fits it onto itself is:

\[\text{smallest angle} = \dfrac{360^\circ}{n}\]
angle=360n

Coordinate rules for testing a graph or completing a shape:

SymmetryPoint \((x, y)\) goes to
axis: the \(y\)-axis (\(x = 0\))\((-x, y)\)
axis: the \(x\)-axis (\(y = 0\))\((x, -y)\)
axis: the line \(y = x\)\((y, x)\)
axis: the line \(y = -x\)\((-y, -x)\)
half-turn about \(O\) (order \(2\))\((-x, -y)\)
quarter-turn about \(O\), anticlockwise\((-y, x)\)
Axis of a parabola. The axis of symmetry is the vertical line halfway between any two points with the same \(y\)-value, for example the \(x\)-intercepts: \(x = \dfrac{x_1 + x_2}{2}\). Points the same distance either side of it have the same \(y\)-value.
Reflecting a graph. To reflect a graph in the \(y\)-axis, replace \(x\) by \(-x\) in its equation. To reflect it in the \(x\)-axis, replace \(y\) by \(-y\).
Two reflections in a row. Reflecting in the \(x\)-axis and then in the \(y\)-axis sends \((x, y) \to (x, -y) \to (-x, -y)\): the same as a half-turn about \(O\). Two mirror lines at right angles always combine to a half-turn about the point where they cross.

How to find the symmetries of a shape

  1. Lines: try each possible fold line: through vertices, through midpoints of sides, horizontal, vertical and diagonal. Count only the ones where the halves match exactly.
  2. Rotation: find the centre, then the smallest turn that fits the shape onto itself. The order is \(360^\circ\) divided by that turn.
  3. Combined figures: a symmetry of the whole figure must fit every part onto itself, so it can only be a symmetry that the parts share.
  4. Patterns on a grid: for order \(4\), every shaded square must appear again after turns of \(90^\circ\), \(180^\circ\) and \(270^\circ\). Shade each square's three images, and count only squares not already shaded.

How to test a graph

  1. Use a rule from the Formulas table, for example \((x, y) \to (-x, -y)\) for order \(2\) about \(O\).
  2. Substitute into the equation and simplify, or test a few points.
  3. To show a symmetry is missing, one point that fails is enough. A single example that breaks a claim is called a counterexample.
Example 1 β€” Symmetry of a regular polygon
Each interior angle of a regular polygon is \(150^\circ\). State
(i) its number of axes of symmetry
(ii) its order of rotational symmetry
(iii) the smallest angle it can be turned through to fit onto itself.
Solution

Find the number of sides first, using the exterior angle.

\(\text{exterior}\)\(=\)\(180^\circ - 150^\circ = 30^\circ\)
\(n\)\(=\)\(\dfrac{360}{30} = 12\)
n=36030=12
Regular 12-sided polygonA regular 12-sided polygon with two of its axes of symmetry dashed, one through opposite vertices and one through the midpoints of opposite sides. Two radii from the centre to neighbouring vertices make a 30 degree angle. 30Β°

A regular polygon with \(n\) sides has \(n\) axes of symmetry and rotational symmetry of order \(n\).

(i) \(\mathbf{12}\) axes: \(6\) through opposite vertices and \(6\) through the midpoints of opposite sides.

(ii) order \(\mathbf{12}\)

\(\text{(iii) smallest turn}\)\(=\)\(\dfrac{360^\circ}{12} = \mathbf{30^\circ}\)
36012=30
Example 2 β€” Completing a shape
A hexagon has rotational symmetry of order \(2\) about the origin \(O\). Three of its vertices are \(A(1, 3)\), \(B(4, 1)\) and \(C(2, -1)\), and the other three are their images.
(i) Find the other three vertices.
(ii) Is the \(y\)-axis an axis of symmetry of the hexagon?
Solution

(i) Order \(2\) means a half-turn (\(180^\circ\)) about \(O\) fits the hexagon onto itself. A half-turn about \(O\) changes the sign of both coordinates: \((x, y) \to (-x, -y)\).

\(A(1, 3)\)\(\to\)\(A'(-1, -3)\)
\(B(4, 1)\)\(\to\)\(B'(-4, -1)\)
\(C(2, -1)\)\(\to\)\(C'(-2, 1)\)
(x,y)→(−x,−y)
Hexagon with rotational symmetry of order 2On a number plane, the vertices A(1, 3), B(4, 1) and C(2, -1) and their images A prime(-1, -3), B prime(-4, -1) and C prime(-2, 1) under a half-turn about the origin form a hexagon. x y βˆ’4 βˆ’2 2 4 βˆ’4 βˆ’2 2 4 O A B C Aβ€² Bβ€² Cβ€²

(ii) Reflecting in the \(y\)-axis sends \((x, y) \to (-x, y)\), so \(A(1, 3)\) would go to \((-1, 3)\). That point is not a vertex, so the \(y\)-axis is not an axis of symmetry.

Example 3 β€” Axis of symmetry of a parabola
The parabola \(y = x^2 + 2x - 8\) crosses the \(x\)-axis at \(x = -4\) and \(x = 2\).
(i) Find the equation of its axis of symmetry.
(ii) The point \((1, -5)\) is on the parabola. Use symmetry to find another point with \(y = -5\).
Solution
Parabola y = x squared plus 2x minus 8 with its axis of symmetryThe parabola crosses the x-axis at -4 and 2. Its axis of symmetry, the dashed line x = -1, is halfway between. The point (1, -5) and its mirror image (-3, -5) are the same distance from the axis. x y βˆ’6 βˆ’4 βˆ’2 2 4 βˆ’8 βˆ’4 O (1, βˆ’5) (βˆ’3, βˆ’5) x = βˆ’1

(i) The axis of symmetry is halfway between the \(x\)-intercepts.

\(x\)\(=\)\(\dfrac{-4 + 2}{2}\)
\(\)\(=\)\(-1\)
x=−4+22=−1

The axis is the vertical line \(\boldsymbol{x = -1}\).

(ii) \((1, -5)\) is \(2\) units to the right of \(x = -1\). Its mirror image is \(2\) units to the left, at \(x = -3\), with the same \(y\)-value: \(\boldsymbol{(-3, -5)}\).

\(\text{Check: } (-3)^2 + 2(-3) - 8\)\(=\)\(9 - 6 - 8 = -5\)
Example 4 β€” Symmetry of a graph
Show that the graph of \(y = x^3 - 4x\) has rotational symmetry of order \(2\) about the origin, and that the \(y\)-axis is not an axis of symmetry.
Solution
Graph of y = x cubed minus 4xThe cubic y = x cubed minus 4x. The point (1, -3) and the point (-1, 3) are joined through the origin, showing the half-turn symmetry. The point (-1, -3), shown as an empty circle, is not on the graph. x y βˆ’3 βˆ’2 βˆ’1 1 2 3 βˆ’4 βˆ’2 2 4 O (1, βˆ’3) (βˆ’1, 3) (βˆ’1, βˆ’3)

A half-turn about \(O\) sends \((x, y) \to (-x, -y)\). Replace \(x\) by \(-x\) and compare with \(-y\).

\((-x)^3 - 4(-x)\)\(=\)\(-x^3 + 4x\)
\(\)\(=\)\(-(x^3 - 4x)\)
(−x)3−4(−x)=−(x3−4x)

So whenever \((x, y)\) is on the graph, \((-x, -y)\) is too. For example \((1, -3) \to (-1, 3)\). The graph fits onto itself after \(180^\circ\) and \(360^\circ\): order 2.

For the \(y\)-axis, \((1, -3)\) would reflect to \((-1, -3)\). But \(x = -1\) gives \(y = -1 + 4 = 3\), not \(-3\). One point that fails is enough: the \(y\)-axis is not an axis of symmetry.

Common pitfalls

Order 1, not 0. Every shape fits onto itself after a full turn, so the smallest possible order is \(1\). Order \(1\) means no rotational symmetry.
Axes through midpoints too. A regular octagon has \(8\) axes, not \(4\): four through opposite vertices and four through midpoints of opposite sides.
Diagonals are not always axes. The diagonals of a rectangle are not axes of symmetry (folding along one does not match the halves), even though they look like it.
Write the axis as an equation. A vertical axis is \(x = a\), not \(y = a\). The \(y\)-axis itself is the line \(x = 0\).
Rotational does not mean line symmetry. A parallelogram has order \(2\) and no axes. Check each kind of symmetry separately.

Frequently asked questions

What is the order of rotational symmetry?

It is the number of times a shape fits exactly onto itself during one full turn of \(360^\circ\), counting the full turn. A square has order \(4\) because it fits every \(90^\circ\).

How many lines of symmetry does a regular polygon have?

A regular polygon with \(n\) sides has \(n\) lines of symmetry. A regular octagon has \(8\), and it also has rotational symmetry of order \(8\).

Can a shape have rotational symmetry but no line symmetry?

Yes. A parallelogram that is not a rectangle or rhombus fits onto itself after a half-turn, so it has rotational symmetry of order \(2\), but no fold line matches its halves.

How do you find the axis of symmetry of a parabola?

Find two points on the parabola with the same \(y\)-value, such as the \(x\)-intercepts, and take the \(x\)-value halfway between them. The axis is the vertical line through that value, for example \(x = -1\).

What does point symmetry mean for a graph?

A graph has point symmetry about the origin when turning it \(180^\circ\) about the origin fits it onto itself. Algebraically, whenever \((x, y)\) is on the graph, \((-x, -y)\) is on it too.

Does a circle have rotational symmetry?

Yes. A circle fits onto itself after a turn of any angle about its centre, and every line through its centre is an axis of symmetry, so it has infinitely many of each.