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Year 9 Maths Advanced Congruence and Similar Figures

Tests for Similar Triangles

20 practice questions 4 video lessons Theory + worked examples

Two triangles are similar when their matching angles are equal (AA), all three pairs of sides are in the same ratio (SSS), or two pairs of sides are in the same ratio with equal included angles (SAS). This NSW Year 9 Advanced maths subtopic uses these tests (NESA outcome MA5‑GEO‑P‑01).

You will name the test for a pair of triangles, write the similarity statement and use the scale factor to find sides. You will find heights from shadows, ladders and cables, the width of a river and the length of a ramp, decide whether two sides in proportion are enough, prove that \(AB^2 = AD \times AC\), and find a tree's height by looking over a fence. It is part of Year 9 Advanced Congruence and Similar Figures.

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  • Tests for Similar Triangles - Video - Tests For Similar Triangles SSS Watch
  • Tests for Similar Triangles - Video - Tests For Similar Triangles SAS Watch
  • Tests for Similar Triangles - Video - Tests For Similar Triangles AAA Watch
  • Tests for Similar Triangles - Video - Tests For Similar Triangles RHS Watch
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Theory

Two triangles are similar when one of four tests holds: AA (equal angles), SSS, SAS or RHS with sides in the same ratio. Once triangles are proved similar, their matching sides give the unknown lengths. This Year 9 Advanced maths page shows how. It comes up if you are heading for Extension maths.

Two triangles are similar if one is an enlargement of the other. For triangles, you do not need to check every angle and every side: any one of these similarity tests is enough.

AA (also written AAA or equiangular): two pairs of equal angles. The third angles are then equal too, because the angle sum is \(180^\circ\).

SSS: all three pairs of matching sides in the same ratio. SAS: two pairs of sides in the same ratio and the included angles equal. RHS: both right-angled, with the hypotenuses and one other pair of sides in the same ratio.

Equal angles often come from a common angle, vertically opposite angles, parallel lines (alternate or corresponding angles) or right angles.

The four similarity testsFour pairs of triangles, a small one and a larger one. AA: two pairs of equal angles marked. SSS: all three sides marked. SAS: two sides and the angle between them marked. RHS: right angle, hypotenuse and one side marked. AA two pairs of equal angles SSS three sides in the same ratio SAS two sides in ratio, included angle equal RHS right angle, hyp and side in ratio
Each test is enough to prove two triangles similar. Compare them with SSS, SAS, AAS and RHS for congruence: sides are now in proportion, not equal.
A small triangle in the corner of a large oneTriangle APQ sits in the corner of triangle ABC, sharing angle A, with PQ parallel to CB. The angles at Q and B are marked equal. A B C P Q
A shared angle plus one more pair of equal angles is the most common way to get AA.

SSS: all three ratios equal.

\[\dfrac{PQ}{AB} = \dfrac{QR}{BC} = \dfrac{RP}{CA}\]
PQAB=QRBC=RPCA

SAS: two ratios equal and the angle between those sides equal.

\[\dfrac{PQ}{AB} = \dfrac{QR}{BC} \quad \text{and} \quad \angle Q = \angle B\]
PQAB=QRBC
A useful result. If \(\triangle ABD \sim \triangle ACB\) (sharing angle \(A\)), matching sides give \(\dfrac{AB}{AC} = \dfrac{AD}{AB}\), so \(AB^2 = AD \times AC\). The same kind of cross-multiplying appears with the altitude to the hypotenuse of a right-angled triangle.

How to decide if two triangles are similar

  1. Look for angles first: a common angle, right angles, vertically opposite angles, parallel lines. Two pairs of equal angles is AA.
  2. Otherwise use sides: pair the sides shortest with shortest. All three ratios equal is SSS.
  3. One angle known: check it is between the two sides, then compare those two ratios (SAS). For right-angled triangles, compare hypotenuses and one other side (RHS).
  4. Write the statement with matching vertices in order and the test in brackets.

Using similar triangles

  1. Find the scale factor from one matching pair, then multiply or divide.
  2. Overlapping triangles: redraw them separately; remember whole sides such as \(AC = AD + DC\).
  3. Not similar? One ratio that differs is enough to show it. Two equal ratios is not enough without the included angle.
  4. Real problems (shadows, ladders, mirrors, lines of sight): find two triangles with a right angle and another equal angle. For a line of sight, measure heights from eye level.
Example 1 — Choosing the test
Show that each pair of triangles is similar and name the test.
Solution
Three pairs of triangles(i) Triangles with sides 5, 7, 8 and 12.5, 17.5, 20. (ii) Triangles with sides 9 and 6 around a 72 degree angle, and 12 and 8 around a 72 degree angle. (iii) Right-angled triangles with hypotenuse 10 and side 6, and hypotenuse 15 and side 9. (i) 5 7 8 12.5 17.5 20 (ii) 72° 72° 9 6 12 8 (iii) 10 6 15 9

(i) Pair the sides by size: \(\dfrac{12.5}{5} = \dfrac{17.5}{7} = \dfrac{20}{8} = 2.5\). SSS.

(ii) The \(72^\circ\) angle is between the sides in both, and \(\dfrac{12}{9} = \dfrac{8}{6} = \dfrac{4}{3}\). SAS.

(iii) Right angles, and hypotenuse with hypotenuse, side with side: \(\dfrac{15}{10} = \dfrac{9}{6} = 1.5\). RHS.

Example 2 — Prove, then calculate
\(\triangle ABC\) has \(\angle B = 90^\circ\), \(AB = 9\) cm and \(BC = 12\) cm. \(D\) is on \(AC\) and \(E\) is on \(BC\), with \(DE \perp BC\) and \(EC = 4\) cm.
(i) Prove that \(\triangle DEC \sim \triangle ABC\).
(ii) Find \(DE\) and \(DC\).
Solution
Right-angled triangle ABC with DE perpendicular to BCTriangle ABC is right-angled at B with AB = 9. D is on AC and E is on BC with DE perpendicular to BC, and EC = 4. A B C D E 9 4

(i) In \(\triangle DEC\) and \(\triangle ABC\):
\(\angle DEC = \angle ABC = 90^\circ\) (given)
\(\angle C\) is common
\(\therefore\ \triangle DEC \sim \triangle ABC\) (AA)

(ii) \(EC\) matches \(BC\), so \(k = \dfrac{4}{12} = \dfrac{1}{3}\). \(DE\) matches \(AB\); \(DC\) matches \(AC\).

\(DE\)\(=\)\(9 \times \dfrac{1}{3} = \mathbf{3}\text{ cm}\)
\(AC\)\(=\)\(\sqrt{9^2 + 12^2} = 15\)
\(DC\)\(=\)\(15 \times \dfrac{1}{3} = \mathbf{5}\text{ cm}\)
DE=9×13=3
Example 3 — Similar or not?
\(\triangle PQR\) has \(PQ = 8\) cm, \(QR = 10\) cm and \(\angle Q = 40^\circ\). \(\triangle XYZ\) has \(XY = 12\) cm, \(YZ = 16\) cm and \(\angle Y = 40^\circ\).
(i) Are the triangles similar?
(ii) What length of \(YZ\) would make them similar?
Solution

(i) The \(40^\circ\) angles are both between the given sides, so test SAS: the two ratios must be equal.

\(\dfrac{XY}{PQ}\)\(=\)\(\dfrac{12}{8} = 1.5\)
\(\dfrac{YZ}{QR}\)\(=\)\(\dfrac{16}{10} = 1.6\)

\(1.5 \ne 1.6\), so the triangles are not similar.

(ii) For SAS, \(YZ\) must use the same scale factor as \(XY\).

\(YZ\)\(=\)\(1.5 \times 10 = \mathbf{15}\text{ cm}\)
128≠1610
Example 4 — A mirror on the ground
To find the height \(h\) of a building, Sam puts a small mirror on level ground \(18\) m from the building. He steps back until he sees the top of the building in the mirror. He is then \(2.4\) m from the mirror and his eyes are \(1.5\) m above the ground. Light leaves a mirror at the same angle it arrives. Find \(h\).
Solution
Using a mirror to measure a buildingNot to scale. A person stands 2.4 m from a small mirror on the ground, with eyes 1.5 m high. The building is 18 m on the other side of the mirror and has height h. The light path from the top of the building to the mirror to the person's eye makes equal angles with the ground. mirror 1.5 m 2.4 m 18 m h

(The diagram is not to scale.) Both triangles have a right angle at the ground, and the angles at the mirror are equal. So the triangles are similar (AA).

\(\dfrac{h}{1.5}\)\(=\)\(\dfrac{18}{2.4}\)
\(h\)\(=\)\(1.5 \times 7.5 = \mathbf{11.25}\text{ m}\)
h1.5=182.4

Common pitfalls

Check all three ratios for SSS. Two equal ratios is not enough on its own. The third pair must give the same ratio too.
SAS needs the included angle. The equal angle has to be between the two sides you are comparing.
Similar is not congruent. The tests for similarity use sides in the same ratio. Equal sides are only the special case \(k = 1\).
Pair the sides correctly. Match shortest with shortest, or read the pairs from the equal angles. A side matches the side opposite the equal angle.
Overlapping triangles share parts. A common angle counts once for each triangle. A whole side may be made of two pieces.

Frequently asked questions

What are the tests for similar triangles?

The four tests are AA (two pairs of equal angles), SSS (three pairs of sides in the same ratio), SAS (two pairs of sides in the same ratio with equal included angles) and RHS (right angle, with hypotenuse and one side in the same ratio).

Is AAA the same as AA?

Yes. If two pairs of angles are equal, the third pair must be equal too because each triangle's angles add to \(180^\circ\). Some books write AAA or equiangular.

What is the difference between congruence tests and similarity tests?

Congruence tests need equal sides. Similarity tests need sides in the same ratio. AA is a similarity test but not a congruence test, because equal angles do not fix the size.

How do you prove two triangles are similar?

Name the two triangles, list the equal angles or the equal ratios of sides with reasons, then write the similarity statement in matching order with the test in brackets.

How do you use similar triangles to find a height?

Find two triangles with a right angle and another equal angle, such as from shadows or a mirror. Then use the ratio of matching sides to find the unknown height.