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Year 9 Maths Advanced Congruence and Similar Figures

Tests for Congruent Triangles

20 practice questions 1 video lesson Theory + worked examples

Two triangles are congruent if they match by one of four tests: SSS, SAS, AAS or RHS. This NSW Year 9 Advanced maths subtopic uses the tests to show triangles are congruent and then find unknown sides and angles (NESA outcome MA5‑GEO‑P‑01).

You will name the test for a pair of triangles, use congruence to find pronumerals, and decide whether equal angles alone, or two sides and a non-included angle, are enough. You will find the extra fact a test needs, measure a river's width with congruent triangles, find the value of \(x\) that makes two triangles congruent, and work with a kite frame. It is part of Year 9 Advanced Congruence and Similar Figures.

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Theory

Two triangles are congruent when one of four congruence tests is met: SSS, SAS, AAS or RHS. This Year 9 Advanced maths page shows how to pick the test and use it to find unknowns. It comes up if you are heading for Extension maths.

Six measurements describe a triangle: three sides and three angles. A congruence test is a set of three of them that fixes the triangle completely. If two triangles share one of these sets, they are congruent.

SSS: three pairs of sides equal. SAS: two pairs of sides and the included angle (the angle between those sides) equal. AAS: two pairs of angles and one pair of matching sides equal. RHS: both triangles have a right angle, equal hypotenuses and one other pair of sides equal.

Useful facts for spotting equal parts: a side shared by both triangles is a common side; vertically opposite angles are equal. Once two triangles are congruent, all their matching sides and angles are equal.

Two combinations are not tests. Three equal angles (AAA) gives the same shape but not always the same size. Two sides and a non-included angle can give two different triangles.

The four congruence tests for trianglesFour triangles. SSS: all three sides marked. SAS: two sides marked with the angle between them. AAS: two angles marked and one side. RHS: a right angle, the hypotenuse and one other side marked. SSS three sides SAS two sides + included angle AAS two angles + matching side RHS right angle, hypotenuse, side
Each test is the least information that fixes one triangle. Any one of them proves congruence.
Equal angles but different sizesA small triangle and a large triangle with the same three angles, shown by matching arcs. They are the same shape but not the same size.
Three equal angles (AAA) is not a test: the triangles have the same shape but can be different sizes.

The four tests:

\[\text{SSS} \qquad \text{SAS} \qquad \text{AAS} \qquad \text{RHS}\]
SSS, SAS, AAS, RHS

For RHS, the third side is fixed by Pythagoras' theorem, which is why the test works:

\[b = \sqrt{c^2 - a^2}\]
b=c2−a2
Matching sides. In congruent triangles, matching sides are opposite equal angles. The angle sum \(180^\circ\) gives the third angle, so two equal angles mean all three are equal.
Setting out. List the three pairs of equal parts, each with a reason (given, common, vertically opposite), then write the statement and the test in brackets: \(\triangle ABC \equiv \triangle DEF\) (SAS).

How to decide if two triangles are congruent

  1. Mark what is equal: given sides and angles, a common side, vertically opposite angles, and the third angle from the angle sum.
  2. Match the vertices: equal angles match; a side matches the side opposite the equal angle.
  3. Pick the test: three sides (SSS); two sides with the angle between them (SAS); two angles and a matching side (AAS); right angle, hypotenuse and side (RHS).
  4. Write the statement with the vertices in matching order and the test in brackets.

Using congruent triangles

  1. Find unknowns: set each unknown equal to its matching part, then solve. Two expressions that match also make an equation.
  2. What extra fact is needed? Work out which test is nearly complete and name the missing part, e.g. the included angle for SAS.
  3. Use Pythagoras' theorem to find a missing side in a right-angled triangle before comparing.
  4. Real problems: build a pair of congruent triangles, prove them congruent, then measure the side you can reach to find the one you cannot.
Example 1 — Choosing the test
Name the test that proves each pair of triangles congruent.
Solution
Three pairs of triangles(i) Two triangles with angles 35 and 80 degrees and a 7 cm side opposite the 80 degree angle. (ii) Two right-angled triangles with hypotenuse 15 cm and another side 9 cm. (iii) Two triangles with sides 11 cm and 6 cm and a 48 degree angle between them. (i) 7 cm35°80° 7 cm35°80° (ii) 15 cm9 cm 15 cm9 cm (iii) 11 cm6 cm48° 11 cm6 cm48°

(i) Two angles are equal, and the \(7\) cm side is opposite the \(80^\circ\) angle in both: AAS.

(ii) Right angle, equal hypotenuses (\(15\) cm, opposite the right angle) and one more equal side: RHS.

(iii) Two equal sides with the \(48^\circ\) angle between them: SAS.

In (i), check the side is in the same position. A \(7\) cm side opposite \(35^\circ\) in one triangle and opposite \(80^\circ\) in the other would prove nothing.

Example 2 — Proof, then calculate
In \(\triangle ABC\), \(AB = AC = 15\) cm and \(BC = 18\) cm. \(AM\) is perpendicular to \(BC\).
(i) Prove that \(\triangle ABM \equiv \triangle ACM\).
(ii) Hence find \(BM\) and the height \(AM\).
Solution
Isosceles triangle ABC with altitude AMIsosceles triangle ABC with AB = AC = 15 cm and base BC = 18 cm. The dashed line AM is perpendicular to BC at M. A B C M 15 cm BC = 18 cm

(i) In \(\triangle ABM\) and \(\triangle ACM\):

\(\angle AMB = \angle AMC = 90^\circ\) (given)
\(AB = AC\) (given, the hypotenuses)
\(AM\) is common

\(\therefore\ \triangle ABM \equiv \triangle ACM\) (RHS)

(ii) Matching sides are equal, so \(BM = MC\) and \(M\) is the midpoint of \(BC\).

\(BM\)\(=\)\(18 \div 2 = \mathbf{9}\text{ cm}\)
\(AM^2\)\(=\)\(15^2 - 9^2 = 144\)
\(AM\)\(=\)\(\mathbf{12}\text{ cm}\)
AM2=152−92=144
Example 3 — Matching sides by opposite angles
The two triangles are congruent. The diagram is not drawn to scale.
(i) Write a congruence statement.
(ii) Find \(x\) and \(y\).
Solution
Two congruent triangles with algebraic sidesTriangle ABC with angle A 40 degrees, angle B 75 degrees, side BC = 3x − 2 and side AC = 17. Triangle DEF with angle E 65 degrees, angle F 40 degrees, side DE = x + 8 and side EF = 4y + 1. 40° 75° 65° 40° 3x − 2 17 x + 8 4y + 1 ABC EFD

(i) Find the third angles: \(\angle C = 180^\circ - 40^\circ - 75^\circ = 65^\circ\) and \(\angle D = 180^\circ - 65^\circ - 40^\circ = 75^\circ\). Match equal angles: \(A \leftrightarrow F\), \(B \leftrightarrow D\), \(C \leftrightarrow E\), so \(\mathbf{\triangle ABC \equiv \triangle FDE}\).

(ii) Matching sides sit opposite equal angles. \(BC\) is opposite \(40^\circ\), like \(DE\). \(AC\) is opposite \(75^\circ\), like \(EF\).

\(3x - 2\)\(=\)\(x + 8\)
\(2x\)\(=\)\(10\)
\(x\)\(=\)\(\mathbf{5}\)
\(4y + 1\)\(=\)\(17\)
\(y\)\(=\)\(\mathbf{4}\)

Check: \(BC = 13 = DE\) \(\checkmark\)

3x−2=x+8
Example 4 — Proved or not?

(i) \(\triangle KLM\) has \(KL = 9\) cm, \(LM = 12\) cm and \(\angle L = 90^\circ\). \(\triangle PQR\) has \(\angle Q = 90^\circ\), \(QR = 9\) cm and hypotenuse \(PR = 15\) cm. Are they congruent?
(ii) \(\triangle ABC\) has \(AB = 7\), \(BC = 10\), \(\angle A = 50^\circ\). \(\triangle DEF\) has \(DE = 7\), \(EF = 10\), \(\angle E = 50^\circ\). Do these facts prove them congruent?
Solution

(i) Find the hypotenuse of \(\triangle KLM\).

\(KM^2\)\(=\)\(9^2 + 12^2 = 225\)
\(KM\)\(=\)\(15\text{ cm}\)

Right angles, hypotenuses \(15\) cm and a side of \(9\) cm in each: yes, RHS, with \(\triangle KLM \equiv \triangle RQP\).

(ii) In \(\triangle DEF\) the \(50^\circ\) angle is between the \(7\) and \(10\) sides. In \(\triangle ABC\) it is at \(A\), which is not between \(AB\) and \(BC\).

Two sides and a 50 degree angle in different positionsTriangle ABC: AB = 7, BC = 10 and angle A = 50 degrees, which is not between the two given sides. Triangle DEF: DE = 7, EF = 10 and angle E = 50 degrees, which is between them. 50° 50° 7 10 7 10 ACB EFD

The facts do not line up with any one test, so they do not prove congruence.

KM2=92+122=225

Common pitfalls

SAS needs the included angle. The angle must be between the two equal sides. Two sides and an angle somewhere else is not a test.
AAA is not a test. Equal angles give the same shape, but one triangle can be an enlargement of the other. Add one matching side to use AAS.
In AAS the side must match. The equal side has to be opposite the same angle in both triangles. Find the third angles first so you can compare.
RHS uses the hypotenuse. The hypotenuse is opposite the right angle. A right angle and two equal shorter sides is SAS, not RHS.
Look for hidden equal parts. A shared side and vertically opposite angles are often the third fact you need. Give each one a reason.

Frequently asked questions

What are the 4 congruence tests for triangles?

The four tests are SSS (three sides), SAS (two sides and the included angle), AAS (two angles and a matching side) and RHS (right angle, hypotenuse and one other side).

What is the difference between SAS and AAS?

SAS uses two sides and the angle between them. AAS uses two angles and one side, which must be opposite the same angle in both triangles.

Why is AAA not a congruence test?

Triangles with the same three angles have the same shape, but one can be bigger than the other. They are similar, not necessarily congruent.

Why is SSA not a congruence test?

With two sides and an angle that is not between them, the third side can often swing into two different positions, giving two different triangles. The facts do not fix one triangle.

Is ASA the same as AAS?

Yes, they work the same way. If two angles are equal the third angles are equal too, so a side between two angles or opposite one of them both fix the triangle. NSW uses the name AAS.

How do you set out a congruence proof?

Name the two triangles. List three pairs of equal parts, each with a reason such as given, common side or vertically opposite angles. Then write the congruence statement with the test in brackets.