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Year 7 Maths Number Plane

Graphing Table of Values

20 practice questions 1 video lesson Theory + worked examples

Graphing Table of Values links a rule, a table of values and a straight-line graph in NSW Year 7 maths (NESA outcome MA4‑LIN‑C‑01). Each column of the table gives a pair of coordinates, and plotting the points for a rule such as \(y = x + 2\) shows them lying on a line.

You will complete tables from a rule, plot and join the points, describe patterns such as rows of matchstick squares with an equation, use a rule to predict larger values, and find where two lines cross (the point of intersection). An electrician's call-out fee plus an hourly rate and a draining water tank are real examples. It is part of Year 7 Number Plane.

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Theory

A table of values lists \(x\)-values and the \(y\)-values a rule gives for them. Each column is a point \((x, y)\). When the points lie on a straight line, the relationship is linear. This Year 7 maths page shows how to fill in a table, plot the points, find the rule from a table and use the line to answer questions.

Ordered pairs can be written in a table of values. Each column (or row) is one point:

\(x\)\(-1\)\(0\)\(2\)\(4\)
\(y\)\(0\)\(3\)\(5\)\(1\)

means the points \((-1, 0)\), \((0, 3)\), \((2, 5)\), \((4, 1)\). A table can also go down the page, with an \(x\) column and a \(y\) column.

Rule to table. Substitute each \(x\)-value into the rule. For \(y = 2x - 1\) and \(x = 4\): \(y = 2 \times 4 - 1 = 7\).

Table to graph. Plot each point, then join them with a ruler and put arrows on both ends: the line keeps going, so infinitely many points fit the rule. Points that lie on one straight line are collinear.

Special lines. If every \(y\)-value is \(2\), the points make the horizontal line \(y = 2\). If every \(x\)-value is \(2\), they make the vertical line \(x = 2\).

The line y = 2x - 1 Points (0, -1), (1, 1), (2, 3) and (3, 5) plotted and joined by a straight line with arrows. The extended line also passes through (-1, -3). −2−11234−4−3−2−11234560xy (1, 1) (2, 3) (3, 5) (−1, −3)
For \(y = 2x - 1\): \(x = 0, 1, 2, 3\) gives \(y = -1, 1, 3, 5\). Each time \(x\) goes up \(1\), \(y\) goes up \(2\). Extending the line finds more points, such as \((-1, -3)\): \(2 \times (-1) - 1 = -3\).
A horizontal line and a vertical line The horizontal line y = 3 and the vertical line x = 1 drawn on a number plane. They cross at (1, 3). 12345123450xy y = 3 x = 1 (1, 3)
Every point on the red line has \(y = 3\): it is the horizontal line \(y = 3\). Every point on the blue line has \(x = 1\): it is the vertical line \(x = 1\).

From a table to a rule:

Going up. If \(y\) goes up by the same step each time \(x\) goes up \(1\), multiply \(x\) by the step, then add or take away to match the table.

\(x\)\(0\)\(1\)\(2\)\(3\)
\(y\)\(-1\)\(1\)\(3\)\(5\)

\(y\) goes up \(2\) each time, so start with \(2x\). At \(x = 0\), \(2x = 0\) but \(y = -1\), so take away \(1\):

\[ y = 2x - 1 \]
y =2 x −1

Going down. If \(y\) goes down by the same step, start with the \(y\)-value at \(x = 0\) and take away the step for each \(x\): \(y = 10, 7, 4, 1\) for \(x = 0, 1, 2, 3\) gives \(y = 10 - 3x\).

Is a point on the line? Substitute its \(x\)-value into the rule. If you get its \(y\)-value, the point is on the line. Two lines cross at the point that fits both rules.
Check every column. A rule must work for every column of the table, not just the first one.

How to graph a rule

  1. Choose some \(x\)-values and make a table.
  2. Substitute each \(x\) into the rule to get \(y\).
  3. Plot each column as a point \((x, y)\).
  4. Join the points with a ruler and put arrows on both ends.

How to find the rule from a table

  1. Find the step: how much \(y\) changes when \(x\) goes up \(1\).
  2. Multiply \(x\) by the step (use \(-\) if \(y\) goes down).
  3. Add or take away to match the \(y\)-value at \(x = 0\).
  4. Check the rule on every column.
Example 1 — Table to graph
Complete the table for \(y = x + 3\), then plot and join the points.
\(x\)\(-1\)\(0\)\(1\)\(2\)
\(y\)
Solution
The line y = x + 3 Points (-1, 2), (0, 3), (1, 4) and (2, 5) joined by a straight line. −2−11231234560xy
\(-1 + 3\)\(=\)\(2\)
\(0 + 3\)\(=\)\(3\)
\(1 + 3\)\(=\)\(4\)
\(2 + 3\)\(=\)\(5\)
−1+3=2,0+3=3,1+3=4,2+3=5

The \(y\)-values are \(2, 3, 4, 5\). The points \((-1, 2)\), \((0, 3)\), \((1, 4)\), \((2, 5)\) make a straight line.

Example 2 — Describe the pattern
Graph the table of values and describe the pattern of points.
\(x\)\(1\)\(2\)\(3\)\(4\)\(5\)
\(y\)\(3\)\(6\)\(9\)\(12\)\(15\)
Solution

The ordered pairs are \(A(1, 3)\), \(B(2, 6)\), \(C(3, 9)\), \(D(4, 12)\), \(E(5, 15)\).

Points from the table y = 3x Points A(1, 3), B(2, 6), C(3, 9), D(4, 12) and E(5, 15) lie on a straight line. 5510150xy A B C D E

The points are collinear: they lie on a straight line. Each \(y\) is three times \(x\), so the rule is \(y = 3x\).

Example 3 — A rule that goes down
(i) Find the rule for this table.
(ii) Use the rule to find \(y\) when \(x = 6\).
\(x\)\(0\)\(1\)\(2\)\(3\)
\(y\)\(11\)\(8\)\(5\)\(2\)
Solution

(i) \(y\) goes down \(3\) each time \(x\) goes up \(1\). At \(x = 0\), \(y = 11\). So \(y = 11 - 3x\). Check with \(x = 3\): \(11 - 3 \times 3 = 2\).

\(y\)\(=\)\(11 - 3 \times 6\)
\(\)\(=\)\(11 - 18 = -7\)
y =11−3×6=11−18=−7

(i) \(y = 11 - 3x\)
(ii) \(y = -7\)

Example 4 — Horizontal and vertical lines
Describe the line through each set of points.
(i) \(x = -1, 0, 1, 2\) and \(y = 4, 4, 4, 4\)
(ii) \(x = -3, -3, -3\) and \(y = 0, 1, 2\)
Solution

(i) Every \(y\) is \(4\): a horizontal line.
(ii) Every \(x\) is \(-3\): a vertical line.

(i) \(y = 4\)
(ii) \(x = -3\)

Example 5 — Half steps and extending
The points \((0, 1)\), \((2, 2)\) and \((4, 3)\) are plotted and joined. The line is extended. What is \(y\) when \(x = 8\)?
Solution

Each time \(x\) goes up \(2\), \(y\) goes up \(1\). From \(x = 4\) to \(x = 8\) is two more steps of \(2\), so \(y\) goes up \(2\) more.

\(y\)\(=\)\(3 + 1 + 1 = 5\)
y =3+1+1=5

\(y = 5\) when \(x = 8\): the point \((8, 5)\) is on the line.

Example 6 — A matchstick pattern
Triangles in a row are made from matches: \(1\) triangle uses \(3\) matches, \(2\) use \(5\), \(3\) use \(7\), \(4\) use \(9\).
(i) Write a rule for the number of matches \(M\) for \(t\) triangles.
(ii) How many matches make \(20\) triangles?
(iii) How many triangles can \(61\) matches make?
Solution

(i) \(M\) goes up \(2\) each time, so start with \(2t\): \(2 \times 1 = 2\), and the table has \(3\) (\(1\) more). So \(M = 2t + 1\).
(iii) Undo the rule: take away \(1\), then divide by \(2\).

\(M\)\(=\)\(2 \times 20 + 1 = 41\)
\((61 - 1) \div 2\)\(=\)\(30\)
M =2×20+1=41,(61−1)÷2=30

(i) \(M = 2t + 1\)
(ii) \(41\) matches
(iii) \(30\) triangles

Example 7 — Two phone plans
Plan A costs \(\$10\) plus \(\$2\) per GB of data: \(A = 2g + 10\). Plan B costs \(\$4\) per GB: \(B = 4g\). For how many GB do they cost the same?
Solution

Make a table and find the column where both costs are equal.

GB \((g)\)\(3\)\(4\)\(5\)\(6\)
Plan A ($)\(16\)\(18\)\(\mathbf{20}\)\(22\)
Plan B ($)\(12\)\(16\)\(\mathbf{20}\)\(24\)

\(2 \times 5 + 10\)\(=\)\(20\)
\(4 \times 5\)\(=\)\(20\)
2×5+10=20,4×5=20

They cost the same, \(\$20\), for \(5\) GB. On a graph, the two lines cross at \((5, 20)\).

Example 8 — Is the point on the line?
The rule is \(y = 4x - 3\). Is each point on the line?
(i) \((15, 57)\)
(ii) \((12, 44)\)
Solution
\(4 \times 15 - 3\)\(=\)\(57\)
\(4 \times 12 - 3\)\(=\)\(45\)
4×15−3=57,4×12−3=45

(i) Yes: \(x = 15\) gives \(y = 57\).
(ii) No: \(x = 12\) gives \(y = 45\), not \(44\).

Common pitfalls

Swapping x and y. The column \(x = 2\), \(y = 3\) is the point \((2, 3)\), not \((3, 2)\).
Checking only one column. \(y = x\) fits \((1, 1)\), but for \(x = 2\) it gives \(2\), not \(3\). The rule that fits \((1, 1)\), \((2, 3)\), \((3, 5)\) is \(y = 2x - 1\).
Mixing up horizontal and vertical. If the \(y\)-values are \(3, 3, 3\), the line is \(y = 3\) (horizontal), not \(x = 3\).
Joining with a curve or no arrows. Join collinear points with a ruler, and put arrows on both ends because the line keeps going.

Frequently asked questions

What is a table of values?

A table of \(x\)-values and the \(y\)-values a rule gives for them. Each column is a point \((x, y)\).

How do you complete a table of values?

Substitute each \(x\)-value into the rule. For \(y = x + 3\) and \(x = 2\), \(y = 5\).

How do you find the rule from a table?

Find how much \(y\) changes when \(x\) goes up \(1\), multiply \(x\) by that step, then add or take away to match the table.

What line do the points (5, 1), (5, 2), (5, 3) make?

The vertical line \(x = 5\), because every \(x\) is \(5\).

How do you check if a point is on a line?

Substitute the \(x\)-value into the rule. If the answer is the \(y\)-value, the point is on the line.