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Year 12 Maths Standard 2 (2027) Algebraic relationships

Simultaneous Equations (Graphically)

20 practice questions 0 video lessons Theory + worked examples

Master simultaneous equations the graphical way for NSW Year 12 Mathematics Standard 2. In this topic you graph two straight lines on the same axes and read the point of intersection — the pair of values that solves both equations at once.

You will learn to solve a pair graphically, decide whether a pair has one solution, no solution (parallel lines) or infinitely many, and find the break-even point where revenue first covers cost — a core Standard 2 skill for comparing real-world plans and pricing.

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Theory

Simultaneous linear equations are two straight-line equations solved together. This Year 12 Standard 2 (NSW) guide shows how to solve them graphically — graph both lines, read the point of intersection, decide how many solutions the pair has, and find the break-even point where cost meets revenue.

A pair of simultaneous linear equations is two straight-line equations that must both be true at the same time. Their solution is the pair of values \((x,y)\) that satisfies both.

Solving graphically means drawing both lines on the same axes. The point of intersection — where the lines cross — is the solution, because that point lies on both lines at once.

A pair can have one solution (lines cross), no solution (parallel lines), or infinitely many (the same line twice). In money problems the crossing point is the break-even point, where revenue equals cost.

Intersection of two linesy=x+1 and y=-x+5 cross at (2,3) x y -1 1 2 3 4 5 6 -1 1 2 3 4 5 6 7 2 3
The solution is the crossing point \((2,3)\).
Parallel linesTwo parallel lines that never meet x y -2 -1 1 2 3 -4 -2 2 4 6
Parallel lines never meet — no solution.

Each line is written in gradient–intercept form:

\[y = mx + c\]
y=mx+c

At the solution the two lines share the same point, so their \(y\)-values are equal there:

\[m_1 x + c_1 = m_2 x + c_2\]
m1x+c1=m2x+c2
Break-even. When one line is revenue \(R\) and the other is cost \(C\), the crossing point is where \(R=C\) — income just covers cost.

How to solve a pair graphically

  1. Rearrange each equation into the form \(y=mx+c\) if it is not already.
  2. Graph both lines on the same axes (plot the \(y\)-intercept and one more point).
  3. Read the coordinates of the point where the lines cross.
  4. Check and state the solution \((x,y)\) in both equations; in a money problem, interpret it as the break-even point.
Example 1 — Read the solution
The graph shows \(y=x+2\) and \(y=-x+4\). Write the solution of the pair.
Solution

Read the crossing point, then check it in both equations.

Example 1y=x+2 and y=-x+4 cross at (1,3) x y -2 -1 1 2 3 4 5 -1 1 2 3 4 5 6 1 3
\((1,3)\)\(\)\(\text{crossing point}\)
\(3\)\(=\)\(1+2\ \checkmark\)
\(3\)\(=\)\(-1+4\ \checkmark\)
\(\therefore\ (x,y)\)\(=\)\((1,3)\)
(1,3)
Example 2 — From a table
Graph \(y=2x-1\) and \(y=x+1\) and find where they meet.
Solution

Both lines pass through the same point at \(x=2\).

Example 2y=2x-1 and y=x+1 cross at (2,3) x y -1 1 2 3 4 -3 -2 -1 1 2 3 4 5 6 7 2 3
\(2(2)-1\)\(=\)\(3\)
\(2+1\)\(=\)\(3\)
\(\therefore\ (x,y)\)\(=\)\((2,3)\)
(2,3)
Example 3 — How many solutions?
How many solutions does \(y=3x+2\) and \(y=3x-1\) have?
Solution

Compare the gradients. Equal gradients mean parallel lines.

Example 3Two parallel lines with gradient 3 x y -2 -1 1 2 -6 -3 3 6 9
\(m_1\)\(=\)\(3\)
\(m_2\)\(=\)\(3\)
\(2\)\(\ne\)\(-1\)

Same gradient, different intercept — parallel, so no solution.

Example 4 — Break-even
A stall sells candles for \(\$4\) each (revenue \(R=4n\)) with costs \(C=20+2n\) dollars for \(n\) candles. Find the break-even point.
Solution

Break-even is where revenue equals cost, \(R=C\).

Example 4Revenue R=4n meets cost C=20+2n at (10,40) n C 5 10 15 20 40 60 R=4n C=20+2n
\(4n\)\(=\)\(20+2n\)
\(2n\)\(=\)\(20\)
\(n\)\(=\)\(10\)
\(C\)\(=\)\(\$40\)
n=10

Selling 10 candles gives revenue \(=\) cost \(=\$40\).

Common pitfalls

Give both coordinates. The solution is a point \((x,y)\); writing only \(x\) loses half the answer.
Watch for parallel lines. Equal gradients never cross, so the pair has no solution — do not invent one.
Rearrange first. Put each equation in the form \(y=mx+c\) before plotting, and read the crossing point off the gridlines carefully.

Frequently asked questions

How do you solve simultaneous equations graphically?

Graph both straight lines on the same axes and read off the coordinates of the point where they cross. That point is the solution, because it is the only pair of x and y values that lies on both lines.

What does the point of intersection tell you?

It gives the solution of the pair: the x-value and y-value that make both equations true at the same time. Always state both coordinates, for example x equals 2 and y equals 3.

What happens if the two lines are parallel?

Parallel lines have the same gradient and never cross, so the pair has no solution. If the two equations are actually the same line, every point lies on both and there are infinitely many solutions.

What is a break-even point?

It is where a revenue line meets a cost line on the graph. At that number of items, income equals cost, so there is no profit and no loss; beyond it the business starts to make a profit.

Can two straight lines have more than one solution?

No. Two different straight lines either cross once (one solution) or are parallel (no solution). The only way to get more than one solution is if the two equations describe the exact same line, giving infinitely many.