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Year 12 Maths Standard 2 (2027) Algebraic relationships

Modelling with Simultaneous Equations

20 practice questions 0 video lessons Theory + worked examples

Learn modelling with simultaneous equations for NSW Year 12 Mathematics Standard 2. In this topic you turn a real-world story — two pricing plans, a mixture, a two-item purchase or a hire cost — into two linear equations, then solve them to find both unknowns.

You will learn to define the pronumerals, translate each fact into an equation, solve the pair by elimination, substitution or graphing, and interpret the solution in context with the right units — a core Standard 2 skill for solving practical problems.

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Theory

Modelling with simultaneous equations turns a worded practical situation into two linear equations you can solve together. This Year 12 Standard 2 (NSW) guide shows how to define the pronumerals, translate each fact into an equation, solve by elimination, substitution or graphing, and interpret the answer in context — for pricing plans, mixtures, two-item purchases and hire costs.

Modelling with simultaneous equations means taking a real-world story with two unknown quantities and writing two linear equations that describe it, then solving them together to find both unknowns.

The key idea is that two unknowns need two facts. Each separate fact in the problem becomes one equation; a single equation on its own can never fix both values. Once you have a pair, you can solve it by elimination, substitution, or by graphing both lines and reading the point of intersection.

The final step is interpretation: the solution \((x,y)\) must be translated back into the context — a price, a mass, a number of hours — stated with the correct units. This is a core Year 12 Standard 2 (NSW) skill for pricing plans, mixtures, two-item purchases and hire costs.

Two plans modelled as linesC=10+5n and C=20+3n cross at (5,35) n C 2 4 6 8 10 20 30 40 50 5 35 Plan A Plan B
Each plan is a line; they cost the same at the crossing point \((5,35)\).
Two conditions, two lines2x+y=8 and x+2y=7 cross at (3,2) x y 1 2 4 5 4 6 8 3 2
Two facts give two lines; the solution \((3,2)\) satisfies both.

A model with two unknowns is a pair of linear equations:

\[a_1x + b_1y = c_1 \qquad a_2x + b_2y = c_2\]
a1x+b1y=c1

When two options are compared (two plans, two shops), model each as a cost and set the expressions equal to find where they agree:

\[C_1 = mx + c \qquad C_2 = px + q \qquad C_1 = C_2\]
C1=C2
Elimination. Scale the equations so one pronumeral has a matching coefficient, then add or subtract to remove it. Substitution. Rearrange one equation for a pronumeral and put it into the other. Either way, solve for one unknown, then back-substitute for the second.

How to model and solve a practical problem

  1. Define the pronumerals: state exactly what each letter represents, with its unit (dollars, kg, hours).
  2. Translate each fact in the story into one linear equation — you need two equations for two unknowns.
  3. Solve the pair by elimination, substitution, or by graphing both lines and reading the intersection.
  4. Interpret and check: write the answer in context with units, and verify it satisfies both original equations.
Example 1 — Two-item purchase
At a canteen, \(4\) sausage rolls and \(3\) juices cost \(\$16.50\); \(2\) sausage rolls and \(5\) juices cost \(\$13.50\). Find the price of each item.
Solution

Let \(r\) and \(j\) be the prices (\$); eliminate \(r\) by doubling the second equation.

\(4r+3j\)\(=\)\(16.50\)
\(2r+5j\)\(=\)\(13.50\)
\(4r+10j\)\(=\)\(27.00\)
\(7j\)\(=\)\(10.50\)
\(j\)\(=\)\(1.50\)
\(r\)\(=\)\(3.00\)
r=3.00

A roll costs \(\$3.00\) and a juice \(\$1.50\).

Example 2 — Mixture
A cafe blends premium beans at \(\$25\)/kg with standard beans at \(\$15\)/kg to make \(10\) kg of blend worth \(\$21\)/kg. How much of each bean is used?
Solution

Let \(p\) and \(s\) be the masses (kg); substitute \(s=10-p\).

\(p+s\)\(=\)\(10\)
\(25p+15s\)\(=\)\(210\)
\(25p+15(10-p)\)\(=\)\(210\)
\(10p+150\)\(=\)\(210\)
\(p\)\(=\)\(6\)
\(s\)\(=\)\(4\)
p=6

Use \(6\) kg premium and \(4\) kg standard beans.

Example 3 — Compare two plans
Kayak hire: Shop A charges \(\$25\) plus \(\$10\) per hour; Shop B charges \(\$40\) plus \(\$5\) per hour. For how many hours do they cost the same?
Solution

Model each shop as a cost line, then set the two costs equal.

Example 3Shop A 25+10h meets Shop B 40+5h at (3,55) h C 1 2 4 5 6 20 40 80 3 55 Shop A Shop B
\(25+10h\)\(=\)\(40+5h\)
\(5h\)\(=\)\(15\)
\(h\)\(=\)\(3\)
\(C\)\(=\)\(\$55\)
h=3

Both cost \(\$55\) at \(3\) hours. For under \(3\) h Shop A is cheaper; beyond \(3\) h Shop B is cheaper.

Example 4 — Counting mix
A basketballer scores \(22\) points from \(15\) successful shots, each worth \(1\) or \(2\) points. How many of each did she make?
Solution

Let \(x\) and \(y\) be the numbers of shots; subtract the equations to eliminate \(x\).

\(x+y\)\(=\)\(15\)
\(x+2y\)\(=\)\(22\)
\(y\)\(=\)\(7\)
\(x\)\(=\)\(8\)
x=8

She made \(8\) one-point and \(7\) two-point shots.

Common pitfalls

Two unknowns need two equations. One fact can never fix both values — read the story for a second condition.
Define your pronumerals. Say what each letter means, with units, before writing equations; otherwise the answer cannot be interpreted.
Answer in context. A bare \((x,y)\) is not the answer — state the price, mass or time with units, and keep dollars and cents consistent.

Frequently asked questions

How do you turn a worded problem into simultaneous equations?

Read the problem for the two unknown quantities and give each a pronumeral with its unit. Then translate each separate fact in the story into one linear equation. Two unknowns need two equations, so look for two distinct pieces of information.

Should I use substitution or elimination?

Both give the same answer, so use whichever is easier for the equations you have. Substitution is neat when one equation already has a pronumeral by itself, like s equals 10 minus p. Elimination is neat when you can scale the equations so one pronumeral cancels when you add or subtract.

Why do I have to define the pronumerals first?

Because the final answer must be stated in context. If you write let x and y with no meaning, you cannot say whether the solution is a price, a mass or a number of hours. Always write, for example, let r be the price of a roll in dollars.

Can I solve a modelling problem by graphing instead?

Yes. Model each condition as a straight line, graph both on the same axes, and read the coordinates of the point where they cross. This is especially useful when comparing two plans or hire costs, because the graph also shows which option is cheaper on each side of the crossing point.

What if the solution is not a whole number?

That is fine — prices and masses are often decimals, like a juice costing 1.50 dollars. Just make sure the answer makes sense in context. If a count of people or objects comes out as a fraction, re-check your equations, because those must be whole numbers.