Resources For Teachers For Tutors For Students & Parents Pricing
Year 12 Maths Standard 1 (2027) Ratios and rates

Fuel Consumption

20 practice questions 0 video lessons Theory + worked examples

Learn about fuel consumption for NSW Year 12 Mathematics Standard 1 (NESA outcome MST-12-S1-05). Fuel consumption is a rate in litres per 100 kilometres (L/100 km) — a car rated at 7 L/100 km burns 7 litres of fuel for every 100 km it drives.

You will find the fuel used on a trip, calculate a vehicle's fuel consumption rate, work out the cost of fuel, and use these rates to see which car is more fuel-efficient — the lower rate wins, which matters when buying a car or planning a road trip.

Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

Fuel consumption is a rate that tells you how many litres a vehicle uses to travel \(100\text{ km}\), written L/100 km. This Year 12 Standard 1 (NSW) guide shows how to find the fuel used on a trip, the consumption rate, the cost of petrol, and which vehicle is more fuel-efficient.

Fuel consumption is a rate measured in litres per 100 kilometres (L/100 km). A car rated at \(7\) L/100 km uses \(7\) litres of fuel for every \(100\text{ km}\) it travels.

To find the fuel used, divide the distance by \(100\) to count the lots of \(100\text{ km}\), then multiply by the rate. To find the rate, divide the litres used by the distance and multiply by \(100\). The cost of fuel \(=\) litres used \(\times\) price per litre.

When comparing vehicles, write each rate in L/100 km. The lower rate is the more fuel-efficient vehicle and costs less to run. This is a core Year 12 Standard 1 (NSW) Ratios and rates skill.

Fuel used against distance for two carsTwo lines from the origin. Car B rises to 40 litres at 400 km (10 L/100 km); car A rises to 24 litres at 400 km (6 L/100 km). At 300 km, A has used 18 L and B 30 L. 100 200 300 400 10 20 30 40 distance (km) fuel used (L) 30 L 18 L Car B: 10 Car A: 6 L/100 km L/100 km
Over \(300\text{ km}\), Car A uses \(18\) L and Car B uses \(30\) L. The less steep line is the more fuel-efficient car.
A 300 km trip split into three lots of 100 kmA road strip split into three equal 100 km blocks, each labelled 6 L, totalling 18 L for 300 km at 6 L/100 km. 100 km 6 L 100 km 6 L 100 km 6 L 300 km at 6 L/100 km 300 Γ· 100 = 3 lots, so 3 Γ— 6 = 18 L
Fuel used \(=\) rate \(\times\) number of \(100\text{ km}\) lots: \(6\times 3=18\) L.

Fuel used on a trip:

\[\text{fuel used} = \text{rate} \times \dfrac{\text{distance}}{100}\]
fuel used=rate×distance100

Fuel consumption rate in L/100 km:

\[\text{rate} = \dfrac{\text{litres used}}{\text{distance}} \times 100\]
rate=litres useddistance×100

Cost of the fuel:

\[\text{cost} = \text{litres used} \times \text{price per litre}\]
cost=litres used×price per litre
Lower is better. The vehicle with the lower L/100 km uses less fuel for the same distance, so it is more fuel-efficient.

How to solve a fuel consumption problem

  1. Identify what you know: the rate (L/100 km), the distance, the litres used or the price per litre.
  2. Fuel used: divide the distance by \(100\), then multiply by the rate.
  3. Rate: divide the litres by the distance, then multiply by \(100\).
  4. Cost: multiply the litres used by the price per litre, and round to the nearest cent.
Example 1 β€” Fuel used on a trip
A hatchback uses \(6.5\) litres of petrol per \(100\text{ km}\). How much petrol does it use on a \(420\text{ km}\) trip?
Solution

Fuel used \(=\) rate \(\times\) the number of \(100\text{ km}\) travelled.

\(\text{fuel}\)\(=\)\(\text{rate} \times \dfrac{\text{distance}}{100}\)
\(\)\(=\)\(6.5 \times \dfrac{420}{100}\)
\(\)\(=\)\(6.5 \times 4.2\)
\(\therefore\ \text{fuel}\)\(=\)\(27.3\text{ L}\)
6.5×4.2=27.3

The hatchback uses \(27.3\) litres.

Example 2 β€” Finding the consumption rate
A four-wheel drive uses \(52\) litres of petrol to travel \(400\text{ km}\). Find its fuel consumption in L/100 km.
Solution

Litres used \(\div\) distance, then \(\times 100\).

\(\text{rate}\)\(=\)\(\dfrac{52}{400} \times 100\)
\(\)\(=\)\(0.13 \times 100\)
\(\therefore\ \text{rate}\)\(=\)\(13\text{ L/100 km}\)
52400×100=13

The four-wheel drive uses \(13\) L/100 km.

Example 3 β€” Cost of the petrol
A ute uses \(9\) litres per \(100\text{ km}\) and petrol costs \(\$1.95\) per litre. Find the cost of petrol for a \(380\text{ km}\) trip.
Solution

Find the litres used, then multiply by the price per litre.

\(\text{fuel}\)\(=\)\(9 \times \dfrac{380}{100}\)
\(\)\(=\)\(9 \times 3.8 = 34.2\text{ L}\)
\(\text{cost}\)\(=\)\(34.2 \times \$1.95\)
\(\therefore\ \text{cost}\)\(=\)\(\$66.69\)
34.2×1.95=66.69

The petrol costs \(\$66.69\).

Example 4 β€” Which car is more efficient?
Car X used \(38.5\) litres to travel \(550\text{ km}\). Car Y uses \(7.5\) L/100 km. (i) Which car is more fuel-efficient? (ii) Petrol costs \(\$1.88\) per litre. How much cheaper is the petrol for an \(800\text{ km}\) trip in the more efficient car?
Solution

Write both as L/100 km, then cost the same trip.

\(\text{(i) Car X}\)\(=\)\(\dfrac{38.5}{550} \times 100 = 7\text{ L/100 km}\)
\(7\)\(\lt\)\(7.5 \ \Rightarrow\ \text{Car X}\)
\(\text{(ii) X}\)\(=\)\(7 \times \dfrac{800}{100} = 7 \times 8 = 56\text{ L}\)
\(\text{Y}\)\(=\)\(7.5 \times \dfrac{800}{100} = 7.5 \times 8 = 60\text{ L}\)
\(\text{saving}\)\(=\)\((60 - 56) \times \$1.88\)
\(\therefore\ \text{saving}\)\(=\)\(4 \times \$1.88 = \$7.52\)
$7.52

(i) Car X; (ii) its petrol is \(\$7.52\) cheaper.

Common pitfalls

The rate is per 100 km. Divide the distance by \(100\) before multiplying by the rate: \(7\times 350\) is far too big; it is \(7\times 3.5=24.5\) L.
Put litres on top. The rate is \(\dfrac{\text{litres}}{\text{km}}\times 100\), not \(\dfrac{\text{km}}{\text{litres}}\).
A lower L/100 km is better. On a graph of fuel against distance, the least steep line is the most fuel-efficient.

Frequently asked questions

What does L/100 km mean?

L/100 km is the number of litres of fuel a vehicle uses to travel 100 kilometres. A car rated at 6.5 L/100 km uses 6.5 litres for every 100 km it drives.

How do you calculate fuel used for a trip?

Divide the distance by 100 to find how many lots of 100 km there are, then multiply by the fuel consumption rate. A car using 6.5 L/100 km on a 420 km trip uses 6.5 times 4.2, which is 27.3 litres.

How do you calculate fuel consumption in L/100 km?

Divide the litres used by the distance travelled, then multiply by 100. A four-wheel drive that uses 52 litres to travel 400 km has a rate of 52 divided by 400 times 100, which is 13 L/100 km.

How do you work out the cost of fuel for a trip?

Work out the litres used, then multiply by the price per litre. A ute using 34.2 litres with petrol at $1.95 per litre costs 34.2 times 1.95, which is $66.69.

Is a higher or lower L/100 km better?

Lower is better. A lower number means the vehicle uses less fuel to travel the same distance, so it is more fuel-efficient and cheaper to run.