Resources For Teachers For Tutors For Students & Parents Pricing
Year 12 Maths Advanced (2027) Applications of calculus

Stationary Points & the First Derivative Test

20 practice questions 0 video lessons Theory + worked examples
NSW · Year 12 Mathematics Advanced · Applications of calculus

Stationary points occur where \(f'(x)=0\); the first derivative test classifies each as a maximum, minimum or horizontal point of inflection.

Part of the NSW Year 12 Mathematics Advanced course, in the Calculus area of study (Applications of calculus focus area) of the 2024 syllabus. Work through practice questions with fully worked solutions and video lessons, or scroll down for the theory summary and worked examples.

Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

Stationary points are where \(f'(x)=0\), classified by how \(f'\) changes sign. This Year 12 Mathematics Advanced topic (MAV-12-06) finds and classifies them.

Solve \(f'(x)=0\), then test the sign of \(f'\) either side: \(+\) then \(-\) is a maximum; \(-\) then \(+\) is a minimum; the same sign both sides is a horizontal point of inflection. (Or use \(f''\): \(<0\) max, \(>0\) min.)

Stationary pointsA cubic with a maximum at (-1,2) and a minimum at (1,-2). xy max min
\(y=x^{3}-3x\): a maximum and a minimum.
\[f'(x)=0\ \text{(stationary)};\quad f''<0\ \text{max},\ f''>0\ \text{min}\]
stationary where f prime is zero; f double prime negative max, positive min

Method

  1. Solve \(f'(x)=0\).
  2. Classify by a sign change of \(f'\) (or the sign of \(f''\)).
  3. Find the \(y\)-values by substituting into \(f\).
Example 1 — Find and classify
Classify the stationary point of \(f(x)=x^{2}-6x+5\).
Solution
\(2x-6\)\(=\)\(0\Rightarrow x=3\)
\(f''\)\(=\)\(2>0\ (\text{min})\)
\(f(3)\)\(=\)\(-4\)
Example 2 — Two points
Find the stationary points of \(f(x)=x^{3}-3x\).
Solution
\(3x^{2}-3\)\(=\)\(0\)
\(x\)\(=\)\(\pm 1\)
Example 3 — Classify with f''
Classify them (\(f''=6x\)).
Solution
\(f''(-1)\)\(=\)\(-6<0\ (\text{max})\)
\(f''(1)\)\(=\)\(6>0\ (\text{min})\)
Example 4 — Horizontal inflection
Classify the stationary point of \(f(x)=x^{3}\).
Solution

\(f'=3x^{2}=0\Rightarrow x=0\); \(f'\) is \(+\) both sides, so a horizontal point of inflection at \((0,0)\).

Common pitfalls

Solve \(f'=0\) first.
Classify by a sign change (or \(f''\)).
No sign change means a horizontal inflection, not a turning point.

Frequently asked questions

What is a stationary point?

A point where the derivative is zero, so the curve is momentarily flat.

How do you classify a stationary point?

Check the sign of the first derivative either side (plus then minus is a max), or use the second derivative (negative is a max, positive is a min).

What is a horizontal point of inflection?

A stationary point where the derivative does not change sign, so it is neither a maximum nor a minimum.

What is the first derivative test?

Testing the sign of f prime just before and after a stationary point to decide if it is a maximum, minimum or inflection.