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Year 12 Maths Advanced (2027) Applications of calculus

Stationary Points & the First Derivative Test

20 practice questions 0 video lessons Theory + worked examples

Learn stationary points and the first derivative test for NSW Year 12 Mathematics Advanced (NESA outcome MAV-12-06). Stationary points are where the gradient is zero, and checking the gradient either side reveals whether each one is a peak, a trough or a flat inflection.

You will learn to solve \(f'(x) = 0\), build a gradient table, and classify each point as a local maximum, local minimum or horizontal point of inflection — the essential tool for curve sketching and for finding best or worst values.

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Theory

Stationary points are where \(f'(x)=0\), classified by how \(f'\) changes sign. This Year 12 Mathematics Advanced topic (MAV-12-06) finds and classifies them.

Solve \(f'(x)=0\), then test the sign of \(f'\) either side: \(+\) then \(-\) is a maximum; \(-\) then \(+\) is a minimum; the same sign both sides is a horizontal point of inflection. (Or use \(f''\): \(<0\) max, \(>0\) min.)

Stationary pointsA cubic with a maximum at (-1,2) and a minimum at (1,-2). xy max min
\(y=x^{3}-3x\): a maximum and a minimum.
\[f'(x)=0\ \text{(stationary)};\quad f''<0\ \text{max},\ f''>0\ \text{min}\]
stationary where f prime is zero; f double prime negative max, positive min

Method

  1. Solve \(f'(x)=0\).
  2. Classify by a sign change of \(f'\) (or the sign of \(f''\)).
  3. Find the \(y\)-values by substituting into \(f\).
Example 1 — Find and classify
Classify the stationary point of \(f(x)=x^{2}-6x+5\).
Solution
\(2x-6\)\(=\)\(0\Rightarrow x=3\)
\(f''\)\(=\)\(2>0\ (\text{min})\)
\(f(3)\)\(=\)\(-4\)
Example 2 — Two points
Find the stationary points of \(f(x)=x^{3}-3x\).
Solution
\(3x^{2}-3\)\(=\)\(0\)
\(x\)\(=\)\(\pm 1\)
Example 3 — Classify with f''
Classify them (\(f''=6x\)).
Solution
\(f''(-1)\)\(=\)\(-6<0\ (\text{max})\)
\(f''(1)\)\(=\)\(6>0\ (\text{min})\)
Example 4 — Horizontal inflection
Classify the stationary point of \(f(x)=x^{3}\).
Solution

\(f'=3x^{2}=0\Rightarrow x=0\); \(f'\) is \(+\) both sides, so a horizontal point of inflection at \((0,0)\).

Common pitfalls

Solve \(f'=0\) first.
Classify by a sign change (or \(f''\)).
No sign change means a horizontal inflection, not a turning point.

Frequently asked questions

What is a stationary point?

A point where the derivative is zero, so the curve is momentarily flat.

How do you classify a stationary point?

Check the sign of the first derivative either side (plus then minus is a max), or use the second derivative (negative is a max, positive is a min).

What is a horizontal point of inflection?

A stationary point where the derivative does not change sign, so it is neither a maximum nor a minimum.

What is the first derivative test?

Testing the sign of f prime just before and after a stationary point to decide if it is a maximum, minimum or inflection.