Resources For Teachers For Tutors For Students & Parents Pricing
Year 12 Maths Advanced (2027) Applications of calculus

Curve Sketching using Calculus

20 practice questions 0 video lessons Theory + worked examples

Learn curve sketching using calculus for NSW Year 12 Mathematics Advanced (NESA outcome MAV-12-06). A careful sketch brings together everything the derivatives reveal, so you can draw an accurate graph of an unfamiliar function without a graphing app.

You will learn to combine intercepts, stationary points, points of inflection, domain, symmetry, asymptotes and end behaviour into one clear sketch, for polynomials, exponentials and other functions — a skill that pulls the calculus course together.

Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

Calculus lets you sketch a curve from its key features — intercepts, stationary points and concavity. This Year 12 Mathematics Advanced topic (MAV-12-06) combines them into a graph.

Find the intercepts (\(x=0\) and \(y=0\)), the stationary points (\(f'=0\), classified), and the concavity / inflection (\(f''\)). Then plot and join with the right shape.

A sketched cubicA cubic with a maximum, a minimum and an inflection, ready to sketch. xy max min
\(y=x^{3}-3x\): max \((-1,2)\), min \((1,-2)\), inflection \((0,0)\).
\[\text{intercepts};\quad f'(x)=0;\quad f''(x)\ \text{for concavity}\]
sketch using intercepts, stationary points from f prime, concavity from f double prime

Method

  1. Intercepts: set \(y=0\) and \(x=0\).
  2. Stationary points: \(f'=0\), then classify.
  3. Concavity: use \(f''\); then plot and join.
Example 1 — Intercepts
Find the \(x\)-intercepts of \(y=x^{3}-3x\).
Solution
\(x(x^{2}-3)\)\(=\)\(0\)
\(x\)\(=\)\(0,\ \pm\sqrt3\)
Example 2 — Stationary points
Find the stationary points.
Solution
\(3x^{2}-3\)\(=\)\(0\)
\(x\)\(=\)\(\pm1\)
Example 3 — Classify
Classify them (\(y''=6x\)).
Solution
\(y''(-1)\)\(<\)\(0\ (\text{max})\)
\(y''(1)\)\(>\)\(0\ (\text{min})\)
Example 4 — Inflection
Find the inflection.
Solution
\(6x\)\(=\)\(0\)
\(x\)\(=\)\(0,\ y=0\)

Common pitfalls

Work in order: intercepts, \(f'\), \(f''\).
Classify every stationary point.
Match the concavity when joining points.

Frequently asked questions

How do you sketch a curve using calculus?

Find the intercepts, the stationary points from f prime and classify them, and the concavity from f double prime, then plot the points and join them smoothly.

How do you find intercepts?

Set y equal to zero for x-intercepts and set x equal to zero for the y-intercept.

Why use the second derivative when sketching?

It tells you the concavity and locates points of inflection, so the curve is drawn with the correct bend.

What features should a good sketch show?

Intercepts, stationary points (maxima and minima), and points of inflection, all clearly labelled.