Resources For Teachers For Tutors For Students & Parents AI New Pricing
Year 10 Maths Core Algebra

Algebraic Fractions

20 practice questions 3 video lessons Theory + worked examples

Algebraic Fractions in NSW Year 10 Core maths is about adding, subtracting, multiplying and dividing fractions that contain pronumerals (NESA outcome MA5‑ALG‑C‑01). Most questions have numerical denominators, so the same lowest common denominator method used for ordinary fractions still works.

You will combine fractions such as \(\frac{x+4}{3} + \frac{2x-1}{5}\), take care with signs when subtracting a binomial numerator, multiply fractions and divide by multiplying by the reciprocal, and cancel common factors. A few harder questions factorise before cancelling. You will also write the perimeter of a triangle with fractional side lengths as a single fraction, and spot the error in a student's working. It is part of Year 10 Core Algebra.

Practice 20 questions
Practice questions

Every question with a fully worked solution.

Start practising
Watch 3 video(s)
  • Algebraic Fractions - Video - Adding and Subtracting Algebraic Fractions Watch
  • Algebraic Fractions - Video - Dividing Algebraic Fractions Watch
  • Algebraic Fractions - Video - Multiplying and Dividing Algebraic Fractions Watch
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

An algebraic fraction is a fraction with a pronumeral in it, such as \(\dfrac{x + 3}{4}\). This Year 10 maths page shows how to add and subtract them with a lowest common denominator, how to multiply and divide them by cancelling common factors, and how to leave the answer in simplest form.

An algebraic fraction has a pronumeral in the numerator, the denominator or both. The rules are the same as for number fractions.

To add or subtract, the fractions need the same denominator. Use the lowest common denominator (LCD): the smallest number that every denominator divides into. The LCD of \(4\) and \(6\) is \(12\), not \(24\).

When a numerator has two terms, such as \(x - 1\), treat it as one quantity: keep it in brackets while you multiply it.

To multiply, cancel common factors, then multiply the numerators and the denominators. To divide, multiply by the reciprocal of the second fraction.

A fraction is in simplest form when the numerator and the denominator have no common factor. You can only cancel a factor of the whole numerator and the whole denominator.

Thirds and quarters written as twelfthsTwo bars each split into 12 equal parts. On the top bar one third is shaded and covers 4 twelfths. On the bottom bar one quarter is shaded and covers 3 twelfths. The lowest common denominator of 3 and 4 is 12. 1 third = 4 twelfths 1 quarter = 3 twelfths LCD of 3 and 4 is 12
To add thirds and quarters, rename both as twelfths. The lowest common denominator (LCD) is the smallest number both denominators divide into.
A minus sign multiplies every term in the numeratorArrows show minus 3 multiplying both x and minus 2 in minus 3 times (x minus 2), giving minus 3x plus 6. Below, 4 times (2x plus 5) minus 3 times (x minus 2) expands to 8x plus 20 minus 3x plus 6. a negative number in front of a bracket βˆ’3(x βˆ’ 2) = βˆ’3x + 6 so in a subtraction of fractions 4(2x + 5) βˆ’ 3(x βˆ’ 2) = 8x + 20 βˆ’ 3x + 6
Keep each numerator in brackets. A minus sign in front of a fraction multiplies every term of its numerator.

Adding or subtracting with the LCD, and multiplying and dividing:

\[\dfrac{a}{b} + \dfrac{c}{d} = \dfrac{ad + bc}{bd} \qquad \dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{ac}{bd} \qquad \dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c}\]
ab÷cd=ab×dc

With \(bd\) replaced by the LCD when \(b\) and \(d\) share a factor.

Simplifying a single fraction. Divide the numbers by their HCF and cancel pronumerals: \(\dfrac{15a^3m}{-5am^2} = -\dfrac{3a^2}{m}\).
Factorise, then cancel. Take a common factor out of a numerator or denominator first: \(\dfrac{4x + 6}{8} = \dfrac{2(2x + 3)}{8} = \dfrac{2x + 3}{4}\). A bracket that appears on the top and the bottom cancels, just like a number.

How to add or subtract algebraic fractions

  1. Find the LCD of the denominators.
  2. Rename each fraction: multiply its numerator, in brackets, by the factor that turns its denominator into the LCD. Write a whole number as a fraction over the LCD.
  3. Combine over one denominator. Expand the brackets, taking care with a minus sign in front of a numerator.
  4. Collect like terms in the numerator.
  5. Simplify: if every term of the numerator shares a factor with the denominator, factorise and cancel.

How to multiply or divide

  1. Flip the second fraction if it is a division.
  2. Factorise any numerator or denominator that has a common factor.
  3. Cancel factors common to a numerator and a denominator, then multiply across.
Example 1 β€” Different denominators
Simplify:
(i) \(\dfrac{2a}{3} + \dfrac{a}{4}\)
(ii) \(\dfrac{5m}{6} - \dfrac{2n}{9}\)
Solution

(i) The LCD of \(3\) and \(4\) is \(12\). Rename each fraction, then add the numerators.

\(\dfrac{2a}{3} + \dfrac{a}{4}\)\(=\)\(\dfrac{8a}{12} + \dfrac{3a}{12}\)
\(\)\(=\)\(\boldsymbol{\dfrac{11a}{12}}\)
11a12

(ii) The LCD of \(6\) and \(9\) is \(18\). \(m\) and \(n\) are not like terms, so the numerator stays as two terms.

\(\dfrac{5m}{6} - \dfrac{2n}{9}\)\(=\)\(\dfrac{15m}{18} - \dfrac{4n}{18}\)
\(\)\(=\)\(\boldsymbol{\dfrac{15m - 4n}{18}}\)
15m−4n18
Example 2 β€” Subtracting binomial numerators
Simplify \(\dfrac{2x + 5}{3} - \dfrac{x - 2}{4}\).
Solution

The LCD is \(12\). Multiply each numerator, in brackets, by the factor that makes its denominator \(12\).

\(\)\(\)\(\dfrac{2x + 5}{3} - \dfrac{x - 2}{4}\)
\(\)\(=\)\(\dfrac{4(2x + 5) - 3(x - 2)}{12}\)
\(\)\(=\)\(\dfrac{8x + 20 - 3x + 6}{12}\)
\(\)\(=\)\(\boldsymbol{\dfrac{5x + 26}{12}}\)
5x+2612

\(-3 \times (-2) = +6\). Writing \(-6\) here is the most common mistake.

Example 3 β€” Multiplying and dividing
Simplify:
(i) \(\dfrac{x - 2}{6} \times \dfrac{9}{4}\)
(ii) \(\dfrac{4x + 8}{5} \div \dfrac{3x + 6}{10}\)
Solution

(i) No common denominator is needed. Cancel the common factor \(3\) from \(9\) and \(6\), then multiply.

\(\dfrac{x - 2}{6} \times \dfrac{9}{4}\)\(=\)\(\dfrac{x - 2}{2} \times \dfrac{3}{4}\)
\(\)\(=\)\(\boldsymbol{\dfrac{3(x - 2)}{8}}\)
3(x−2)8

(ii) Multiply by the reciprocal of the second fraction. Factorise each numerator so the common bracket \((x + 2)\) can cancel.

\(\)\(\)\(\dfrac{4x + 8}{5} \div \dfrac{3x + 6}{10}\)
\(\)\(=\)\(\dfrac{4(x + 2)}{5} \times \dfrac{10}{3(x + 2)}\)
\(\)\(=\)\(\dfrac{4 \times 2}{3}\)
\(\)\(=\)\(\boldsymbol{\dfrac{8}{3}}\)
83
Example 4 β€” Three terms in one fraction
Write as a single fraction: \(\dfrac{x}{2} - \dfrac{x + 3}{5} + 2\).
Solution

The LCD of \(2\) and \(5\) is \(10\). Write the whole number \(2\) as \(\dfrac{20}{10}\).

\(\)\(\)\(\dfrac{x}{2} - \dfrac{x + 3}{5} + 2\)
\(\)\(=\)\(\dfrac{5x - 2(x + 3) + 20}{10}\)
\(\)\(=\)\(\dfrac{5x - 2x - 6 + 20}{10}\)
\(\)\(=\)\(\boldsymbol{\dfrac{3x + 14}{10}}\)
3x+1410

Check with \(x = 2\): the question gives \(1 - 1 + 2 = 2\) and the answer gives \(\dfrac{20}{10} = 2\).

Common pitfalls

Brackets around every numerator. In \(\dfrac{2x + 5}{3} - \dfrac{x - 2}{4}\) the second numerator becomes \(-3(x - 2) = -3x + 6\), not \(-3x - 6\).
Only cancel factors, never terms. In \(\dfrac{x + 6}{3}\) you cannot cancel the \(6\) with the \(3\): \(6\) is a term, not a factor of the whole numerator.
Do not add the denominators. \(\dfrac{x}{3} + \dfrac{x}{4}\) is \(\dfrac{7x}{12}\), not \(\dfrac{2x}{7}\). Rename both fractions over the LCD first.
Flip the second fraction only. When dividing, keep the first fraction as it is and multiply by the reciprocal of the second.

Frequently asked questions

How do you add algebraic fractions?

Find the lowest common denominator, rename each fraction so it has that denominator, then add the numerators and collect like terms. Keep each numerator in brackets while you rename it.

Why do you put brackets around the numerator?

Because the whole numerator is multiplied by the same number. For \(\dfrac{x - 2}{4}\) renamed over \(12\), the numerator becomes \(3(x - 2)\), and a minus sign in front changes both signs.

How do you divide algebraic fractions?

Multiply the first fraction by the reciprocal of the second. Then factorise, cancel any common factors and multiply across.

Can you cancel the x in (x + 3) over x?

No. The \(x\) on top is only one term of the numerator, not a factor of it. You can only cancel a factor of the whole numerator and the whole denominator.

What is the lowest common denominator?

The smallest number that every denominator divides into exactly. For \(6\) and \(9\) it is \(18\). Using a bigger common denominator still works, but you have more simplifying to do at the end.