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Year 10 Maths Advanced Single Variable and Bivariant Statistics

Boxplots

20 practice questions 1 video lesson Theory + worked examples

A box plot shows the five-number summary of a data set: a box from \(Q_1\) to \(Q_3\) with a line at the median, and whiskers out to the minimum and maximum. Each section holds about a quarter of the scores. In NSW Year 10 Advanced maths you draw box plots, read them, and use them to make statements about the data (NESA outcome MA5‑DAT‑C‑01).

You will draw box plots from lists, dot plots, column graphs and tables, and read percentages and counts from them, such as how many units rent for between two prices. You will explain why a box plot can have no lower whisker and match a data set to a box plot. Harder questions decide which statements must, could or cannot be true, and rebuild all the scores from a summary and a mean. It is part of Year 10 Advanced Single Variable and Bivariant Statistics.

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Theory

A box plot (box-and-whisker plot) draws the five-number summary to scale: the box runs from \(Q_1\) to \(Q_3\) with a line at the median, and whiskers reach the minimum and maximum. This Year 10 Advanced maths page covers drawing box plots from any data display, marking outliers, reading percentages and counts, and working backwards from a summary to the data.

A box plot is drawn above a number line. The box spans the middle \(50\%\) of the data, from the lower quartile \(Q_1\) to the upper quartile \(Q_3\); its length is the IQR. A vertical line inside it marks the median. The whiskers join the box to the minimum and maximum.

Each of the four sections (whisker, half-box, half-box, whisker) contains about \(25\%\) of the scores. A longer section means those scores are more spread out, not that there are more of them.

An outlier may be drawn as a separate point; the whisker then ends at the most extreme score that is not an outlier. A common test: a score more than \(1.5 \times \text{IQR}\) below \(Q_1\) or above \(Q_3\).

A box plot does not show the mean, the mode or the number of scores.

Parts of a box plotA box plot on a scale from 0 to 60. The left whisker starts at the minimum 8. The box runs from Q1 20 to Q3 36 with the median 26 marked inside it. The right whisker ends at 44, the largest score that is not an outlier, and an outlier at 56 is drawn as a separate circle. 0102030405060 minimum Q₁ median Q₃ max* outlier box = middle 50%, length = IQR
A box plot draws the five-number summary to scale. *When an outlier is marked separately, the whisker stops at the largest (or smallest) score that is not an outlier.
Dot plot and box plot of the same dataA dot plot of 13 scores from 2 to 12, with the same data drawn underneath as a box plot: minimum 2, Q1 3.5, median 5, Q3 7.5, maximum 12. Dashed lines link the five values to the dot plot. 02468101214
The same \(13\) scores as a dot plot and as a box plot. The box plot hides individual scores but shows centre, spread and shape at a glance.
\[\text{min} \;\Big|\; Q_1 \;\Big|\; \text{median} \;\Big|\; Q_3 \;\Big|\; \text{max} \qquad\qquad \text{outlier if } x < Q_1 - 1.5\,\text{IQR} \ \text{ or } \ x > Q_3 + 1.5\,\text{IQR}\]
IQR=Q3−Q1
Part of the box plotFraction of the scores (about)
below \(Q_1\), or above \(Q_3\)\(25\%\) each
between \(Q_1\) and \(Q_3\) (the box)\(50\%\)
above \(Q_1\), or below \(Q_3\)\(75\%\)
above or below the median\(50\%\)
Positions. For \(n = 27\) scores the median is the \(14\)th, \(Q_1\) the \(7\)th and \(Q_3\) the \(21\)st. If \(Q_1\) is the pass mark, at least \(27 - 6 = 21\) students scored at least that mark.
Converting units. If every score is changed by \(y = ax + b\) with \(a > 0\), each of the five values changes the same way, and the IQR is multiplied by \(a\). For \(F = 1.8C + 32\), an IQR of \(5^\circ\)C becomes \(9^\circ\)F.

Drawing a box plot

  1. Order the data (or use running totals for a table or graph) and find the five-number summary.
  2. Draw a number line with an even scale that covers the minimum to the maximum.
  3. Draw the box from \(Q_1\) to \(Q_3\) and a line at the median.
  4. Add the whiskers to the minimum and maximum, or to the last non-outlier, marking any outlier as a dot.

Reading a box plot

  1. Read the five values from the scale.
  2. Percentages: use \(25\%\), \(50\%\), \(75\%\); multiply by the number of scores for 'about how many'.
  3. Spread and shape: IQR \(= Q_3 - Q_1\); compare the two halves of the box and the two whiskers.
  4. Special cases: no whisker means the minimum (or maximum) equals the quartile; a median on the edge of the box means it equals a quartile.
  5. Must, could or cannot: only the five values are certain. Statements about the mean or exact individual scores can only be 'could'.
  6. Working backwards: place the known values at their positions, then use the mean (for a total) and the order of the scores.
Example 1 β€” Draw a box plot with an outlier
The commute times, in minutes, of \(11\) workers were \(12,\ 15,\ 18,\ 19,\ 21,\ 22,\ 24,\ 26,\ 27,\ 30,\ 52\).
(i) Find the five-number summary.
(ii) Use the test "more than \(1.5 \times \text{IQR}\) beyond a quartile" to show that \(52\) is an outlier.
(iii) Draw the box plot and describe the shape.
Solution

(i) The data are in order. Median: the \(6\)th score, \(22\). Lower half \(12, \ldots, 21\): \(Q_1 = 18\). Upper half \(24, \ldots, 52\): \(Q_3 = 27\). Summary: \(\mathbf{12,\ 18,\ 22,\ 27,\ 52}\).

(ii) The IQR is \(27 - 18 = 9\).

\(Q_3 + 1.5 \times \text{IQR}\)\(=\)\(27 + 13.5 = 40.5\)

\(52 > 40.5\), so \(52\) is an outlier. (Nothing is below \(18 - 13.5 = 4.5\).)

(iii) Draw \(52\) as a separate point and end the upper whisker at \(30\), the largest time that is not an outlier.

Box plot of 11 commute timesA box plot on a scale from 10 to 55: whisker from 12 to 18, box from 18 to 27 with the median at 22, whisker from 27 to 30, and the outlier 52 drawn as a separate circle. 10152025303540455055

The median is nearer \(Q_1\) and there is a long tail on the right: positively skewed.

27+1.5×9=40.5
Example 2 β€” Reading a box plot
The box plot shows the ages of \(160\) people at a concert.
Ages at a concertA box plot on a scale from 10 to 65: minimum 14, Q1 19, median 23, Q3 34, maximum 61. 101520253035404550556065
(i) About how many people were aged between \(19\) and \(34\)? (ii) About how many were older than \(19\)? (iii) Find the IQR. (iv) Which quarter of the ages is most spread out? (v) True or false: more people were aged \(34\) to \(61\) than \(14\) to \(19\).
Solution

Read the five values: \(14,\ 19,\ 23,\ 34,\ 61\). Each section holds about a quarter of the people.

\(\text{(i)}\ \ Q_1 \text{ to } Q_3\)\(=\)\(\dfrac{1}{2} \times 160 \approx \mathbf{80}\)
\(\text{(ii)}\ \ \text{above } Q_1\)\(=\)\(\dfrac{3}{4} \times 160 \approx \mathbf{120}\)
\(\text{(iii)}\ \ \text{IQR}\)\(=\)\(34 - 19 = \mathbf{15}~\text{years}\)

(iv) The top quarter runs from \(34\) to \(61\), a spread of \(27\) years, the longest section.

(v) False. Each of those sections holds about \(25\%\) of the people. A longer section means the ages are more spread out, not that there are more people.

34×160=120
Example 3 β€” Box plot from a frequency table
The table shows the number of people in \(25\) cars at a car park.
People in the car\(1\)\(2\)\(3\)\(4\)\(5\)\(6\)
Frequency\(3\)\(5\)\(12\)\(3\)\(1\)\(1\)
Draw a box plot and explain where the median line appears.
Solution

Running totals: \(3,\ 8,\ 20,\ 23,\ 24,\ 25\). The median is the \(13\)th car; each half has \(12\) cars.

\(\text{median}\)\(=\)\(13\text{th} = 3 \quad (8 < 13 \le 20)\)
\(Q_1\)\(=\)\(\text{average of 6th and 7th} = 2\)
\(Q_3\)\(=\)\(\text{average of 19th and 20th} = 3\)

Summary: \(\mathbf{1,\ 2,\ 3,\ 3,\ 6}\).

Box plot with the median on the edge of the boxA box plot on a scale from 0 to 7: whisker from 1 to 2, box from 2 to 3 with the median line on the right edge at 3, and a whisker from 3 to 6. 01234567

The median equals \(Q_3\), so the median line sits on the right edge of the box. So many cars hold \(3\) people that the \(13\)th to the \(20\)th cars are all \(3\).

median=Q3=3
Example 4 β€” Scores from a five-number summary
Seven whole-number scores have five-number summary \(2,\ 4,\ 9,\ 13,\ 20\) and mean \(9\).
(i) Show that the 3rd and 5th scores add to \(15\).
(ii) List every possible set of scores.
(iii) Which set is it if the mode is \(4\)?
Solution

(i) With \(7\) scores, \(Q_1\) is the \(2\)nd score, the median the \(4\)th and \(Q_3\) the \(6\)th. So the scores are \(2,\ 4,\ s_3,\ 9,\ s_5,\ 13,\ 20\).

\(2 + 4 + s_3 + 9 + s_5 + 13 + 20\)\(=\)\(7 \times 9 = 63\)
\(s_3 + s_5\)\(=\)\(15\)

(ii) The order needs \(4 \le s_3 \le 9\) and \(9 \le s_5 \le 13\). Pairs adding to \(15\): \((4, 11),\ (5, 10),\ (6, 9)\). The sets are

\[2, 4, 4, 9, 11, 13, 20 \qquad 2, 4, 5, 9, 10, 13, 20 \qquad 2, 4, 6, 9, 9, 13, 20\]

(iii) Only the first set has \(4\) as its mode: \(\mathbf{2,\ 4,\ 4,\ 9,\ 11,\ 13,\ 20}\).

s3+s5=15

Common pitfalls

Use an even scale. Draw the box plot to scale on a number line; unequal gaps between ticks distort the shape.
A longer section does not hold more scores. Every section holds about a quarter of the data. Length shows spread, not quantity.
Whisker to the last non-outlier. When an outlier is shown as a dot, the whisker stops at the next most extreme score, not at the outlier.
The mean is not on a box plot. The line in the box is the median. You cannot read the mean from a box plot.
Missing whisker or edge median is not an error. It happens when the minimum equals \(Q_1\), or the median equals a quartile, usually because of repeated scores.

Frequently asked questions

How do you draw a box plot?

Find the five-number summary: minimum, lower quartile, median, upper quartile and maximum. Draw a scaled number line, a box from the lower to the upper quartile with a line at the median, and whiskers out to the minimum and maximum.

What percentage of the data is in the box of a box plot?

About 50 percent. The box runs from the lower quartile to the upper quartile, so it holds the middle half of the scores.

How are outliers shown on a box plot?

An outlier can be drawn as a separate dot or cross. The whisker then ends at the most extreme score that is not an outlier.

Why does a box plot sometimes have no whisker?

If the minimum equals the lower quartile, or the maximum equals the upper quartile, that whisker has length zero, so it does not appear.

Can you find the mean from a box plot?

No. A box plot shows only the five-number summary. The mean needs every score, or at least their total.