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Primary - Stage 3 (Year 5 & 6) Stage 3 (Year 5 & 6) Multiplication

Multiply by two-digit numbers - 3-digit x 2-digit

20 practice questions 0 video lessons Theory + worked examples
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Theory

To multiply a three-digit number by a two-digit number, find a partial product for the ones and one for the tens (with a zero placeholder), then add them. The method matches two-by-two with one extra column.

A three-digit number is multiplied by a two-digit multiplier using the same two-row method.

The first partial product comes from the ones digit; the second from the tens digit, with a zero placeholder.

Adding the two partial products gives the answer. There is just one more column than a two-by-two.

Long multiplication: 346 times 25 346 multiplied by 25 set out in columns. The first partial product 346 times 5 is 1730, the second 346 times 20 is 6920, and their sum is 8650. 346 × 25 1730 + 6920 346 × 5 346 × 20 8650
\(346 \times 25 = 8650\). Partial products \(346\times5=1730\) and \(346\times20=6920\); their sum is \(8650\).

Two rows of multiplying across three digits, then one addition.

StepMultiplyPartial product
Ones\(346\times5\)\(1730\)
Tens\(346\times20\)\(6920\)
Add\(1730+6920\)\(8650\)
Every digit is multiplied each row. The tens row keeps its zero placeholder so the columns line up for adding.

How to multiply three digits by two digits

  1. Multiply the three-digit number by the ones digit.
  2. Write a zero, then multiply by the tens digit.
  3. Line up the two partial products by place value.
  4. Add them for the final answer.
Example 1 — Starter
Calculate \(234 \times 12\).
Solution

\(468\) then \(2340\).

\(234 \times 12\)\(=\)\(2808\)
Example 2 — Both partials
Calculate \(346 \times 25\).
Solution

\(1730\) then \(6920\).

\(346 \times 25\)\(=\)\(8650\)
Example 3 — Neat numbers
Calculate \(125 \times 14\).
Solution

\(500\) then \(1250\).

\(125 \times 14\)\(=\)\(1750\)
Example 4 — Fundraising
Each of 32 schools collects $145. What is the total?
Solution
\(145 \times 32\)\(=\)\(4640\)

The total is $4640.

Common pitfalls

Missing a digit. Each row must multiply all three digits of the larger number.
Dropping the tens zero. The second partial product still needs its \(0\) placeholder in the ones place.
Losing a carry. Bigger digits can carry more than once per row, so track each carry carefully.

Frequently asked questions

How do you multiply a three-digit number by a two-digit number?

Multiply the three-digit number by the ones digit, then by the tens digit with a zero placeholder, and add the two partial products. \(346\times25=1730+6920=8650\).

Why is there a zero in the second partial product?

The tens digit stands for tens, so multiplying by it gives a number of tens. The zero in the ones place keeps the digits in their correct columns.

Is this different from two-digit by two-digit?

No, the method is the same. There is just one more column to multiply in each row.

How can I check my answer?

Estimate by rounding: \(346\times25\) is about \(350\times25=8750\), close to \(8650\).

What if a row needs several carries?

Carry each time a product reaches ten, writing the carried digit above the next column and adding it in. Keep track of every carry.