Resources For Teachers For Tutors For Students & Parents Pricing
Year 9 Maths Number and Financial Mathematics

The Real Number System

20 practice questions 0 video lessons Theory + worked examples
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

The real numbers are all the numbers on the number line. Each one is either rational, so it can be written as a fraction of two integers, or irrational, so it cannot. A surd is an irrational root, such as \(\sqrt{7}\) or \(\sqrt[3]{9}\). This Year 9 maths page shows how to sort real numbers, write recurring decimals as fractions, estimate and order surds, and use them in problems. Curriculum: VC2M9N01 / AC9M9N01.

A rational number can be written as \(\dfrac{a}{b}\), where \(a\) and \(b\) are integers and \(b \ne 0\). Integers, fractions, terminating decimals such as \(0.3\) and recurring decimals such as \(0.\dot{4}\dot{5}\) are all rational.

An irrational number cannot be written as a fraction. Its decimal goes on forever without repeating. \(\pi\) is irrational: \(\dfrac{22}{7}\) and \(3.14\) are only approximations.

Together, the rational and irrational numbers make up the real numbers. Every point on the number line is a real number.

A surd is a root that is irrational, such as \(\sqrt{7}\), \(\sqrt{50}\) or \(\sqrt[3]{9}\). A root is a surd only when it does not come out exactly: \(\sqrt{36} = 6\) and \(\sqrt[3]{8} = 2\) are rational, so they are not surds. \(\pi\) is irrational but is not a surd, because it is not a root of a rational number.

A surd is an exact value. A decimal such as \(\sqrt{7} \approx 2.65\) is only a rounded approximation. The square root of a negative number, such as \(\sqrt{-4}\), is not a real number, because no real number squares to a negative.

Rational and irrational numbersA box for the real numbers split into two parts. Rational: integers, fractions, terminating decimals, recurring decimals and roots that come out exactly, such as root 36 equals 6. Irrational: surds such as root 2, root 50 and cube root 9, and pi, which is irrational but not a surd. Real numbers Rational integers: βˆ’3, 0, 18 fractions: 2/7, 5/11 terminating: 0.3, 1.25 recurring: 0.4545… √36 = 6, βˆ›8 = 2 Irrational surds: √2, √50, βˆ›9 not surds: Ο€
Every real number is rational or irrational. A surd is an irrational root, such as \(\sqrt{2}\). \(\pi\) is irrational but not a surd.
Irrational numbers on a number lineA number line from 0 to 5 with root 2 at about 1.41, root 5 at about 2.24, pi at about 3.14, root 11 at about 3.32 and root 19 at about 4.36. 0 1 2 3 4 5 √2 √5 Ο€ √11 √19
Irrational numbers still have a place on the number line. \(\sqrt{19}\) sits between \(4\) and \(5\) because \(16 \lt 19 \lt 25\).

A number is rational if it can be written as \(\dfrac{a}{b}\), with \(a\) and \(b\) integers and \(b \ne 0\). Otherwise it is irrational.

For a whole number \(n\):

\[\sqrt{n}\ \text{is rational} \iff n \text{ is a perfect square}\]\[\sqrt[3]{n}\ \text{is rational} \iff n \text{ is a perfect cube}\]
n rational if and only if n is a perfect square

Rules for working with roots of positive numbers:

\[\sqrt{a}\times\sqrt{b} = \sqrt{ab}\]\[\sqrt{\dfrac{a}{b}} = \dfrac{\sqrt{a}}{\sqrt{b}}\]\[(\sqrt{a})^2 = a\]
a×b=ab
Recurring decimals to fractions. One repeating digit goes over \(9\): \(0.\dot{8} = \dfrac{8}{9}\). A repeating block of two digits goes over \(99\): \(0.\dot{3}\dot{6} = \dfrac{36}{99} = \dfrac{4}{11}\). For a whole-number part, keep it in front: \(2.\dot{8} = 2\dfrac{8}{9}\).
Between two whole numbers. Find the perfect squares either side. \(25 \lt 30 \lt 36\), so \(\sqrt{30}\) lies between \(5\) and \(6\).
Ordering. Write every number as a decimal to three or four places, then compare. A surd or \(\pi\) needs a calculator; a recurring decimal is written out with its repeating digits.
Rational plus irrational. Adding a rational number to an irrational one, or multiplying an irrational one by a non-zero rational, always gives an irrational number. So \(3 - \sqrt{2}\) and \(5\sqrt{7}\) are irrational.

How to decide if a number is rational or a surd

  1. Simplify first: evaluate roots of perfect squares and cubes, and write decimals as fractions.
  2. Check the number under the root. For \(\sqrt{n}\), is \(n\) a perfect square? For \(\sqrt[3]{n}\), a perfect cube? For a fraction, check top and bottom.
  3. Decide. If the result is a whole number, fraction, terminating or recurring decimal, it is rational. An irrational root is a surd. A square root of a negative number is not real.
  4. To decide whether \(\sqrt{an}\) is rational for a whole number \(n\), check whether \(an\) is a perfect square.
  5. To show a decimal is only an approximation, square it: \(1.73^2 = 2.9929\), not \(3\), so \(\sqrt{3} \ne 1.73\).
Example 1 β€” Surd, rational or not real?
Classify each number as rational, a surd, or not a real number.
(i) \(\sqrt{0.09}\)
(ii) \(\sqrt{\dfrac{7}{25}}\)
(iii) \(\sqrt[3]{40}\)
(iv) \(\sqrt{-16}\)
Solution

Try to write each one as a fraction of two integers.

\(\sqrt{0.09}\)\(=\)\(\sqrt{\dfrac{9}{100}} = \dfrac{3}{10}\)
\(\sqrt{\dfrac{7}{25}}\)\(=\)\(\dfrac{\sqrt{7}}{5}\)
0.09=0.3,725=75

(i) \(0.3\) is a fraction, so \(\sqrt{0.09}\) is rational.

(ii) \(7\) is not a perfect square, so \(\sqrt{7}\) is irrational and \(\sqrt{\dfrac{7}{25}}\) is a surd.

(iii) \(3^3 = 27\) and \(4^3 = 64\), so \(40\) is not a perfect cube. \(\sqrt[3]{40}\) lies between \(3\) and \(4\) and is a surd.

(iv) Any real number squared is \(0\) or positive, so no real number squares to \(-16\). \(\sqrt{-16}\) is not a real number.

Example 2 β€” Estimating and perfect squares
Without a calculator:
(i) find the two consecutive whole numbers between which \(\sqrt{75}\) lies
(ii) find every whole number \(n\) from \(1\) to \(30\) for which \(\sqrt{3n}\) is rational.
Solution

(i) Find the perfect squares either side of \(75\):

\(8^2 = 64\)\(\lt \)\(75 \lt 81 = 9^2\)
8<75<9

So \(\sqrt{75}\) lies between \(\mathbf{8}\) and \(\mathbf{9}\).

(ii) \(\sqrt{3n}\) is rational only when \(3n\) is a perfect square. For \(n\) from \(1\) to \(30\), \(3n\) goes from \(3\) to \(90\). The perfect squares in that range that are multiples of \(3\) are:

\(3n\)\(=\)\(9,\ 36,\ 81\)
\(n\)\(=\)\(\boldsymbol{3,\ 12,\ 27}\)
n=3,12,27

Check: \(\sqrt{9} = 3\), \(\sqrt{36} = 6\) and \(\sqrt{81} = 9\). The other perfect squares up to \(90\) (\(4, 16, 25, 49, 64\)) are not multiples of \(3\).

Example 3 β€” Recurring decimals are rational
Show that each number is rational by writing it as a fraction in simplest form.
(i) \(0.\dot{8}\)
(ii) \(0.\dot{3}\dot{6}\)
Solution

(i) One digit repeats, so multiply by \(10\). Subtracting removes the repeating tail:

\(x\)\(=\)\(0.888\ldots\)
\(10x\)\(=\)\(8.888\ldots\)
\(10x - x\)\(=\)\(8\)
\(9x\)\(=\)\(8\)
\(x\)\(=\)\(\mathbf{\dfrac{8}{9}}\)

(ii) Two digits repeat, so multiply by \(100\):

\(x\)\(=\)\(0.363636\ldots\)
\(100x\)\(=\)\(36.363636\ldots\)
\(99x\)\(=\)\(36\)
\(x\)\(=\)\(\dfrac{36}{99} = \mathbf{\dfrac{4}{11}}\)

Both are fractions of two integers, so both are rational. Every recurring decimal can be written this way.

Example 4 β€” Real numbers in order and in use
(i) Write \(\sqrt{7}\), \(2.65\) and \(\dfrac{8}{3}\) in ascending order.
(ii) A square tile has an area of \(30~\text{cm}^2\), so its side is \(\sqrt{30}\) cm. Find its perimeter, correct to \(2\) decimal places.
Solution

(i) Write each number as a decimal to four places:

\(\sqrt{7}\)\(=\)\(2.6457\ldots\)
\(2.65\)\(=\)\(2.6500\)
\(\dfrac{8}{3}\)\(=\)\(2.6666\ldots\)

So the order is \(\boldsymbol{\sqrt{7},\ 2.65,\ \dfrac{8}{3}}\). Note that \(\dfrac{8}{3} = 2.\dot{6}\) is rational, but \(\sqrt{7}\) is not.

(ii) Four equal sides. Keep the exact value \(4\sqrt{30}\) and round only at the end:

\(P\)\(=\)\(4\sqrt{30}\)
\(\)\(=\)\(21.9089\ldots\)
\(\)\(\approx\)\(\mathbf{21.91}\ \textbf{cm}\)

Rounding the side first, to \(5.48\), would give \(21.92\) cm, which is wrong.

Common pitfalls

A root sign does not make a surd. \(\sqrt{1.21} = 1.1\) and \(\sqrt[3]{27} = 3\) are rational. Evaluate first, then decide.
Approximations are not exact. A calculator shows \(\sqrt{7} = 2.6457513\ldots\), but any rounded value squared misses \(7\). Write \(\sqrt{7}\) when an exact answer is needed.
\(\sqrt{a} + \sqrt{b}\) is not \(\sqrt{a + b}\). \(\sqrt{9} + \sqrt{16} = 3 + 4 = 7\), but \(\sqrt{25} = 5\). Roots multiply under one sign; they do not add under one sign.
\(\sqrt{-16}\) is not \(-4\). \((-4)^2 = 16\), not \(-16\). A square root of a negative number is not real. A cube root of a negative number is fine: \(\sqrt[3]{-8} = -2\).

Frequently asked questions

What is a surd?

A surd is a root that cannot be simplified to a rational number, such as \(\sqrt{7}\) or \(\sqrt[3]{9}\). Its decimal goes on forever without repeating, so a surd is left in root form as an exact value.

What is the difference between rational and irrational numbers?

A rational number can be written as a fraction of two integers, so its decimal ends or repeats. An irrational number cannot, so its decimal never ends and never repeats.

Is pi a surd?

No. \(\pi\) is irrational, but a surd is an irrational root of a rational number, and \(\pi\) is not one. \(\dfrac{22}{7}\) is only an approximation of \(\pi\).

How do you tell if a square root is rational?

Simplify what is under the root. For a whole number, the square root is rational only if the number is a perfect square, like \(49\). For a fraction or decimal, write it as a fraction and check the top and bottom.

What are the real numbers?

All the rational numbers and all the irrational numbers together. Every point on the number line is a real number. The square root of a negative number, such as \(\sqrt{-9}\), is not a real number.