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Year 8 Maths Volume

Volume of a Prism

20 practice questions 2 video lessons Theory + worked examples
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Theory

A prism has the same cross-section all the way through. Its volume is the area of the cross-section times the height: \(V = Ah\). A triangular prism with a right-angled cross-section of sides \(4\) cm and \(5\) cm, \(6\) cm long, has \(V = 10 \times 6 = 60~\text{cm}^3\). This Year 8 maths page shows how.

The shape that runs all the way through is the cross-section. Every slice parallel to the ends is the same shape and size: a uniform cross-section.

\(V = Ah\), where \(A\) is the area of the cross-section and \(h\) is the distance between the ends, measured at right angles to the cross-section. When a prism lies on its side, \(h\) is its length.

Two steps, every time: find \(A\), then multiply by \(h\).

Areas you need: rectangle \(lw\); triangle \(\dfrac{1}{2}bh\); parallelogram \(bh\); trapezium \(\dfrac{1}{2}(a + b)h\); rhombus or kite \(\dfrac{1}{2}xy\); sector \(\dfrac{\theta}{360} \times \pi r^2\).

A hole straight through belongs to the cross-section: take its area off \(A\) first.

Working backwards: \(A = V \div h\) or \(h = V \div A\). A cube has \(V = s^3\), so \(s = \sqrt[3]{V}\).

Scaling and context. Halving the area halves the volume; tripling the length triples it. Cost \(=\) volume \(\times\) price per cubic metre; \(1~\text{m}^3\) of water is \(1\) kL.

Triangular prism A prism lying on its side with a shaded right-angled triangle cross-section at the front; its length h runs back. base h
The shaded face is the cross-section; \(h\) runs at right angles to it, along the prism.
Trapezium prism A prism whose shaded front face is a trapezium; its length h runs back. h
A trapezium cross-section: find its area first, then multiply by \(h\).

Volume of a prism:

\[ V = Ah \]
V = A h
A sloping side is never a perpendicular height. In a triangle or trapezium, use the length at right angles to the base.
Same units first. Change \(40\) cm to \(0.4\) m before multiplying with lengths in metres.

How to find the volume of a prism

  1. Identify the cross-section and the height \(h\) at right angles to it.
  2. Find the area \(A\) of the cross-section.
  3. Multiply: \(V = Ah\), in cubic units.
Example 1 — A triangular prism
Find the volume of this triangular prism.
Triangular prism 4 by 5 by 6 A triangular prism: the right-angled triangle cross-section has sides 4 cm and 5 cm; the prism is 6 cm long. 4 cm 5 cm 6 cm
Solution
\(A\)\(=\)\(\dfrac{1}{2} \times 4 \times 5 = 10\)
\(V\)\(=\)\(10 \times 6 = 60\)
60 cm

\(60~\text{cm}^3\)

Example 2 — A trapezium base
A prism has a trapezium cross-section with parallel sides \(2\) cm and \(5\) cm, \(3\) cm apart. The prism is \(4\) cm long. Find its volume.
Solution
\(A\)\(=\)\(\dfrac{1}{2} \times 3 \times (2 + 5) = \dfrac{21}{2}\)
\(V\)\(=\)\(\dfrac{21}{2} \times 4 = 42\)
42 cm

\(42~\text{cm}^3\) (cubic units, because it is a volume).

Example 3 — A prism standing up
A prism stands on its triangular end. The triangle has base \(8\) cm and perpendicular height \(7\) cm, and the prism is \(5\) cm high. Find
(i) the area of the cross-section
(ii) the volume
Solution
\(A\)\(=\)\(\dfrac{1}{2} \times 8 \times 7 = 28\)
\(V\)\(=\)\(28 \times 5 = 140\)
28 cm 140 cm

(i) \(28~\text{cm}^2\)
(ii) \(140~\text{cm}^3\)

Example 4 — Trapezium cross-section and cost
A concrete kerb is a prism \(8\) m long. Its cross-section is a trapezium with parallel sides \(0.3\) m and \(0.2\) m, \(0.25\) m apart. Concrete costs \(\$220\) per cubic metre. Find the cost.
Solution
\(A\)\(=\)\(\dfrac{1}{2} \times 0.5 \times 0.25\)
\(\)\(=\)\(0.0625\)
\(V\)\(=\)\(0.0625 \times 8 = 0.5\)
\(0.5 \times 220\)\(=\)\(110\)
$110

The concrete costs \(\$110\).

Example 5 — Working backwards
(i) A triangular prism has a volume of \(486~\text{cm}^3\). Its cross-section has base \(9\) cm and height \(12\) cm. How long is it?
(ii) A cube has a volume of \(512~\text{cm}^3\). How long is each edge?
Solution
\(A\)\(=\)\(\dfrac{1}{2} \times 9 \times 12 = 54\)
\(h\)\(=\)\(486 \div 54 = 9\)
\(s\)\(=\)\(\sqrt[3]{512} = 8\)
9 cm 8 cm

(i) \(9\) cm
(ii) \(8\) cm, because \(8 \times 8 \times 8 = 512\).

Example 6 — A sector cross-section
A fan-shaped paver is a prism \(8\) cm thick. Its cross-section is a sector of radius \(15\) cm and angle \(60^\circ\). Find its volume, to \(1\) decimal place.
Solution
\(A\)\(=\)\(\dfrac{60}{360} \times \pi \times 15^2 = 37.5\pi\)
\(V\)\(=\)\(37.5\pi \times 8 = 300\pi\)
\(\)\(=\)\(942.47\ldots\)
942.5 cm

\(942.5~\text{cm}^3\)

Common pitfalls

Using a slant length. Only the perpendicular height goes into the area formula.
Mixing h with a measurement of the cross-section. h is the distance between the two ends.
Mixing units. Change every length to one unit before multiplying.
Using V = Ah for a pyramid. A solid that tapers to a point is not a prism.

Frequently asked questions

What is a prism?

A solid with the same cross-section all the way through, such as a triangular prism.

What is the formula for the volume of a prism?

\(V = Ah\): area of the cross-section times the height.

What is a cross-section?

The shape you see when you slice a solid parallel to its ends.

How do I find the length of a prism from its volume?

Divide the volume by the area of the cross-section: \(h = V \div A\).

How do I find the edge of a cube from its volume?

Take the cube root: \(s = \sqrt[3]{V}\).