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Year 7 Maths Fractions

Fractions

20 practice questions 2 video lessons Theory + worked examples
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Practice questions

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Theory

A fraction \(\dfrac{a}{b}\) has a numerator \(a\) (top) and a denominator \(b\) (bottom). Equivalent fractions name the same amount, such as \(\dfrac{3}{4}\) and \(\dfrac{6}{8}\). This Year 7 maths page covers proper and improper fractions, mixed numerals, equivalent fractions, simplest form using the HCF, and comparing fractions.

In \(\dfrac{a}{b}\), the numerator \(a\) is the top number and the denominator \(b\) is the bottom number.

A proper fraction has a numerator less than its denominator: \(\dfrac{5}{7}\), \(\dfrac{41}{100}\). An improper fraction has a numerator equal to or bigger than its denominator: \(\dfrac{7}{5}\), \(\dfrac{100}{41}\).

A mixed numeral is a whole number and a proper fraction: \(3\dfrac{5}{6}\), \(10\dfrac{1}{7}\).

Equivalent fractions name the same amount. Multiply or divide the numerator and the denominator by the same number: \(\dfrac{3}{4} = \dfrac{6}{8} = \dfrac{9}{12} = \dfrac{12}{16}\).

The highest common factor (HCF) is the largest number that divides both numbers. A fraction is in simplest form when the only common factor of the top and bottom is \(1\).

Three quarters equals six eighths Two bars of the same length. The top bar is cut into 4 equal parts with 3 shaded. The bottom bar is cut into 8 equal parts with 6 shaded. The shaded lengths match. 34 68
Cutting each quarter in half makes eighths, so \(\dfrac{3}{4} = \dfrac{6}{8}\).
Two and three fifths as thirteen fifths Three bars each cut into 5 equal parts. The first two bars are fully shaded (1 whole each) and 3 parts of the third bar are shaded. Altogether 13 fifths are shaded. 1 whole 1 whole 35
\(2\dfrac{3}{5}\) is \(2\) wholes and \(3\) fifths: \(5 + 5 + 3 = 13\) fifths, so \(2\dfrac{3}{5} = \dfrac{13}{5}\).

Converting and simplifying:

\[ 6\dfrac{3}{4} = \dfrac{4 \times 6 + 3}{4} = \dfrac{27}{4} \]
63/4=(4×6+3)/4=27/4
\[ \dfrac{45}{7} = 45 \div 7 = 6 \text{ remainder } 3 = 6\dfrac{3}{7} \]
45/7=6 remainder 3=63/7
\[ \dfrac{36}{40} = \dfrac{18}{20} = \dfrac{9}{10} \]
36/40=18/20=9/10
Use the HCF to simplify in one step. Factors of \(18\): \(1, 2, 3, 6, 9, 18\). Factors of \(24\): \(1, 2, 3, 4, 6, 8, 12, 24\). The HCF is \(6\), so \(\dfrac{18}{24} = \dfrac{3}{4}\).
Comparing fractions. Write both with the same denominator, then compare the numerators. The lowest common denominator (LCD) is the smallest number both denominators divide into.

How to write a mixed numeral as an improper fraction

  1. Multiply the whole number by the denominator.
  2. Add the numerator, and keep the denominator: \(6\dfrac{3}{4} = \dfrac{27}{4}\).

How to write an improper fraction as a mixed numeral

  1. Divide the numerator by the denominator.
  2. The remainder is the new numerator: \(\dfrac{45}{7} = 6\dfrac{3}{7}\).

How to simplify a fraction

  1. Find the HCF of the numerator and denominator.
  2. Divide both by the HCF.
Example 1 — Find the pronumeral
Find the value of \(x\) if \(\dfrac{2}{3} = \dfrac{x}{9}\).
Solution
\(\dfrac{2}{3}\)\(=\)\(\dfrac{2 \times 3}{3 \times 3}\)
\(\)\(=\)\(\dfrac{6}{9}\)
2/3=6/9

\(3 \times 3 = 9\), so multiply the top by \(3\) too: \(x = 6\).

Example 2 — Missing numbers
Find the missing number.
(i) \(\dfrac{4}{7} = \dfrac{\square}{28}\)
(ii) \(\dfrac{3}{8} = \dfrac{15}{\square}\)
Solution

(i) \(28 \div 7 = 4\), so multiply the top by \(4\).
(ii) \(15 \div 3 = 5\), so multiply the bottom by \(5\).

(i) \(16\)
(ii) \(40\)

Example 3 — HCF and simplest form
Find the HCF of \(18\) and \(30\). Use it to write \(\dfrac{18}{30}\) in simplest form.
Solution

Factors of \(18\): \(1, 2, 3, 6, 9, 18\). Factors of \(30\): \(1, 2, 3, 5, 6, 10, 15, 30\). The HCF is \(6\).

\(\dfrac{18}{30}\)\(=\)\(\dfrac{18 \div 6}{30 \div 6}\)
\(\)\(=\)\(\dfrac{3}{5}\)
18/30=3/5

\(\dfrac{3}{5}\)

Example 4 — Improper to mixed
Write \(\dfrac{24}{5}\) as a mixed numeral.
Solution
\(\dfrac{24}{5}\)\(=\)\(\dfrac{20}{5} + \dfrac{4}{5}\)
\(\)\(=\)\(4\dfrac{4}{5}\)
24/5=20/5+4/5=44/5

\(24 \div 5\) is \(4\) remainder \(4\), so \(4\dfrac{4}{5}\).

Example 5 — Mixed and improper
(i) Write \(4\dfrac{2}{3}\) as an improper fraction.
(ii) Write \(\dfrac{45}{12}\) in simplest form, then as a mixed numeral.
Solution
\(4\dfrac{2}{3}\)\(=\)\(\dfrac{12}{3} + \dfrac{2}{3} = \dfrac{14}{3}\)
\(\dfrac{45}{12}\)\(=\)\(\dfrac{15}{4} = 3\dfrac{3}{4}\)
42/3=14/3,45/12=15/4=33/4

(i) \(\dfrac{14}{3}\)
(ii) HCF \(3\): \(\dfrac{15}{4} = 3\dfrac{3}{4}\)

Example 6 — Compare in context
In class 7A, \(14\) of the \(24\) students walk to school. In class 7B, \(15\) of the \(28\) walk. Which class has the larger fraction of walkers?
Solution
\(\dfrac{14}{24}\)\(=\)\(\dfrac{7}{12} = \dfrac{49}{84}\)
\(\dfrac{15}{28}\)\(=\)\(\dfrac{45}{84}\)
14/24=7/12=49/84,15/28=45/84

The LCD of \(12\) and \(28\) is \(84\). \(49 > 45\), so 7A has the larger fraction.

Common pitfalls

Adding instead of multiplying. Adding the same number to the top and bottom changes the size: \(\dfrac{1}{2}\) is not \(\dfrac{1 + 2}{2 + 2} = \dfrac{3}{4}\).
Stopping before simplest form. \(\dfrac{12}{18} \div 2\) gives \(\dfrac{6}{9}\), which still simplifies. The HCF is \(6\): \(\dfrac{2}{3}\).
Converting a mixed numeral wrongly. \(3\dfrac{2}{5} = \dfrac{3 \times 5 + 2}{5} = \dfrac{17}{5}\), not \(\dfrac{6}{5}\).
One part short is not equal. \(\dfrac{2}{3}\) and \(\dfrac{3}{4}\) are each one part short of a whole, but \(\dfrac{8}{12} < \dfrac{9}{12}\).

Frequently asked questions

What is an equivalent fraction?

A fraction that names the same amount, made by multiplying or dividing the top and bottom by the same number. \(\dfrac{3}{4} = \dfrac{6}{8}\).

How do you simplify a fraction?

Divide the top and bottom by their HCF. \(\dfrac{18}{30} = \dfrac{3}{5}\).

How do you change a mixed numeral to an improper fraction?

Multiply the whole number by the denominator and add the numerator. \(6\dfrac{3}{4} = \dfrac{27}{4}\).

What is an improper fraction?

A fraction whose numerator is equal to or bigger than its denominator, such as \(\dfrac{13}{5}\).

How do you compare two fractions?

Write them with the same denominator and compare the numerators.