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Year 6 Maths Patterns & Rules

Determine a rule from a table of values

20 practice questions 0 video lessons Theory + worked examples
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Theory

A table of values pairs each input with an output made by the same rule. When the inputs go up by \(1\), the gap between outputs tells you the multiplier; then you find what to add or subtract. This Year 6 maths page shows how to find one-step and two-step rules, test them on every row, and use them to find any output or to work back to an input.

An input goes into the rule and an output comes out. The rule must work for every row.

A one-step rule adds, subtracts, multiplies or divides once: input \(\times 7\), or input \(+ 9\).

A two-step rule does two operations in order, such as multiply by \(4\), then add \(3\).

When the inputs go up by \(1\), the outputs go up by the multiplier. Outputs \(7, 11, 15, 19\) go up by \(4\), so the rule starts "multiply by \(4\)"; \(1 \times 4 = 4\) and \(7 - 4 = 3\), so it is multiply by \(4\), then add \(3\).

To work backwards, undo the steps in reverse order: subtract \(3\), then divide by \(4\).

Table for multiply by 4 then add 3 A table with inputs 1, 2, 3, 4 and outputs 7, 11, 15, 19. Arrows under the outputs show each gap is plus 4. Input 1 2 3 4 Output 7 11 15 19 +4 +4 +4
The outputs go up by \(4\): multiply by \(4\). Then \(1 \times 4 + 3 = 7\), so add \(3\).
Two-step machine A machine: input 5, multiply by 4 to get 20, then add 3 to get the output 23. 5 20 23 × 4 ÷ 4 + 3 − 3
A two-step rule as a machine. Going back, undo the steps: \(-3\) then \(\div 4\).

Finding a rule when the inputs go up by 1:

\[ \text{multiplier} = \text{gap between outputs} \]
multiplier = gap between outputs
\[ \text{extra} = \text{output} - \text{input} \times \text{multiplier} \]
extra = output − input × multiplier
\[ \text{output} = \text{input} \times 4 + 3 \]
output = input ×4+3
Test every row. A rule that only fits the first row is not the rule.
Inputs that skip. If the inputs go up by \(2\), the output gap is twice the multiplier.

Finding the rule

  1. Check that the inputs go up by \(1\) (if not, divide the output gap by the input gap).
  2. Gap between outputs = multiplier.
  3. Multiply the first input; add or subtract to reach the first output.
  4. Test the rule on every row.

Working backwards from an output

  1. Undo the last step first (add becomes subtract).
  2. Then undo the multiply by dividing.
Example 1 — One-step multiply
Inputs \(1, 2, 3\) give outputs \(7, 14, 21\). Find the rule and the output for input \(9\).
Solution
\(9 \times 7\)\(=\)\(63\)
9×7=63

Multiply by \(7\); output \(63\).

Example 2 — One-step add
Inputs \(1, 2, 3\) give outputs \(17, 18, 19\). Find the rule and the output for input \(25\).
Solution
\(25 + 16\)\(=\)\(41\)
25+16=41

Add \(16\); output \(41\).

Example 3 — Two-step rule
Use the first diagram. Find the rule and the output for input \(12\).
Solution
\(12 \times 4 + 3\)\(=\)\(51\)
12×4+3=51

Multiply by \(4\), then add \(3\); output \(51\).

Example 4 — Test every row
Inputs \(1, 2, 3\) give outputs \(4, 7, 10\). Max says the rule is "add \(3\)". Is he right?
Solution
\(2 + 3\)\(=\)\(5\)
2+3=5, not 7

No: add \(3\) gives \(5\) for input \(2\), not \(7\). The outputs go up by \(3\), so the rule is multiply by \(3\), then add \(1\).

Example 5 — Inputs that skip
Inputs \(2, 4, 6\) give outputs \(10, 16, 22\). Find the rule and the output for input \(10\).
Solution

Inputs go up by \(2\) and outputs by \(6\), so the multiplier is \(6 \div 2 = 3\). \(2 \times 3 = 6\) and \(10 - 6 = 4\).

\(10 \times 3 + 4\)\(=\)\(34\)
10×3+4=34

Multiply by \(3\), then add \(4\); output \(34\).

Example 6 — Work backwards
The rule is multiply by \(4\), then add \(3\). An output is \(63\). What is the input?
Solution
\(63 - 3\)\(=\)\(60\)
\(60 \div 4\)\(=\)\(15\)
(63−3)÷4=15

\(15\). Check: \(15 \times 4 + 3 = 63\).

Example 7 — Hiring bikes
Bike hire: \(1\) hour costs \(\$13\), \(2\) hours \(\$18\), \(3\) hours \(\$23\).
(i) Find the rule.
(ii) What do \(8\) hours cost?
Solution
\(8 \times 5 + 8\)\(=\)\(48\)
8×5+8=48

(i) Multiply the hours by \(5\), then add \(8\) (a \(\$5\) hourly rate plus an \(\$8\) fee).
(ii) \(\$48\)

Example 8 — Find the mistake
Inputs \(1, 2, 3\) give outputs \(6, 10, 14\). Leo sees the outputs go up by \(4\) and says the rule is "multiply by \(4\)". Explain the mistake and find the output for input \(15\).
Solution
\(15 \times 4 + 2\)\(=\)\(62\)
15×4+2=62

Multiply by \(4\) gives \(4\) for input \(1\), not \(6\); she must also add \(2\). Output \(62\).

Common pitfalls

Testing only the first row. Check the rule on every row of the table.
Using the gap as the whole rule. Outputs going up by \(4\) means multiply by \(4\), then add or subtract something.
Ignoring skipped inputs. Divide the output gap by the input gap to find the multiplier.
Undoing in the wrong order. Work backwards: undo the add first, then the multiply.

Frequently asked questions

How do I find a rule from a table?

Find the gap between outputs (the multiplier), then add or subtract to match the first row. Test every row.

What is a two-step rule?

A rule with two operations in order, such as multiply by \(4\), then add \(3\).

How do I find the input from an output?

Undo the steps in reverse order.

What if the inputs do not go up by 1?

Divide the output gap by the input gap.

Why must the rule work for every row?

Many rules fit one row; only the true rule fits them all.