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Year 3 Maths Whole Numbers & Place Value

Partition & rename numbers (standard & non-standard)

20 practice questions 0 video lessons Theory + worked examples
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Theory

Partitioning and renaming numbers is a Year 3 place value skill: splitting a number into thousands, hundreds, tens and ones, writing it in standard and expanded form, and renaming it in non-standard ways. This Year 3 maths page explains how 324 can be shown as 3 hundreds, 2 tens and 4 ones, or renamed as 2 hundreds, 12 tens and 4 ones, how many tens or hundreds are in a number, and why renaming helps with subtraction. Curriculum: VC2M3N02, VC2M3N04 / AC9M3N01, AC9M3N03.

To partition a number means to split it into parts by place value. The usual way is standard partitioning: break the number into thousands, hundreds, tens and ones. For example, \(324\) is \(3\) hundreds, \(2\) tens and \(4\) ones, so \(324 = 300 + 20 + 4\). Written as a sum like this it is in expanded form. In \(7091\) there are no hundreds, so \(7091 = 7000 + 90 + 1\).

Non-standard partitioning splits the same number a different way, using more than \(9\) in a place. You can rename \(324\) as \(2\) hundreds, \(12\) tens and \(4\) ones, which is \(200 + 120 + 4\). The number has not changed, it is just grouped differently.

Renaming works because ten of one place makes one of the next: \(10\) ones \(= 1\) ten, \(10\) tens \(= 1\) hundred, and \(10\) hundreds \(= 1\) thousand. So a whole number can be counted in any place: \(5300\) is \(53\) hundreds or \(530\) tens altogether.

Base ten blocks showing 324 partitioned in the standard way Three hundred-flats, two ten-rods and four unit cubes make 324: 3 hundreds is 300, 2 tens is 20 and 4 ones is 4. 3 hundreds= 300 2 tens= 20 4 ones= 4
Standard partition: \(324\) as \(3\) hundreds, \(2\) tens and \(4\) ones.
Base ten blocks showing 324 renamed as 2 hundreds, 12 tens and 4 ones Two hundred-flats, twelve ten-rods and four unit cubes still make 324: 2 hundreds is 200, 12 tens is 120 and 4 ones is 4. 2 hundreds= 200 12 tens= 120 4 ones= 4
Renamed: the same \(324\) as \(2\) hundreds, \(12\) tens and \(4\) ones.
Place value chart for 7091 A place value chart with the digits 7, 0, 9 and 1 under thousands, hundreds, tens and ones, with values 7000, 0, 90 and 1. ThousandsHundredsTensOnes 7091 70000901
\(7091 = 7000 + 90 + 1\): the empty hundreds place is left out of the sum.

Renaming does not need formulas, but these place value facts are the ones to remember. Ten of one place always makes one of the next.

\[ 10 \text{ ones} = 1 \text{ ten} \]
10 ones =1 ten
\[ 10 \text{ tens} = 1 \text{ hundred} \]
10 tens =1 hundred
\[ 10 \text{ hundreds} = 1 \text{ thousand} \]
10 hundreds =1 thousand
\[ 324 = 300 + 20 + 4 = 200 + 120 + 4 \]
324=300+20+4=200+120+4
\[ 5300 = 53 \text{ hundreds} = 530 \text{ tens} \]
5300=53 hundreds =530 tens
Standard vs non-standard. Standard partitioning keeps each place under \(10\), like \(324 = 300 + 20 + 4\). Non-standard partitioning lets a place hold \(10\) or more, like \(324 = 200 + 120 + 4\). Both name the same number.
How many tens or hundreds altogether? Cover the ones digit to see the number of tens: \(5300\) has \(530\) tens. Cover the tens and ones to see the number of hundreds: \(53\) hundreds. Cover the last three digits to see the whole thousands: \(61\,208\) has \(61\) thousands.

How to rename a number

  1. Partition first. Split the number into standard place value parts: thousands, hundreds, tens and ones.
  2. Trade a place. Swap \(1\) hundred for \(10\) tens, or \(1\) ten for \(10\) ones, wherever you need more. Ten of one place makes one of the next.
  3. Check the total. Add the new parts. They must still make the number you started with.

How to read non-standard blocks

  1. Find each value. Work out what each group is worth, for example \(14\) tens is \(140\).
  2. Add the values. Add the groups to get the number, then trade 10 for 1 to write it the standard way.
Example 1 — Expanded form
Write \(476\) in expanded form.
Solution
\(476\)\(=\)\(4\text{ hundreds},\ 7\text{ tens},\ 6\text{ ones}\)
\(476\)\(=\)\(400 + 70 + 6\)
476=400+70+6

Standard partitioning gives \(400 + 70 + 6\).

Example 2 — Expanded form with a zero
Write \(7091\) in expanded form. What is the value of the 9?
Solution
\(7091\)\(=\)\(7000 + 0 + 90 + 1\)
\(7091\)\(=\)\(7000 + 90 + 1\)
7091=7000+90+1

The 0 hundreds are left out, so \(7091 = 7000 + 90 + 1\). The 9 is in the tens place, so it is worth \(90\).

Example 3 — Non-standard partition
Fill in the blank: \(362 = 2\) hundreds, \(\underline{\phantom{00}}\) tens and \(2\) ones.
Solution
\(2\text{ hundreds}\)\(=\)\(200\)
\(362 - 200\)\(=\)\(160 + 2\)
\(160\)\(=\)\(16\text{ tens}\)
200+160+2=362

The blank is \(16\) tens, because \(200 + 160 + 2 = 362\).

Example 4 — Reading non-standard blocks
These base ten blocks show \(1\) hundred, \(14\) tens and \(5\) ones. What number do they make?
Base ten blocks showing 1 hundred, 14 tens and 5 ones One hundred-flat, fourteen ten-rods and five unit cubes: 100 plus 140 plus 5 makes 245. 1 hundred= 100 14 tens= 140 5 ones= 5
Solution
\(100 + 140 + 5\)\(=\)\(245\)
\(14\text{ tens}\)\(=\)\(1\text{ hundred},\ 4\text{ tens}\)
100+140+5=245

The blocks make \(245\). Renamed the standard way, that is \(2\) hundreds, \(4\) tens and \(5\) ones.

Example 5 — How many hundreds and tens?
Look at the number \(5300\).
(i) How many hundreds are there altogether?
(ii) How many tens are there altogether?
(iii) Write \(2480\) as hundreds and ones.
Solution
\(5300\)\(=\)\(53\text{ hundreds}\)
\(5300\)\(=\)\(530\text{ tens}\)
\(2480\)\(=\)\(2400 + 80\)
5300=53 hundreds =530 tens

(i) \(53\) hundreds.
(ii) \(530\) tens.
(iii) \(24\) hundreds and \(80\) ones.

Example 6 — Renaming a large number
Fill the gap: \(92\,000 = 80\,000 + \underline{\phantom{0000}}\)
Solution
\(92\,000 - 80\,000\)\(=\)\(12\,000\)
\(90\,000\)\(=\)\(80\,000 + 10\,000\)
92000=80000+12000

The gap is \(12\,000\). One ten thousand was renamed as 10 thousands.

Example 7 — Rename to subtract
Use renaming to work out \(500 - 30\).
Solution
\(500\)\(=\)\(4\text{ hundreds},\ 10\text{ tens}\)
\(10\text{ tens} - 3\text{ tens}\)\(=\)\(7\text{ tens}\)
\(500 - 30\)\(=\)\(470\)
500-30=470

Renaming \(500\) as \(4\) hundreds and \(10\) tens gives tens to subtract from, so \(500 - 30 = 470\).

Common pitfalls

Renaming keeps the number the same. Watch out for thinking a non-standard partition is bigger. \(2\) hundreds, \(12\) tens and \(4\) ones is still \(324\), not more.
Ten of one place makes one of the next. \(12\) tens is not \(12\) hundreds. \(12\) tens is \(1\) hundred and \(2\) tens, which is \(120\).
Keep counting past nine. In non-standard partitioning a place can hold \(10\) or more. \(15\) tens means \(150\), not \(105\).
"How many tens" is not "the tens digit". The tens digit of \(5300\) is 0, but there are \(530\) tens altogether in \(5300\).

Frequently asked questions

What does partition mean in maths?

To partition a number means to split it into parts by place value. For example, \(456\) partitions into \(400 + 50 + 6\).

What is non-standard partitioning?

Non-standard partitioning splits a number in a different way to the usual places. For example, \(456\) can be renamed as 3 hundreds, 15 tens and 6 ones, which is \(300 + 150 + 6\). It is still \(456\).

How do you rename a number in place value?

Trade one block of a place for ten of the next place down. One hundred becomes 10 tens, and one ten becomes 10 ones. The number stays the same, it is just grouped differently.

Why do we rename numbers before subtracting?

Renaming gives you enough in a place to subtract from. To work out \(500 - 30\), rename \(500\) as 4 hundreds and 10 tens, then take 3 tens from the 10 tens to get \(470\).

How many tens are in 5300?

There are 530 tens in \(5300\). Cover the ones digit and read what is left.

What is expanded form?

Expanded form writes a number as the value of each digit added together. For example, \(476 = 400 + 70 + 6\).