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Year 3 Maths Addition

Add two-digit numbers - with regrouping

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Theory

Adding two-digit numbers with regrouping is a Year 3 maths skill: add the ones first, and when they make ten or more, swap ten ones for one ten and carry it into the tens column. This page explains regrouping, the column method, the split strategy and the number line jump strategy, including totals past 100. Curriculum: VC2M3N04 / AC9M3N03.

To add two-digit numbers you add the ones first, then the tens. Sometimes the ones make ten or more. Ten ones is really one full ten, so you regroup: keep the extra ones and move the ten to the tens column. Moving that ten across is called carrying.

For \(46 + 29\), the ones make \(6 + 9 = 15\). That is 1 ten and 5 ones, so write the 5 and carry the 1 ten. Then the tens make \(4 + 2 + 1 = 7\), which gives \(75\).

There is more than one way to add. The column method lines the digits up and adds each column. The split strategy adds the tens and ones on their own, then joins them. The jump strategy starts at the first number on a number line and jumps the tens, then the ones.

Column addition of 46 plus 29 with a carried ten The sum 46 plus 29 set out in columns. The ones 6 plus 9 make 15, so 5 is written and 1 ten is carried, shown in red above the tens. The tens 4 plus 2 plus 1 make 7, giving the answer 75. tensones 1 46 +29 75
Column method: write the 5 ones and carry 1 ten (red), then add the tens.
Regrouping fifteen ones into one ten and five ones Fifteen unit squares in a row. A red dashed box rings the first ten, labelled one ten, and the last five are labelled five ones. This shows ten ones being regrouped as one ten. 1 ten5 ones 6 ones + 9 ones = 15 ones = 1 ten and 5 ones
Ten of the fifteen ones are regrouped into one ten, leaving five ones.

Regrouping rests on a few place value facts. Keep these in mind whenever a column reaches ten.

\[ 10 \text{ ones} = 1 \text{ ten} \]
10 ones =1 ten
\[ 10 \text{ tens} = 1 \text{ hundred} \]
10 tens =1 hundred
\[ 46 + 29 = (40 + 20) + (6 + 9) \]
46+29=(40+20)+(6+9)
Regrouping swaps ten ones for one ten. So \(6 + 9 = 15\) ones becomes 1 ten and 5 ones: you write the 5 and carry the ten. The same idea moves a ten into the hundreds when the tens reach ten, as in \(58 + 46 = 104\).

How to add two-digit numbers with regrouping

  1. Line up the columns. Write the numbers so ones sit under ones and tens under tens.
  2. Add the ones. If they make ten or more, write the ones digit and carry 1 ten above the tens column.
  3. Add the tens. Add the tens digits and the carried ten. Write the total to get your answer.
Does it regroup? Look at the ones digits before you start. If they add to \(10\) or more, a ten is carried. Missing numbers: for \(26 + \square = 71\), count on from \(26\) in easy jumps (\(+4\) to \(30\), \(+40\) to \(70\), \(+1\) to \(71\)) and add the jumps.
Example 1 β€” Two-digit plus one-digit
What is \(65 + 8\)?
Column addition of 65 plus 8 with a carried ten The sum 65 plus 8 in columns. The ones 5 plus 8 make 13, so 3 is written and 1 ten is carried, shown in red. The tens 6 plus 1 make 7, giving 73. tensones 1 65 +8 73
Solution
\(\text{ones: }5 + 8\)\(=\)\(13\)
\(\text{write }3,\text{ carry }1\text{ ten}\)
\(\text{tens: }6 + 1\)\(=\)\(7\)
65+8=73

So \(65 + 8 = 73\).

Example 2 β€” Split strategy
Work out \(57 + 26\) by adding the tens and the ones separately.
Solution
\(\text{tens: }50 + 20\)\(=\)\(70\)
\(\text{ones: }7 + 6\)\(=\)\(13\)
\(70 + 13\)\(=\)\(83\)
57+26=83

The ten inside \(13\) joins the tens, so \(57 + 26 = 83\).

Example 3 β€” Jump on a number line
Use the jump strategy for \(35 + 29\).
Number line jump strategy for 35 plus 29 A number line starting at 35. An arc jumps plus 20 to 55, then a second arc jumps plus 9 to 64, so 35 plus 29 is 64. +20+9 355564
Solution
\(35 + 20\)\(=\)\(55\)
\(55 + 9\)\(=\)\(64\)
35+29=64

Jump \(+20\), then \(+9\) crosses \(60\): \(35 + 29 = 64\).

Example 4 β€” Money past 100
A game costs \(\$58\) and a book costs \(\$46\). What is the total cost?
Solution
\(\text{ones: }8 + 6\)\(=\)\(14\ (\text{carry }1)\)
\(\text{tens: }5 + 4 + 1\)\(=\)\(10\)
\(58 + 46\)\(=\)\(104\)
58+46=104

The ten in the tens column moves into the hundreds. The total is \(\$104\).

Example 5 β€” Missing number
What number goes in the box? \(26 + \square = 71\)
Solution
\(26 + 4\)\(=\)\(30\)
\(30 + 40\)\(=\)\(70\)
\(70 + 1\)\(=\)\(71\)
\(4 + 40 + 1\)\(=\)\(45\)
26+45=71

The missing number is \(45\). Check: \(26 + 45 = 71\).

Example 6 β€” Three numbers and a target
A school canteen sold \(34\) apples, \(48\) bananas and \(26\) pears.
(i) How many pieces of fruit is that altogether?
(ii) How many more pieces would make \(150\)?
Solution
\(34 + 48\)\(=\)\(82\)
\(82 + 26\)\(=\)\(108\)
\(108 + 2\)\(=\)\(110\)
\(110 + 40\)\(=\)\(150\)
34+48+26=108

(i) \(108\) pieces of fruit.
(ii) Count on from \(108\) to \(150\): \(2 + 40 = 42\) more.

Common pitfalls

Write one digit, carry the rest. Watch out when the ones make ten or more. For \(8 + 7 = 15\), write 5 in the ones place and carry 1 ten, never write 15 in the ones column.
Do not forget the carried ten. Add it in with the tens. If you carried 1, the tens might be \(5 + 2 + 1\), not just \(5 + 2\).
Line the columns up. Keep ones under ones and tens under tens. If the digits drift out of line, the values get added in the wrong place.

Frequently asked questions

How do you add two-digit numbers with regrouping?

Add the ones first. If they make ten or more, write the ones digit and carry 1 ten into the tens column. Then add the tens, including the carried ten. For \(46 + 29\), the ones make \(15\), so write 5 and carry 1 ten, then \(4 + 2 + 1 = 7\), giving \(75\).

What does regrouping or carrying mean in addition?

Regrouping means swapping ten ones for one ten. When a column adds to ten or more, you keep the extra ones in that column and carry the ten into the next column to the left.

When do you need to regroup when adding?

You regroup whenever a column adds to ten or more. Check the ones first: if the ones digits add to \(10\) or more, you must carry a ten. For \(36 + 48\) the ones are \(6 + 8 = 14\), so you regroup.

What is the split strategy for addition?

The split strategy adds the tens and the ones separately, then joins them. For \(57 + 26\), add \(50 + 20 = 70\) and \(7 + 6 = 13\), then \(70 + 13 = 83\). The ten inside \(13\) joins the tens.

How do you add on a number line using the jump strategy?

Start at the first number, then jump the tens and the ones. For \(35 + 29\), start at \(35\), jump \(+20\) to reach \(55\), then jump \(+9\) to land on \(64\).

What is 46 + 29?

\(46 + 29 = 75\). The ones make \(6 + 9 = 15\), so write 5 and carry 1 ten. The tens make \(4 + 2 + 1 = 7\), so the answer is \(75\).